某办公楼电气部分设计计算书

某办公楼电气局部设计计算书1.电光源及灯具的选择一层商铺选用3×16W的嵌入式栅格荧光灯，室外走廊选用32W的嵌入式直置插拔式节能筒灯；办公室选用3×18W的嵌入式栅格荧光灯；走廊灯分别选用2×32W的嵌入式栅格荧光灯和3×18W的嵌入式栅格荧光灯；电梯前室、楼梯间选用3×16的吸顶灯，卫生间选用28W的防水防尘吸顶灯；地下室水池、走廊选用2×18W的三防荧光灯；阳台灯、三层平台分别选用22W的壁灯和250W的圆形投光灯。2.确定布置灯具方案和进行照度计算〔1〕选择照度。查照明标准值，办公楼办公室Eav300lx，卫生间、楼梯间、电梯前室、走廊Eav150lx，商铺Eav200lx，变配电间、设备间Eav200lx。〔2〕计算高度。办公楼层高为3.0m，工作面为0.75m，所以各计算高度为：办公室、商铺、卫生间、变配电间、设备间h=3.0-0.75=2.25m走廊、电梯前室h=3.0m〔3〕面积计算。地下室变配电间A=4.4×7.4=32.56㎡设备间A=4.4×8.2=36.08㎡走廊A=〔9.3+6.3+8.7〕×1.6=38.88㎡过道A=4.6×2.5=11.5㎡一层商铺A1=〔6.3+9.3〕×9.6×1/2=74.88㎡A2=6.8×9.6=65.28㎡A3=6.2×9.6=59.52㎡A4=7.4×6.3=46.62㎡雨棚A1=1.4×30.8=43.12㎡A2=1.4×14.1=19.74㎡电梯前室A=4.6×2.5=11.5㎡二层开放办公室A1=23×8.3=190.9㎡A2=〔5.3+9.3〕×14.7×1/2=107.31㎡A3=6.3×6.1=38.43㎡电梯前室A=3.7×6.6=24.42㎡三层开放办公室A1=6.3×20.8=131.04㎡A2=6.3×6.3=39.69㎡电梯前室A=4.7×3.7=17.39㎡四层办公室A1=6.3×6.1=38.43㎡A2=5.9×9.5=56.05㎡A3=5.9×6.2=36.58㎡A4=7.8×6.8=53.04㎡走廊A=1.7×20=34㎡电梯前室A=3.7×6.6=24.42㎡五至十三层办公室A1=6.3×6.1=38.43㎡A2=5.9×9.5=56.05㎡A3=5.9×6.2=36.58㎡A4=7.8×6.8=53.04㎡走廊A=1.7×20=34㎡电梯前室A=3.7×6.6=24.42㎡十四层办公室A1=6.3×6.1=38.43㎡A2=5.9×9.5=56.05㎡A3=5.9×6.2=36.58㎡A4=7.8×6.8=53.04㎡走廊A=1.7×20=34㎡电梯前室A=3.7×6.6=24.42㎡十五层办公室A1=6.3×6.1=38.43㎡A2=4.9×8.4=41.16㎡A3=4.9×6.2=30.38㎡A4=6.8×6.8=46.24㎡电梯前室A=4.7×3.7=17.39㎡〔4〕照度计算〔采用单位容量法〕。查表《建筑电气设计手册》，得各房间的照明单位安装功率Po为：地下室配电间Po=0.0560W/㎡设备间Po=0.0551W/㎡走廊Po=0.0897W/㎡过道Po=0.0897W/㎡一层商铺Po1=0.0435W/㎡Po2=0.0483W/㎡Po3=0.0492W/㎡Po4=0.0508W/㎡雨棚Po1=0.0897W/㎡Po2=0.0897W/㎡电梯前室Po=0.0897W/㎡二层开放办公室Po1=0.0432W/㎡Po2=0.0416W/㎡Po3=0.0541W/㎡电梯前室Po=0.0735W/㎡三层开放办公室Po1=0.0458W/㎡Po2=0.0537W/㎡电梯前室Po=0.0810W/㎡四层办公室Po1=0.0541W/㎡Po2=0.0503W/㎡Po3=0.0548W/㎡Po4=0.0504W/㎡走廊Po=0.0897W/㎡电梯前室Po=0.0735W/㎡五至十三层办公室Po1=0.0541W/㎡Po2=0.0503W/㎡Po3=0.0548W/㎡Po4=0.0504W/㎡走廊Po=0.0897W/㎡电梯前室Po=0.0735W/㎡十四层办公室Po1=0.0541W/㎡Po2=0.0503W/㎡Po3=0.0548W/㎡Po4=0.0504W/㎡走廊Po=0.0897W/㎡电梯前室Po=0.0735W/㎡十五层办公室Po1=0.0541W/㎡Po2=0.0542W/㎡Po3=0.0578W/㎡Po4=0.0518W/㎡电梯前室Po=0.0810W/㎡〔5〕计算总安装容量。