《电工学-电子技术-下册》试题及解答.doc

91docWAPTXT *1 C A B C D *2 2 0V Ui=3V U0 ( D ) A B 0 C 5V D 3V *3( B )PN A1 B2 C3 D4 25 D A B C D *6 PN D A B C D 8 C A Q B C Au rir0 D Q Au riro *9 9 C1C2 u u0 ui ( B ) A B C 90 D9* 11 RL ( B ) A B C D 13 1. / 33( A ) A B C D 14PN A ) A B C D *16 16 D ) 16 * 19 19 ui C A. RL B. RC C. RB D. RB 19 *21 21 0V I A A.4mA B.0mA C.4A D.3mA *22 Q 22 Q B A. B. Q C. Q D. Q Q 21 19 22 24 24 0V I ( B ) A.1mA2 / 33 24 B.0mA C.1A D.3mA *25 Q 25 Q ( D ) A. RB B. Rc C. Rc D. RB 25 * 26 C A. B. C. D. 28 28 CE A A. B. C. D. D D u A 29. 29 D1 2 3 o A.0V B.6V C.18V D.+12V 28 29 * 30 B A. B. C. D. *31 31 VCC=12V RC=3k =50 UBE UCE=6V RB B A200k B300k C360k D600k 31 *1N *2 3 / 33* 3 PN _ P_ N *4 5 *6 7 7 RL (? ?) (? ?) 8 9 4V 1k 2V 7 1k 10 *11 *12 *13 PN _ _ _ _ *14 15 *16 0.20.30607V *17 NPN _ PNP_ 18PN 19_ *1 1 VCC=24V B=800k R RC=6k RL=3k UBE=0.7V =50rbe=1.2K 1(IBQICQUCEQ) 2 Au ri ro 1 (1) I BQ U CC 24 = = 30 A RB 800 103 I CQ = I BQ = 50 30 = 1.5mA1U CEQ = U CC ? I CQ RC = 24 ? 1.5 6 = 15V4 / 33(2) Au = ? RC / / RL 6 / /3 = ?50 = ?83.3 rbe 1.2 ri rbe = 1.2 K ? rO = RC = 6 K ?2 2 =40 C1 C2 2 12 = 240 10 IBQ + 0.73IBQ = 50 Arbe = 300 + (1 + ) = 300 +26mV IEQ26mV = 820? 2 IBQ 240 103 820 ri = RB / rbe = = 817? 240 103 + 820 ro = Rc = 4 k ? 4 103 8 103 ?40 ? ( RC / RL ) 4 103 + 8 103 = ?130 Au = = rbe 820*3 3 UBE=0.7VUCC=12VRC=2k RB=280k RL=6k 1C2 C Ui=0 1V U0=8V. 3 U CC = I BQ RB + U BE12 = I BQ 280 103 + 0.7I BQ = 40.4 A U o ? ( RC / RL ) = = ?80 Ui rbe 26mV ( RC / RL ) = 80 (300 + ) I BQ Au =32 103 6 103 26 10?3 = 80 (300 + ) 2 103 + 6 103 40.4 10?6 = 50#*4 4 UBE=0.7V RB1 8V RC=2k RE=1.5k UCE. 4 VB VE VB = U CC ? U RB1 = 12 ? 8 = 4V VE = VB ? U BE = 4 ? 0.7 = 3.3V4 5 / 33IE =U CEVE 3.3 = = 2.2mA I C RE 1.5 = U CC ? I E ( RC + RE )= 12 ? 2.2(2 + 1.5) = 4.3V *1 1 =50rbe=1k R2=3k R3=1k C1 C2 (1) (2) RL & A u = & U0 & Ui(3) RL=3k & A u =? 1 11& 2) Au =& & Uo ? I b R1 ? R2 = = & & r + (1 + ) I R r + (1 + ) R & U i I e be b 1 be 350 3 103 = = ?2.88 1 103 + (1 + 50) 1 103 & & ? I b ( R2 / RL ) ? ( R2 / RL ) & U 3) Au = o = = & & r + (1 + ) I R r + (1 + ) R & U Ii b be b 3 be3=50 1.5 10 = ?1.44 1 103 + (1 + 50) 1 10332 2 =50UBE=0.6V ui=3sint mV C1C2 (1) t2 ? & (2) A u ? (3) ? 