命令解释程序的实验报告

实验二、命令解解释程序的编写实验专业06级软件工程姓名黄雪虹学号060614143实验目的（1）掌握命令解释程序的原理；（2）掌握简单的DOS调用方法；（3）掌握C语言编程初步。实验内容和要求编写类似于DOS，UNIX的命令行解释程序（1）自行定义系统提示符（2）自定义命令集（8-10个）（3）用户输入HELP以查找命令的帮助（4）列出命令的功能，区分内部还是外部命令（5）用户输入QUIT退出（6）内部命令有dir,cd,md,rd,cls,date,time,ren,copy等。实验方法、步骤及结果测试源程序名：hxh.c可执行程序名：HXHC~1.exe原理分析及流程图采用数组的存储结构。主要算法：显示程序提示信息；While(1)｛显示提示符；接收键盘的字符串；判断是否quit程序退出指令，是则退出；判断是否内部命令，并给出相应的信息，否则给出错误信息；｝显示退出程序信息流程图：YY输入字符串数组a,b[10]=0?输出outofworkC1循环判断是否等于关键字输出外部命令输出内部命令结束NNY开始主要程序段及其解释：#include<stdio.h>#include<string.h>voidmain()/*主函数*/{char*b[11]={"dir","cd","md","rd","cls","date","time","ren","copy","help","quit"};/*指针数组存储关键字*/intpan(charch1[],char*j[11]);chara[10],*p=a;printf("Welcome.........\nPleasenteracommand!\nEnter'quit'toquit.\nForhelp,Enter'help'.\n");c1:printf("c:\>$");scanf("%s",a);pan(p,b);/*函数调用*/if(strcmp(a,b[10])!=0)/*比较输入的字符串是否quit结束命令*/gotoc1;elseprintf("outofwork!!\n");}intpan(charch1[],char*j[11])/*子函数*/{inti;for(i=0;i<11;i++)if(strcmp(ch1,j[i])==0)/*比较输入的字符串与数组的关键字是否相等*/ { switch(i) { case0:printf("commandnameisdir.\nIt'sfunctionislistfile.\nIt'saninternalcommand.\nVolumeindriveKgasnolabel.\nVolumeSerialNumberis60F0-6C24\n\n");break; case1:printf("commandnameiscd.\nIt'sfunctionischangedirectory.\nIt'saninternalcommand.\n");break; case2:printf("commandnameismd.\nIt'sfunctioniscreatanewdirectory.\nIt'saninternalcommand.\n");break; case3:printf("commandnameisrd.\nIt'sfunctionisdeleteadirectorywhichisempty.\nIt'saninternalcommand.\n");break; case4:printf("commandnameiscls.\nIt'sfunctioniscleanscreen\nIt'saninternalcommand.\n");break; case5:printf("commandnameisdate.\nIt'sfunctionisshowdate.\nIt'saninternalcommand.\n");break; case6:printf("commandnameistime.\nIt'sfunctionisshiotime.\nIt'saninternalcommand.\n");break; case7:printf("commandnameisren.\nIt'sfunctionisrenameafile.\nIt'saninternalcommand.\n");break; case8:printf("commandnameiscopy.\nIt'sfunctioniscopyfiles.\nIt'saninternalcommand.\n");break; case9:printf("dir\tcd\tmd\trd\tcls\ndate\ttime\tren\tcopy\nEnter\"quit\"toquitthisprogram!!\n");break; case10:printf("Thanksforusingit,bye!!\n");break; } return1;}printf("Nothisone!!\nNotainter