〔P=Po×A×E〕地下室变配电间P=0.0560×32.56×200=364.98W设备间P=0.0551×36.08×200=397.46W走廊P=0.0897×38.88×150=523.13W过道P=0.0897×11.5×150=154.8W一层商铺P1=0.0435×74.88×200=651.46WP2=0.0483×65.28×200=630.60WP3=0.0492×59.52×200=585.68WP4=0.0508×46.62×200=473.66W走廊P1=0.0897×43.12×150=580.18WP2=0.0897×19.74×150=265.60W电梯前室P=0.0897×11.5×150=154.80W二层开放办公室P1=0.0432×190.9×300=2476.80WP2=0.0416×107.31×300=1339.80WP3=0.0541×38.43×300=624.20W电梯前室P=0.0735×24.42×150=269.23W三层开放办公室P1=0.0458×131.04×300=1799.15WP2=0.0537×39.69×300=639.39W电梯前室P=0.0810×17.39×150=211.29W四层办公室P1=0.0541×38.43×300=624.20WP2=0.0503×56.05×300=847.40WP3=0.0548×36.58×300=601.60WP4=0.0504×53.04×300=802.60W走廊P=0.0874×34×150=457.50W电梯前室P=0.0735×24.42×150=269.23W五至十三层办公室P1=0.0541×38.43×300=624.20WP2=0.0503×56.05×300=847.40WP3=0.0548×36.58×300=601.60WP4=0.0504×53.04×300=802.60W走廊P=0.0874×34×150=457.50W电梯前室P=0.0735×24.42×150=269.23W十四层办公室P1=0.0541×38.43×300=624.20WP2=0.0503×56.05×300=847.40WP3=0.0548×36.58×300=601.60WP4=0.0504×53.04×300=802.60W走廊P=0.0874×34×150=457.50W电梯前室P=0.0735×24.42×150=269.23W十五层办公室P1=0.0541×38.43×300=624.20WP2=0.0542×41.16×300=668.97WP3=0.0578×30.38×300=526.80WP4=0.0518×46.24×300=718.00W电梯前室P=0.0810×17.39×150=211.29W〔6〕计算灯具数量。N=P/p地下室变配电间N=8套设备间N=9套走廊N=9套过道间、楼梯间N=8套水池N1=6套N2=9套一层店铺N1=14套〔3×16w〕1套〔28w〕N2=11套〔〔3×16w〕1套〔28w〕3套〔3×18w〕N3=12套〔〔3×16w〕1套〔28w〕3套〔3×18w〕N4=11套〔3×16w〕配电间N=1套〔3×16w〕仓库N=2套〔3×16w〕楼梯间、电梯前室N=7套〔3×16w〕二层开放办公室N1=34套〔3×18w〕N2=26套〔3×18w〕N3=12套〔3×18w〕卫生间N=5套〔28w〕楼梯间、电梯前室N=10套〔3×16w〕8套〔3×18w〕配电间N=1套〔3×16w〕三层开放办公室N1=28套〔3×18w〕N2=12套〔3×18w〕卫生间N=5套〔28w〕楼梯间、电梯前室N=8套〔