2014年 数据结构和程序设计真题

.程序设计部分读程序，写结果 1.#includeUsing namespace stdMain()int i=2，j=4，m，n;m = +i + j+;/i=3 j=5 m=3+4=7n = (+i)+(+j)+m;/i=4,j=6,n=4+6+7=17cout ijmn;/46717return 0;2. #includeUsing namespace stdmain()int a=1,b=2,c=3,d=4,y=10;switch(y) case1:a+;break; default:d=1; case2:b+;break;/d=1,b=3 case4:c+;break;Cout abcdendl;/1331 Return 0;3. #includeUsing namespace std Main() Int i=0,sum=0; for(;)i+=2;if(i10) cout ”sum=”sum; break;if(i=8) continue; sum+=I;/0+2+4+6+10=22Return 0;4. #includeUsing namespace std;Int &f1（int &a）;Int f2 (int b );Main() Int x=10;Int y=f1(x);Int z=f2(x);cout xendl/20cout yendl;/20cout zendl;/40 return 0; Int &f1(int &a) a+=a; Int f2(int b) b+=b;#includeUsing namespace stdClass A private:int a;static int b;public： A（int i）a=i;b+=i; Void f();void A:f() cout ”a=”aendl; cout ”b=”bendl;Private A:b=0;Main()A obj1(10);/obj1.f(); A obj2(15);obj2.f();obj1.f();return 0;a=10b=10a=15b=25a=10b=256. #includeUsing namespace stdClass A Private: int a; public: A() cout”As default constactour called.n”; A(int i) a= i; cout”As constractour called.n”; Void print() couta,; A() cout”As destractor called.n” Int Geta return a; Class B Public:AB() cout”Bs default constactour called.n”; B(int i, int j, int k ) A(i),aa(j)cout ”Bs constractor called.n”； B() cout ”Bs destractor called.n” Void print(); Private: Int b; A aa;Void B:print() A:print(); Cout baa.Geta()end