2 12 6 / 33u BE = U BE + ube t2 3 ?3mV ube 0 t = ube = ?U bem = ?3mV 2 u BE = U BE + ube = 0.7 + (?0.003) = 0.697V 2 I B =U CC ? U BE 12 ? 0.7 = = 20 A RB 560 26 rbe = 300 + = 1600? = 1.6k ? 0.02 R RL 6 3 & Au = ? C = ?50 = ?62.5 rbe 1.6 ro = RC = 6k ? 3 ri rbe = 1.6k ?#*3 3 Ucc=12V RC=5k =100,rbe=2.5k UBE C1C2 1 RB 1M IBICUCE 2 RB 0 ? ? 3 RB ? 3 ? 4 S IBICUCE ? 5 S (RB=1M ) 6 ui S u0 ?U CC 12V = 3 = 0.012mA = 12 A RB 10 k ? I C = I B = 100 0.012 = 1.2mA U CE = U CC ? I C RC = 12 ? 1.2 5 = 6V3 1 RB = 1M ? I B = 2 RB = 0 U BE = 12V R 100k ? RB 3 RB I B = 0 , 4 S IBICUCE C2 5 S R 5 & Auo = ? C = ?100 = ?200 ri rbe = 2.5k ? ro = RC = 5k ? rbe 2.56 S 7 / 33R / RL R & U Au = O = ? L = ? C UI rbe rbe & & RL RC Au Auo ui u0 4 4 1 T 8 2 UCC=20V RC=0.5K Q IB=200A (1) RB UCE ( UBE=0.6V) (2) RB IC UCE 44 1 T 2 =I CQ I BQ=20 = 100 0.220 ? 0.6 = 97 k ? 0.2U CEQ = U CC ? I C RC = 20 ? 20 0.5 = 10V RB = U CC ? U BEQ I BQ =2 RB IC UCE U CE = U CC ? I C RC (U CE = 0, I C =U CC 20 = = 40V ) RC 0.5( I C = 0, U CE = U CC ) IC UCE 5 5 30UBE0.7VC1C2CE 1 ui=0.141sintV u0=? 2 RL1.2k u0=?8 / 333RL1.2k 60 u0=? 5 1 VB = 12 10 = 4V 20 + 10 VE = VB ? U BE = 4 ? 0.7 = 3.3V V 3.3 IE = E = = 1.65mA RE 2 26 rbe = 300 + (1 + ) IE 26 = 300 + (1 + 30) = 0.79k ? 1.65 & U R 2 & Auo = o = ? C = ?30 = ?76 & Ui rbe 0.79 & 0.141 = 0.1V Ui = 2 & & & = A U = ?76 0.1 = ?7.6V Uo uo i5 uo = 7.6 2 sin(t + )V 2 RL = RC RL = 2 1.2 = 0.75k ? & R 0.75 & U Au = o = ? L = ?30 = ?28.5 & U r 0.79i be& 0.141 = 0.1V Ui = 2 & & & = A U = ?28.5 0.1 = ?2.85V Uo u iuo = 2.85 2 sin(t + )V 26 26 3 rbe = 300 + (1 + ) = 300 + (1 + 60) = 1.26k ? IE 1.65 & R 0.75 & U Au = o = ? L = ?60 = ?35.7 & U r 1.26i be& 0.141 = 0.1V Ui = 2 & & & = A U = ?35.7 0.1 = ?3.57V Uo u iuo = 3.57 2 sin(t + )V9 / 336 6 1 2 UBE (1) Ic=2mA RB ? (2) ib=0.02sintmA iC,uCE u0 t 66 1 6 2 I C = 2mA IC 2 = = 50 I B = 0.04mA I B 0.04 U CE = U CC ? I C RC = 12 ? 2 3 = 6V U ? U BE U CC 12 RB = CC = = 300k ? IB IB 0.04 2 U CE = U CC ? I C RC MN iC,uCE= u0 t #*7 7 RB U1=9.4V =50 ES=10mV 1 rbe 2 A u 3 Ui 4 U010 / 337 9.4 = 0.047 mA 200 103 26mV rbe = 300 + = 0.853k ? 