3×16w〕7套〔3×18w〕配电间N=1套〔3×16w〕阳台、平台N=13套〔22w〕4套〔250w〕四层办公室N1=12套〔3×18w〕N2=16套〔3×18w〕N3=12套〔3×18w〕N4=12套〔3×18w〕卫生间N=5套〔28w〕楼梯间、电梯前室N=10套〔3×16w〕7套〔2×32w〕配电间N=1套〔3×16w〕五至十三层办公室N1=12套〔3×18w〕N2=16套〔3×18w〕N3=12套〔3×18w〕N4=12套〔3×18w〕卫生间N=5套〔28w〕楼梯间、电梯前室N=10套〔3×16w〕7套〔2×32w〕配电间N=1套〔3×16w〕十四层办公室N1=12套〔3×18w〕N2=16套〔3×18w〕N3=12套〔3×18w〕N4=12套〔3×18w〕卫生间N=5套〔28w〕楼梯间、电梯前室N=10套〔3×16w〕7套〔2×32w〕配电间N=1套〔3×16w〕十五层办公室N1=12套〔3×18w〕N2=12套〔3×18w〕N3=10套〔3×18w〕N4=9套〔3×18w〕卫生间N=5套〔28w〕楼梯间、电梯前室N=8套〔3×16w〕7套〔2×32w〕配电间N=1套〔3×16w〕阳台N=14套〔22w〕3.确定照明供电方式和照明路线布置方式。采用380/221V三相四线制供电。电源有地下室2轴线地下电缆穿钢管引至地下室变配电间，再由变配电间引至配电间，再分别穿钢管引至各个楼层配电间的配电箱。供电方式见竖向干线系统图、配电箱系统图，由地下室变配电间的配线柜引出十六条单相支路到各楼层配电箱，再由层配电箱引至各个照明和插座等用电。4.计算照明负荷荧光灯的损耗系数α=0.2；指示灯的损耗系数α=0；需要系数Kd=0.8；按将功率因数提高到cosψ=0.9计算。地下室照明设备容量WL1支路：荧光灯8只×〔3×16〕W。那么：灯具设备容量Pe1=∑Pa〔1+α〕=8×〔3×16〕×〔1+0.2〕=460.8W计算负荷P30.1=KdPe1=0.8×460.8=368.64W计算电流I30.1=P30.1/〔Upcosψ〕=368.64/〔220×0.9〕=2.1AWL2支路：荧光灯9只×〔3×16〕W。那么：Pe2=∑Pa〔1+α〕=9×〔3×16〕×〔1+0.2〕=518.4WP30.2=KdPe2=0.8×518.4=414.72WI30.2=P30.2/〔Upcosψ〕=414.72/〔220×0.9〕=2.1AWL3支路：三防荧光灯6只×〔2×18〕W。那么：Pe3=∑Pa〔1+α〕=6×〔2×18〕×〔1+0.2〕=259.2WP30.3=KdPe3=0.8×259.2=207.36WI30.3=P30.3/〔Upcosψ〕=207.36/〔220×0.9〕=1.1AWL4支路：三防荧光灯9只×〔2×18〕W。那么：Pe4=∑Pa〔1+α〕=9×〔2×18〕×〔1+0.2〕=388.8WP30.4=KdPe4=0.8×388.8=311.04WI30.4=P30.4/〔Upcosψ〕=311.04/〔220×0.9〕=1.6AWL5支路：三防荧光灯9只×〔2×18〕W。那么：Pe5=∑Pa〔1+α〕=9×〔2×18〕×〔1+0.2〕=388.8WP30.5=KdPe5=0.8×388.8=311.04WI30.5=P30.5/〔Upcosψ〕=311.04/〔220×0.9〕=1.6AWL6支路：指示灯6只×〔2×8〕W；应急灯11只×〔2×3〕W。那么：Pe6=∑Pa〔1+α〕=6×〔2×8〕+11×〔2×3〕=162WP30.6=KdPe6=0.8×162=129.6WI30.6=P30.6/〔Upcosψ〕=129.6/〔220×0.9〕=0.7AWL7支路：荧光灯8只×〔3×16〕W。那么：Pe7=∑Pa〔1+α〕=8×〔3×16〕×〔1+0.2〕=460.8WP30.7=KdPe7=0.8×460.8=368.64WI30.7=P30.7/〔Upcosψ〕=368.64/〔220×0.9〕=1.9AWL8支路：插座5只，每只按1000W。