二C语言练习题

1、考试题型：一、填空题二、选择题三、阅读程序，写出程序运行结果四、程序填空。五、程序编写题。1，#include <stdio.h>long int f(int k) long int h; if (k=1 | k=0) h=1; else h=k*f(k-1); return(h);void main(void) int n; long int t; printf("please input n:"); scanf(“%d”,&n); t=f(n); printf(“%d!=%dn”,n,t);2，#include <stdio.h>long

2、 int fib(int n) long int f; if (n=1 | n=2) f=1; else f=fib(n-1)+fib(n-2); return(f);void main(void) int i; for (i=1;i<=12;i+) printf(“%10d”,fib(i); if (i%4=0) printf(“n”); printf(“n”);3，#include <stdio.h>int fac(int n) int z; if (n>0) z=n*fac(n-2); else z=1; return z;void main(void) int

3、x=7,y; y=fac(x); printf(“y=%dn”,y);4，# include <stdio.h>void main(void) int n,s; int sum(int n); printf("please input n:"); scanf(“%d”,&n); s=sum(n); printf("sum=%dn",s);int sum(int n) int s;if (n=1) s=1; else s=sum(n-1)+n; return s;5，# include <stdio.h>void main(

4、void) float x; int n,z; float power(float,int); printf("please input x,n:”); scanf(“%f%d”,&x,&n); z=power(x,n); printf("power=%dn",z);float power(float x,int n) float p;if (n=1) p=x; else p=power(x,n-1)*x; return p;6，#include <stdio.h>void main(void) int i,j,m,n; i=8;j=1

5、0; m=+i;n=j+; printf(“%dt%dn”,i,j); printf(“%dt%dn”,m,n);7，#include <stdio.h>void main(void) int i=10; switch (i) case 9:i=i+1; case 10:i=i+1; case 11:i=i+1; default : i=i+1; printf(“i=%dn”,i);8#include <stdio.h>void main(void) int a=2,b=-1,c=2; if (a<b) if (b<0) c=0; else c=c+1; p

6、rintf(“c=%dn”,c);9，#include <stdio.h>void main(void) int i,k,a10,p3; k=5; for (i=0;i<10;i+) ai=i; for (i=0;i<3;i+) pi=ai*(i+1); for (i=0;i<3;i+) k=k+pi*2; printf(“k=%dn”,k); 10，#include <stdio.h>void main(void) int i=0,j=0,k=0,m; for (m=0;m<4;m+) switch (m) case 0:i=m+; case

7、1:j=m+; case 2:k=m+; case 3:m+; printf(“%dn%dt%dt%dn”,i,j,k,m);11，#include <stdio.h>void main(void) int a=1,b=2; void modify(int x,int y); printf("a=%dtb=%dn",a,b); modify(a,b); printf("a=%dtb=%dn",a,b);void modify(int x,int y) printf("x=%dty=%dn",x,y); x=x+3; y=y

8、+4; printf("x=%dty=%dn",x,y);12， #include<stdio.h> #include<string.h> void main(void) char a=”abcdef”; int n ; void fun(char s,int k); n=strlen(a); fun(a,n); puts(a); void fun(char s,int k) int x,y; char c; x=0; for(y=k-1;x<y;y-) c=sy;sy=sx;sx=c; x+; 13，# include <stdio.h

9、>void main( void) int a5=1,2,3,4,5; int *p=a; p+=2; printf(“%dt”,*p) ; p-; printf(“%dn”,*p) ; printf(“%dt”,*p-) ; printf(“%dn”,*p) ; 14，#include <stdio.h>void main(void) int sub(int x,int y); int a,b,m; printf("Input a,b:”); scanf(“%d%d”,&a,&b); m=sub(a,b); printf(“a-b=%dn”,m);

10、int sub(int x,int y) int z; z=x-y; return(z);16，#include <stdio.h>#include <string.h>#define N 30void main(void) char s1N,s2N,s3N,s3*N; printf("Input first String:n"); gets(s1); printf("Input second String:n"); gets(s2); printf("Input third String:n"); gets(

11、s3); strcpy(s,s1); strcat(s,s2); strcat(s,s3); printf("s=");puts(s);17，# include <stdio.h># include <math.h>main() int a,b,c,n,m; printf("please input number:n"); scanf("%d",&n); a=n/100; b=n%100/10; c=n%100%10; m=c*100+b*10+a; printf("m=%dn",m

12、);18，#include <stdio.h>void main() int i,a,b,c,j=1; for (i=1; i<=599 ;i+) if ( i%3=0 ) a=i/100; b=i%100/10; c=i%100%10; if ( a=5|b=5|c=5 ) printf("%5d",i); if ( j%5=0 ) printf( "n" ); j+; printf("n");printf("总计有%d个满足要求的数字：n", j-1);19，#include <stdi

13、o.h>int main() int m, n, m1,n1,a; printf("Input m, n:n"); scanf("%d%d", &m, &n); m1=m; n1=n; a=m1%n1; while(a!=0) m1=n1;n1=a; a=m1%n1; printf("最大公约数为： %d.n",n1 ); printf("最小公倍数为： %dn",m*n/n1);20，# include <stdio.h>void main() float x,y; printf

14、("please Input x：n"); scanf("%f",&x); if (x<2) y=-x+2.5; else if (x>=2&&x<4) y=2-1.5*(x-3)*(x-3); else y=x/2-1.5; printf("y=%.2fn",y); 21，#include <stdio.h>#include <iomanip.h>#define N 10void print(int a) int i;for(i=0;i<N;i+)printf(

15、“%5d”,ai);printf(“n”);void sort1( int a ) int i,j,temp;for(i=0;i<N-1;i+) for(j=0;j<=N-1-i;j+) if (aj>aj+1) temp=aj; aj=aj+1; aj+1=temp;void main(void)int i;int b10;printf("please input 10 numbet:n");for(i=0;i<10;i+)scanf(“%d”,&bi);sort1(b);printf("output 10 number:n&qu

16、ot;);print(b);22，#include <stdio.h>void main ( ) int x=2, 4, 6, 8, 10 ;int a, b, *p;p=&x0;a=*(p+2);b=*(p+4);printf("%d,%d,%dn", *p, a, b);23，#include <stdio.h>void main( ) int x=1,y=0,a=0,b=0;switch(x) case 1: switch(y) case 0: a+;break;case 1: b+;break;case 2: a+;b+;break;printf("a=%d,b=%dn",a,b);24，#include<stdio.h>int fun