往复蹬踏式驱动装置设计与分析.pdf

Tz!9s冯永伟,李超(2,2210013)K1:对普通自行车驱动装置的受力情况进行了分析,指出了其不合理的地方,并提出了对人力驱动装置的改进措施b新型往复蹬踏驱动装置的设计,解决了普通自行车驱动装置对人力利用低下的问题,该装置可用作人们的代步及运货工具b1oM:驱动装置；往复；自行车ms|:U484DSM:BcI|:1007-9483(2002)06-0052-02DesignandAnalysisofDrivingDeviceofReciprocatingPedalingFENGYong-wei,LIChao(NanjingInstituteofTechnology,JiangsuNanjing,210013,China)154CLzZ_,P1a_-R,ziT,s5bC图1普通自行车驱动装置受力1,360bH,1B,LFFAcM,m1U,5B=S:W=2Q180b0bFAclsinAdA=4FAclT:lwcO2A；AwcO2AyCbwcMrsFlc:Flc=FAc#sinA180bS=,FAc(rsFlmc:Flmc=Q180b0bFAclsinAdAPl=2PFAc(rsFlmcFAc1qmc:mc=FlmcFAc100%=2P100%=6317%|FAc,Flc,Flmc3BUS,m2UbmVn,Y1z60%P,40%SbB4(rz1q,zb图2普通自行车力线图2Tz!91-车架；2-驱动轴；3,13-超越离合器；4,6-链条；5,8-脚蹬摇杆；7-从动链轮；9,11-脚蹬；10-滑轮；12-驱动链轮图3往复蹬踏式驱动装置结构示意图z!9L1,Bl:2002-08-19Te:(1964-),3,2Y,2=,V,1Z_!9b522002M11!9/316YV).LC.,m3Ub3,13%O1z2,z12z2,V7,(5,8B11,9,BO1,H6z12V7,H4sY(5,8,WYV3aO11013bzT:_/HH,WHzH_,Ozz_,zYVH6V_,V7P1_-bNH,WH4YVPQ_,PzW)s,PM_Mb/MK,P_MKH,MZ_,P_/P,NHP_,P1_-R,7Q_,zW)sbIn(5,8/,VO!BKv(m),K(,/HH4s87Vb3zs|zem4UdembL!zO1O2a,(O1A1lA,H(BO1lB,Vr1,zr2,r3,(O1A1,sLO1O2LCHbInH()V?,4q,5B图4新型驱动系统运动示意图|(sLH,HM,m4Ub51T:lB=a#cosH+r35(KH,HxLbLTAFAB_/T,C1VO1Mrbes,.,B1l(30b),B)HS_/b5FB=FA#lAlBFBT/,zO23zMdMd=FB#r35O1MrMr=Md#r1r2|3TiMr=FA#lAlB#r3#r1r2(1)9TV,VO1Mr+(1,7BbY1VMrcM,m1.1VMrc=FA#sinA#l#r1cr2c(2)YV1,zlAlB#r3#r1r2jvl,zVY1zKvzrTb,w(rsFl:Fl=FA#sinB(75bB105b)T,(rsFlm:Flm=Q105b75bFAlAsinBdBlAP/6=12sin15bPFAFA1qmm=FlmFA100%=12sin15bP100%=98186%|FA,Fl,Flm3BUS,m5UbmVn,Tz99%,Y1zM1,vv4qb图5新型驱动装置力线图4zsm1UY1z,.1:ic=r1cr2c(3)m4U,zH,(BQ,MY1zB,(BQ,BZ_VSB=2lBsin(2),VSB2Pr3,(/58:)53#!9#Tz!9s212几个关键模块的说明21211自动建模模块8m2U,144a110VU,b-+,vVU#iBV,|,M#H,O|XIHZ_(VA)T),VvvhlbVibUS,V|(m7U)b|11265256109,|xyz1x1y1z12x2y2z2,图7实体模型数据结构21212矩阵自生成模块9H,mw)KT,BM9,LC),Pb#vM,7i9VUS,1|,V913M,V7EmwN,y,7Opb21213矩阵运算模块USMM,9VELC,V4qA,MMAHE,USsLFhVb33IsqP4,5sVT；7BfKnm,TmTm,5v6H,VnPq?Pr4,Hvvh!91!9M1:bv,20011219+!9M1q:v,19871319m/CADM1:bv,20011419mM1W:W:v,20001(53:)9zO2V,NHVO1VSB2Pr3#r2r1b5z.1:i=1/2SB2Pr3#r2r1=Pr3r1SBr2|SB=2lBsin(2)Tiei=Pr3r12lBsin(2)r2(4)5.?1-s,Y1z(T(2)#.1(T(3),.(T(1)#.1(T(4)bCa|j,7FA=FAc,iPzY1zKvM,FA#lAlB#r3#r1r2=FAc#l#r1cr2c(r1cr2c)/(r3r1lBr2)=lAl1.1,ici=r1c/r2c(Pr3r1)/(2lBsin(/2)r2)=2lAsin(/2)P#lTTs,Ts0z；sVUYz,zPHvylyWC?90b120bS=S,2l,5NHz.1vY1,T91,qMf/,z11Bt,zv,V