那么：Pe8=∑Pa〔1+α〕=5×1000=5000WP30.8=KdPe8=0.8×5000=4000WI30.8=P30.8/〔Upcosψ〕=4000/〔220×0.9〕=20.2AWL9支路：荧光灯1只×〔3×16〕W。那么：Pe9=∑Pa〔1+α〕=1×〔3×16〕×〔1+0.2〕=57.6WP30.9=KdPe9=0.8×57.6=46.08WI30.9=P30.9/〔Upcosψ〕=46.08/〔220×0.9〕=0.3AL1-1：Pe=∑〔Pe1+Pe2+Pe3+……+Pe9〕=460.8+518.4+259.2+388.8+388.8+162+460.8+5000+57.6=7696.4WP30=KdPe=0.8×7696.4=6157.12WI30=P30/〔Upcosψ〕=6157.12/〔220×0.9〕=31.1A一层照明设备容量WL1支路：荧光灯14只×〔3×16〕W；防水防尘吸顶灯1只×28W；插座5只，每只按100W。那么：Pe1=∑Pa〔1+α〕=[14×〔3×16〕+1×28]×〔1+0.2〕+5×100=1340WP30.1=KdPe1=0.8×1340=1072WI30.1=P30.1/〔Upcosψ〕=1072/〔220×0.9〕=5.4AWL2支路：荧光灯11只×〔3×16〕W，3只×〔3×18〕W；防水防尘吸顶灯1只×28W；插座5只，每只按100W。那么：Pe2=∑Pa〔1+α〕=[11×〔3×16〕+3×〔3×18〕+1×28]×〔1+0.2〕+5×100=1361.6WP30.2=KdPe2=0.8×1361.6=1089.28WI30.2=P30.2/〔Upcosψ〕=11089.28/〔220×0.9〕=5.5AWL3支路：荧光灯12只×〔3×16〕W，3只×〔3×18〕W；防水防尘吸顶灯1只×28W；插座5只，每只按100W。那么：Pe3=∑Pa〔1+α〕=[12×〔3×16〕+3×〔3×18〕+1×28]×〔1+0.2〕+5×100=1419.2WP30.3=KdPe3=0.8×1419.2=1135.36WI30.3=P30.3/〔Upcosψ〕=11089.28/〔220×0.9〕=5.8AWL4支路：荧光灯11只×〔3×16〕W；插座4只，每只按100W。那么：Pe4=∑Pa〔1+α〕=11×〔3×16〕×〔1+0.2〕+4×100=1033.6WP30.4=KdPe4=0.8×1033.6=826.88WI30.4=P30.4/〔Upcosψ〕=826.88/〔220×0.9〕=4.2AWL5支路：嵌入式直插拔式节能筒灯13只×32W。那么：Pe5=∑Pa〔1+α〕=13×32×〔1+0.2〕=499.2WP30.5=KdPe5=0.8×499.2=399.36WI30.5=P30.5/〔Upcosψ〕=399.36/〔220×0.9〕=2.1AWL6支路：荧光灯7只×〔3×16〕W。那么：Pe6=∑Pa〔1+α〕=7×32×〔1+0.2〕=403.2WP30.6=KdPe6=0.8×403.2=322.56WI30.6=P30.6/〔Upcosψ〕=322.56/〔220×0.9〕=1.7AWL7支路：指示灯2只×〔2×8〕W；应急灯4只×〔2×3〕W。那么：Pe7=∑Pa〔1+α〕=2×(2×8)+4×〔2×3〕=56WP30.7=KdPe7=0.8×56=44.8WI30.7=P30.7/〔Upcosψ〕=44.8/〔220×0.9〕=0.3AWL8支路：荧光灯2只×〔3×16〕插座2只，每只按100W。那么：Pe8=∑Pa〔1+α〕=2×〔3×16〕×〔1+0.2〕+2×100=315.2WP30.8=KdPe8=0.8×315.2=252.16WI30.8=P30.8/〔Upcosψ〕=252.16/〔220×0.9〕=1.3AWL9支路：荧光灯1只×〔3×16〕W。