超快光学-第03章-脉冲(1).ppt_第1页
超快光学-第03章-脉冲(1).ppt_第2页
超快光学-第03章-脉冲(1).ppt_第3页
超快光学-第03章-脉冲(1).ppt_第4页
超快光学-第03章-脉冲(1).ppt_第5页
已阅读5页,还剩27页未读 继续免费阅读

下载本文档

版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领

文档简介

Ultrashort Laser Pulses I,Description of pulses Intensity and phase The instantaneous frequency and group delay Zeroth and first-order phase The linearly chirped Gaussian pulse,Prof. Rick Trebino Georgia Tech ,An ultrashort laser pulse has an intensity and phase vs. time.,Neglecting the spatial dependence for now, the pulse electric field is given by:,Intensity,Phase,Carrier frequency,A sharply peaked function for the intensity yields an ultrashort pulse. The phase tells us the color evolution of the pulse in time.,The real and complex pulse amplitudes,Removing the 1/2, the c.c., and the exponential factor with the carrier frequency yields the complex amplitude, E(t), of the pulse:,This removes the rapidly varying part of the pulse electric field and yields a complex quantity, which is actually easier to calculate with.,is often called the real amplitude, A(t), of the pulse.,Electric field E (t),Time fs,The Gaussian pulse,where tHW1/e is the field half-width-half-maximum, and tFWHM is the intensity full-width-half-maximum. The intensity is:,For almost all calculations, a good first approximation for any ultrashort pulse is the Gaussian pulse (with zero phase).,Intensity vs. amplitude,The intensity of a Gaussian pulse is 2 shorter than its real amplitude. This factor varies from pulse shape to pulse shape.,Its easy to go back and forth between the electric field and the intensity and phase: The intensity:,Calculating the intensity and the phase,f(t) = - ImlnE(t),The phase:,Equivalently,I(t) = |E(t)|2,Also, well stop writing “proportional to” in these expressions and take E, E, I, and S to be the field, intensity, and spectrum dimensionless shapes vs. time.,The Fourier Transform,To think about ultrashort laser pulses, the Fourier Transform is essential.,We always perform Fourier transforms on the real or complex pulse electric field, and not the intensity, unless otherwise specified.,The frequency-domain electric field,The frequency-domain equivalents of the intensity and phase are the spectrum and spectral phase. Fourier-transforming the pulse electric field:,yields:,The frequency-domain electric field has positive- and negative-frequency components.,Note that f and j are different!,Note that these two terms are not complex conjugates of each other because the FT integral is the same for each!,The complex frequency-domain pulse field,Since the negative-frequency component contains the same infor-mation as the positive-frequency component, we usually neglect it. We also center the pulse on its actual frequency, not zero. So the most commonly used complex frequency-domain pulse field is:,Thus, the frequency-domain electric field also has an intensity and phase. S is the spectrum, and j is the spectral phase.,The spectrum with and without the carrier frequency,Fourier transforming E (t) and E(t) yields different functions.,The spectrum and spectral phase,The spectrum and spectral phase are obtained from the frequency-domain field the same way the intensity and phase are from the time-domain electric field.,or,Intensity and phase of a Gaussian,The Gaussian is real, so its phase is zero.,Time domain: Frequency domain:,So the spectral phase is zero, too.,A Gaussian transforms to a Gaussian,Intensity and Phase,Spectrum and Spectral Phase,The spectral phase of a time-shifted pulse,Recall the Shift Theorem:,So a time-shift simply adds some linear spectral phase to the pulse!,Time-shifted Gaussian pulse (with a flat phase):,What is the spectral phase?,The spectral phase is the phase of each frequency in the wave-form.,0,All of these frequencies have zero phase. So this pulse has: j(w) = 0 Note that this wave-form sees constructive interference, and hence peaks, at t = 0. And it has cancellation everywhere else.,w1 w2 w3 w4 w5 w6,Now try a linear spectral phase: j(w) = aw.,By the Shift Theorem, a linear spectral phase is just a delay in time. And this is what occurs!,t,j(w1) = 0,j(w2) = 0.2 p,j(w3) = 0.4 p,j(w4) = 0.6 p,j(w5) = 0.8 p,j(w6) = p,To transform the spectrum, note that the energy is the same, whether we integrate the spectrum over frequency or wavelength:,Transforming between wavelength and frequency,The spectrum and spectral phase vs. frequency differ from the spectrum and spectral phase vs. wavelength.,Changing variables:,The spectral phase is easily transformed:,The spectrum and spectral phase vs. wavelength and frequency,Example: A Gaussian spectrum with a linear spectral phase vs. frequency,Note the different shapes of the spectrum and spectral phase when plotted vs. wavelength and frequency.,Bandwidth in various units,In frequency, by the Uncertainty Principle, a 1-ps pulse has bandwidth: dn = 1/2 THz,So d(1/l) = (0.5 1012 /s) / (3 1010 cm/s) or: d(1/l) = 17 cm-1,In wavelength:,Assuming an 800-nm wavelength:,using dn dt ,or: dl = 1 nm,In wave numbers (cm-1), we can write:,The temporal phase, (t), contains frequency-vs.