0.047 mA RL 50 2 & 2 Au = ? =? = ?117.2 rbe 0.853 3 ri = RB / rbe = 0.849k ? ri 0.849 U i = Es = 10 = 8.09mV ri + Rs 0.849 + 0.2 4 U o = AuU i = 117.2 8.09 = 948.1mV1 I B =7 1 1 V1 V2 UZ=5.3V 0.7V U0 ( D ) A1.4V B4.6V C5.3V D6V 2 2 V1 8VV2 6V U ( A ) A.6V B.8V C.10V D.2V123 ( C ) A. B. C. D. 4 Ui U0 ( D ) A Ui U0 B Ui U0 C Ui U0 D Ui U0 *5 5 I B ) 5 A1mA B0 C1mA D *6( B ) 11 / 33A B C D 7 7 UO U2 C ) AU0=0.45U2 BU0=1.1U2 CU0=0.9U2 DU0=1.2U2 *8( B ) A.0 B. C. D.0 *9 9 R1=1k RF=3k Ui=1V U1U2U3U4 3V ( B ) A.U1 B.U2 C.U3 D.U479* 10 A A. B. C. D. 11 500 12V B A.5.4V12V B.5.4V17V C.9V12V D.9V17V 12 12 u 10V u0 ( D ) A.12V B.9V C.4.5V D.0V 13 13 U0=3V P ( D )12 / 33 12 13 A. n B. C. D. m 14 14 12V 5mA 30mA U0= ( D ) A.0V B.30V C.10V D.12V 15 15 V1 U Z1 6V V2 U Z 2 3V U0 A A3V B6V C9V D15V 14 15 * 16 16 IL C 1 A. mA 3 1 B. mA 2 C.1mA D.2mA 16 17 U B A. 2 U B.0.9U C.2 U 2D.0.45U* 18 Ui0 B A. B. C. D. *19 19 B A0 B1 C2 D 20 20 D B 13 / 33A10VB14.14VC20VD28.28V 19 20 1 5A _2.5_ A 2 3 100 10V 0.05_A 4 9V 10V *5 Au0 _ _ _ *6 7 8 _ _ 9 W7815 _+15V_ 10 10 u0= 2 V #*1 1 C=1000F RL=100 UO=30V u2= 2 U2 sin314tV 1 U2 2 uO 1 1 10 1RLC = 100 1000 10?6 = 10?1 = 0.1 T 0.02 (3 5) = (3 5) = (0.03 0.05) 2 214 / 33 RL C (3 5)T U 2 U 2 = U O = 30V 22 uO #*2 2 RL=100 ? U2=12V U0 C 2 U o = 1.2U 2 = 1.2 12 = 14.4V T RLC (3 ? 5) 2 0.02 100 C (3 ? 5) 2 C 300 F ? 500 F2#*3 3 u0=ui1-ui2 R1 Rf1R2 Rf2 3 ui1 ?uo1 = R1 R f 1uo1 = ?Rf 1 R1 ui1 u01 ui 2 ?u0 + = R2 R2 R f 2uo = R f 1R f 2 R1 R2 ui1 ? Rf 2 R2 Rf 2 ui 21 R f 1 = R13 uo = ui1 ? ui 2 R f 2 = R2 R2 R f 1R f 2R1 R215 / 334 4 u0 ui1ui2 4 A1 uo1 = ?(ui 2 ) R11 R12 2 2 = ?( ui1 + ui 2 ) = ?(ui1 + ui 2 ) 2 2Rfui1 +Rf4A2 2 uo = ? uo1 = ui1 + ui 2 25 5 5 A1 uo1 = ?1. ui1dt CR1 A2 uo = ?(R1 R uo1 + 1 ui 2 ) 5 R2 R2 R 1 R 1 R = ?(? 1 ui1dt + R12 ui 2 ) = CR2 ui1dt ? R12 ui 2 R2 CR16 6 UOM=12V R1=10k ,R2=R3=RF=20k U1=3VU2=2V (1) S 1 UO=? (2) S 2 UO=? 6 R3 RF R ui1 + (1 + F ) ui 2 R1 R1 R2 + R3 20 20 20 uo = ? ui1 + (1 + ) ui 2 10 10 20 + 20 3 = ?2ui1 + ui 2 2 1 S 1 ui1 = U1 = 3V , ui 2 = U 2 = 2V 3 U O = uo = ?2 3 + 2 = ?3V 2 2 S 2 ui1 = 0, ui 2 = U 2 = 2V uo = ?616 / 33 U O = uo = ?2 0 +3 2 = 3V 27 7 S a I x 5mA u 0 5V S b I x 1mA u 0 5V R1 R2 7 I F = I x uo = ? I F RF = ? I x RF 1 S a RF = R1 I F = I x = 5mA uo = ? I x R1 = ?5 R1 = ?5V R1 = 1k ?72 S b RF = R1 + R2I F = I x = 1mA uO = ? I x ( R1 + R2 ) = ?( R1 + R2 ) = ?(1 + R2 ) = ?5V R2 = 4k ? *8 8 R110k R220k RF100k uI10.2VuI2 0.5V uO 8 uo = ?(RF R ui1 + F ui 2 )