那么：Pe9=∑Pa〔1+α〕=1×〔3×16〕×〔1+0.2〕=57.6WP30.9=KdPe9=0.8×57.6=46.08WI30.9=P30.9/〔Upcosψ〕=46.08/〔220×0.9〕=0.3AL1-2：Pe=∑〔Pe1+Pe2+Pe3+……+Pe9〕=1340+1361.6+1419.2+1033.6+499.2+403.2+56+315.2+57.6=6485.6WP30=KdPe=0.8×6485.6=5188.48WI30=P30/〔Upcosψ〕=6485.6/〔220×0.9〕=26.2A二层照明设备容量WL1支路：荧光灯34只×〔3×18〕W。那么：Pe1=∑Pa〔1+α〕=34×〔3×18〕×〔1+0.2〕=2203.2WP30.1=KdPe1=0.8×2203.2=1762.56WI30.1=P30.1/〔Upcosψ〕=1762.56/〔220×0.9〕=8.9AWL2支路：荧光灯26只×〔3×18〕W。那么：Pe2=∑Pa〔1+α〕=26×〔3×18〕×〔1+0.2〕=1684.8WP30.2=KdPe2=0.8×1684.8=1347.84WI30.2=P30.2/〔Upcosψ〕=1347.84/〔220×0.9〕=6.8AWL3支路：荧光灯12只×〔3×18〕W。那么：Pe3=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.3=KdPe3=0.8×777.6=622.08WI30.3=P30.3/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL4支路：荧光灯8只×〔3×18〕W，10只×〔3×16〕W。那么：Pe4=∑Pa〔1+α〕=[8×〔3×18〕+10×〔3×16〕W]×〔1+0.2〕=1094.4WP30.4=KdPe4=0.8×1094.4=875.52WI30.4=P30.4/〔Upcosψ〕=875.52/〔220×0.9〕=4.5AWL5支路：防水防尘吸顶灯5只×28W。那么：Pe5=∑Pa〔1+α〕=5×28×〔1+0.2〕=168WP30.5=KdPe5=0.8×168=134.4WI30.5=P30.5/〔Upcosψ〕=134.4/〔220×0.9〕=0.7AWL6支路：指示灯5只×〔2×8〕W；应急灯6只×〔2×3〕W，4只×36W。那么：Pe6=∑Pa〔1+α〕=5×〔2×8〕+6×〔2×3〕+4×36=260WP30.6=KdPe6=0.8×260=208WI30.6=P30.6/〔Upcosψ〕=208/〔220×0.9〕=1.1AWL7支路：插座13只，每只按500W。那么：Pe7=∑Pa〔1+α〕=13×500=6500WP30.7=KdPe7=0.8×6500=5200WI30.7=P30.7/〔Upcosψ〕=5200/〔220×0.9〕=26.3AWL8支路：插座5只，每只按500W。那么：Pe8=∑Pa〔1+α〕=5×500=2500WP30.8=KdPe8=0.8×2500=2000WI30.8=P30.8/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL9支路：插座9只，每只按500W。那么：Pe9=∑Pa〔1+α〕=9×500=4500WP30.9=KdPe9=0.8×4500=3600WI30.9=P30.9/〔Upcosψ〕=3600/〔220×0.9〕=18.2AWL10支路：荧光灯1只×〔3×16〕W。那么：Pe10=∑Pa〔1+α〕=1×〔3×16〕×〔1+0.2〕=57.6WP30.10=KdPe10=0.8×57.6=46.08WI30.10=P30.10/〔Upcosψ〕=46.08/〔220×0.9〕=0.3AL2-1：Pe=∑〔Pe1+Pe2+Pe3+……+Pe10〕=2203.2+1684.8+777.6+1094.4+168+260+6500+2500+4500+57.6=19745.6WP30=KdPe=0.8×19745.6=15796.48WI30=P30/〔Upcosψ〕=15796.48/〔220×0.9〕=79.8A三层照明设备容量WL1支路：荧光灯28只×〔3×18〕W。