【毕业学位论文】Sn1-xZnxNi 液固扩散偶的界面反应研究-材料学

分类号 . 密级 U D C 编号 中 南 大 学 士学位论文 论 文 题 目 i 液/固扩散偶的界面反应研究 学科、专业 材 料 学 研究生姓名 袁 媛 导师姓名及 专业技术职称 金 展 鹏 教 授 s he on i s I he i n/Ni 73K 73K 73K, 73K, is i)/ n/Ni 23K 38K is up by . is to in n/Ni n/Ni is by i (n , 22, 1 23K 4 is at 1i) 23K of by is by i (n 8, , 1 73K .5 1.5 s n on n n on n 73K of In 1(2(of in no by s V 摘 要 本次工作制备了一系列液 /固扩散偶， 用电子探针及扫描电镜对其作了背散射电子像形貌分析和成分分析。 i 液 /固扩散偶在 773K 退火生成 而其在 873K 时退火先后生成了 。 i 扩散偶分别在 623K 和 738K 退火一小时，均生成了包含 和 1的扩散层。 关于 i 和 i 扩散偶的界面反应，用 件，依据最大驱动力模型对其生成相顺序及形貌进行了预测。预测结果和实验结果吻合得很好，并对其形貌做了很好的解释。 制备了一系列 i（ x= 8（亚共晶） ， （共晶） ，22（过共晶） ， 31(过共晶） )液 /固扩散偶。当这些扩散偶在 623 均先生成了 相。随退火时间延长，在 体和 相之间生成了1相，并形成了富 液相和 1相的混合区域。 在 873K 退火其最终扩散通道分别为 i)/2/2+i ）； i)/2/1/1+ i ）； i)/1/2/1/1+ i） 。 对这些扩散偶的扩散层形貌和成分分析， 初步确定了 623K 和 873初步确定了相形成序列和扩 散通道。此次实验中发现了两个的新三元相 1和 2，其成分分别约为 用 件初步外推了 元体系相图。 外推结果很好的再现了 623K 时的实验结果，并很好的解释了其扩散层形貌。 s . . 1 . 1 b . 2 of . 4 he . 5 . 6 . 7 . 8 . 8 n i. 12 i n. 14 of on i n 18 . 20 ew . 23 . 23 . 24 . 25 . 26 of . 26 of . 29 . 29 of . 30 in . 34 . 36 . i . 38 . 38 . 38 . 40 s I n/Ni . 40 n/Ni . 42 i 23K. 43 i 73K. 49 . 57 . . 58 . 58 he . 59 . 59 of n/Ni 1 of n/Ni 4 he . 66 . 66 . 67 he . 67 . 69 . . 71 . 72 83s 1. is a a a 98K. In a in of or As a in of to of a in is to of in of 1, as As a It as a of by of to a is to of to is of on of i of to of be to a s 2 of C b n is 3a 0a a 56K, As of of Pb s 31. Pb of 50 mN/m 05K, 3470 mN/m 53K) 2. As an in at as .1 , Pb of or ) to or ) 3K. if it in a 26% in of to 3. Pb as a n u to by in b a it an is on of A of in A of to 5 m in in at 1. or b to 2. 2. MT is nPb to of of R, as by (R=(/g)1/2=2.2 is of MT .5 mm to a of in of to s 4 3. is is on of on of in is on of 4. of of in in at of of is is in of in In of It CB of to an to it is to of to or of of a of of a to as s 5of a is to of of A to be of of a of he a or a of an of it at a is of 56K. A of is a of a of is to or of is by or of a to as of a as or of s 6 of a 3. he n to on a of it to of n 04K. in in a is at a is 11K. as 11K, in a in in be a at be 11K to is of is 4. is to at in a as 0be in or of no is of to be in of at of