-time information. The pulse instantaneous angular frequency, inst(t), is defined as:,The Instantaneous frequency,This is easy to see. At some time, t, consider the total phase of the wave. Call this quantity 0: Exactly one period, T, later, the total phase will (by definition) increase to 0 + 2p: where (t+T) is the slowly varying phase at the time, t+T. Subtracting these two equations:,Dividing by T and recognizing that 2/T is a frequency, call it inst(t): inst(t) = 2/T = 0 (t+T) (t) / T But T is small, so (t+T) (t) /T is the derivative, d /dt. So were done! Usually, however, well think in terms of the instantaneous frequency, inst(t), so well need to divide by 2: inst(t) = 0 (d/dt) / 2 While the instantaneous frequency isnt always a rigorous quantity, its fine for ultrashort pulses, which have broad bandwidths.,Instantaneous frequency (contd),Group delay,While the temporal phase contains frequency-vs.-time information, the spectral phase contains time-vs.-frequency information. So we can define the group delay vs. frequency, tgr(w), given by: tgr(w) = d / d A similar derivation to that for the instantaneous frequency can show that this definition is reasonable. Also, well typically use this result, which is a real time (the rads cancel out), and never d/d, which isnt. Always remember that tgr(w) is not the inverse of inst(t).,Phase wrapping and unwrapping,Technically, the phase ranges from p to p. But it often helps to “unwrap” it. This involves adding or subtracting 2p whenever theres a 2p phase jump. Example: a pulse with quadratic phase,Wrapped phase,The main reason for unwrapping the phase is aesthetics.,Note the scale!,Phase-blanking,When the intensity is zero, the phase is meaningless. When the intensity is nearly zero, the phase is nearly meaningless. Phase-blanking involves simply not plotting the phase when the intensity is close to zero.,The only problem with phase-blanking is that you have to decide the intensity level below which the phase is meaningless.,-f(wi),Re,Im,E(wi),S(wi),Phase Taylor Series expansions,We can write a Taylor series for the phase, f(t), about the time t = 0: where,where only the first few terms are typically required to describe well-behaved pulses. Of course, well consider badly behaved pulses, which have higher-order terms in (t). Expanding the phase in time is not common because its hard to measure the intensity vs. time, so wed have to expand it, too.,is related to the instantaneous frequency.,Frequency-domain phase expansion,Its more common to write a Taylor series for ():,As in the time domain, only the first few terms are typically required to describe well-behaved pulses. Of course, well consider badly behaved pulses, which have higher-order terms in ().,where,is the group delay!,is called the group-delay dispersion.,Zeroth-order phase: the absolute phase,The absolute phase is the same in both the time and frequency domains. An absolute phase of p/2 will turn a cosine carrier wave into a sine. Its usually irrelevant, unless the pulse is only a cycle or so long.,Notice that the two four-cycle pulses look alike, but the three single-cycle pulses are all quite different.,First-order phase in frequency: a shift in time,By the Fourier-transform Shift Theorem,Note that j1 does not affect the instantaneous frequency, but the group delay = j1.,First-order phase in time: a frequency shift,By the Inverse-Fourier-transform Shift Theorem,Time domain,Frequency domain,Note that 1 does not affect the group delay, but it does affect the instantaneous frequency = 1.,Second-order phase: the linearly chirped pulse,A pulse can have a frequen

温馨提示

  • 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
  • 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
  • 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
  • 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
  • 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
  • 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
  • 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

评论

0/150

提交评论