那么：Pe1=∑Pa〔1+α〕=28×〔3×18〕×〔1+0.2〕=1814.4WP30.1=KdPe1=0.8×1814.4=1451.52WI30.1=P30.1/〔Upcosψ〕=1451.52/〔220×0.9〕=7.4AWL2支路：荧光灯12只×〔3×18〕W。那么：Pe2=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.2=KdPe2=0.8×777.6=622.08WI30.2=P30.2/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL3支路：荧光灯7只×〔3×18〕W,8只×〔3×16〕W。那么：Pe3=∑Pa〔1+α〕=[7×〔3×18〕+8×〔3×16〕]×〔1+0.2〕=914.4WP30.3=KdPe3=0.8×914.4=731.52WI30.3=P30.3/〔Upcosψ〕=731.52/〔220×0.9〕=3.7AWL4支路：防水防尘吸顶灯5只×28W。那么：Pe4=∑Pa〔1+α〕=5×28×〔1+0.2〕=168WP30.4=KdPe4=0.8×168=134.4WI30.4=P30.4/〔Upcosψ〕=134.4/〔220×0.9〕=0.7AWL5支路：指示灯5只×〔2×8〕W；应急灯6只×〔2×3〕W，4只×36W。那么：Pe5=∑Pa〔1+α〕=5×〔2×8〕+6×〔2×3〕+4×36=260WP30.5=KdPe5=0.8×260=208WI30.5=P30.5/〔Upcosψ〕=208/〔220×0.9〕=1.1AWL6支路：壁灯13只×22W；投光灯4只×250W。那么：Pe6=∑Pa〔1+α〕=〔13×22+4×250〕×〔1+0.2〕=1543.2WP30.6=KdPe6=0.8×1543.2=1234.56WI30.6=P30.6/〔Upcosψ〕=1234.56/〔220×0.9〕=6.3AWL7支路：插座11只，每只按500W。那么：Pe7=∑Pa〔1+α〕=11×500=5500WP30.7=KdPe7=0.8×5500=4400WI30.7=P30.7/〔Upcosψ〕=4400/〔220×0.9〕=22.3AWL8支路：插座5只，每只按500W。那么：Pe8=∑Pa〔1+α〕=5×500=2500WP30.8=KdPe8=0.8×2500=2000WI30.8=P30.8/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL9支路：荧光灯1只×〔3×16〕W。那么：Pe9=∑Pa〔1+α〕=1×〔3×16〕×〔1+0.2〕=57.6WP30.9=KdPe9=0.8×57.6=46.08WI30.9=P30.9/〔Upcosψ〕=46.08/〔220×0.9〕=0.3AL1-2：Pe=∑〔Pe1+Pe2+Pe3+……+Pe9〕=1814.4+777.6+914.4+168+260+1543.2+5500+2500+57.6=13535.2WP30=KdPe=0.8×13535.2=10828.16WI30=P30/〔Upcosψ〕=10828.16/〔220×0.9〕=54.7A四层照明设备容量WL1支路：荧光灯16只×〔3×18〕W。那么：Pe1=∑Pa〔1+α〕=16×〔3×18〕×〔1+0.2〕=1036.8WP30.1=KdPe1=0.8×1036.8=829.44WI30.1=P30.1/〔Upcosψ〕=829.44/〔220×0.9〕=4.2AWL2支路：荧光灯12只×〔3×18〕W。那么：Pe2=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.2=KdPe2=0.8×777.6=622.08WI30.2=P30.2/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL3支路：荧光灯12只×〔3×18〕W。那么：Pe3=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.3=KdPe3=0.8×777.6=622.08WI30.3=P30.3/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL4支路：荧光灯12只×〔3×18〕W。那么：Pe4=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.4=KdPe4=0.8×777.6=622.08WI30.4=P30.4/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL5支路：荧光灯7只×〔2×32〕W,10只×〔3×16〕W。那么：Pe5=∑Pa〔1+α〕=[7×〔2×32〕+10×〔3×16〕]×〔1+0.2〕=1113.6WP30.5=KdPe5=0.8×1113.6=890.88WI30.5=P30.5/〔Upcosψ〕=890.88/〔220×0.9〕=4.5AWL6支路：防水防尘吸顶灯5只×28W。那么：Pe6=∑Pa〔1+α〕=5×28×〔1+0.2〕=168WP30.6=KdPe6=0.8×168=134.4WI30.6=P30.6/〔Upcosψ〕=134.4/〔220×0.9〕=0.7AWL7支路：指示灯7只×〔2×8〕W；应急灯6只×〔2×3〕W，3只×36W。那么：Pe7=∑Pa〔1+α〕=7×〔2×8〕+6×〔2×3〕+3×36=2656WP30.=KdPe7=0.8×256=204.8WI30.7=P30.7/〔Upcosψ〕=204.8/〔220×0.9〕=1.1AWL8支路：插座5只，每只按500W。那么：Pe8=∑Pa〔1+α〕=5×500=2500WP30.8=KdPe8=0.8×2500=2000WI30.8=P30.8/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL9支路：插座4只，每只按500W。那么：Pe9=∑Pa〔1+α〕=4×1500=2000WP30.9=KdPe9=0.8×2000=1600WI30.9=P30.9/〔Upcosψ〕=1600/〔220×0.9〕=8.1AWL10支路：插座5只，每只按500W。那么：Pe10=∑Pa〔1+α〕=5×500=2500WP30.10=KdPe10=0.8×2500=2000WI30.10=P30.10/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL11支路：插座4只，每只按500W。那么：Pe11=∑Pa〔1+α〕=4×500=2000WP30.11=KdPe11=0.8×2000=1600WI30.11=P30.11/〔Upcosψ〕=1600/〔220×0.9〕=8.1AWL12支路：荧光灯1只×〔3×16〕W。那么：Pe12=∑Pa〔1+α〕=1×〔3×16〕×〔1+0.2〕=57.6WP30.12=KdPe12=0.8×57.6=46.08WI30.12=P30.12/〔Upcosψ〕=46.08/〔220×0.9〕=0.3AL2-2：Pe=∑〔Pe1+Pe2+Pe3+……+Pe12〕=1036.8+777.6+777.6+777.6+1113.6+168+256+2500+2000+2500+2000+57.6=13964.8WP30=KdPe=0.8×13964.8=11171.84WI30=P30/〔Upcosψ〕=11171.84/〔220×0.9〕=56.5A五至十三层照明设备容量WL1支路：荧光灯16只×〔3×18〕W。那么：Pe1=∑Pa〔1+α〕=16×〔3×18〕×〔1+0.2〕=1036.8WP30.1=KdPe1=0.8×1036.8=829.44WI30.1=P30.1/〔Upcosψ〕=829.44/〔220×0.9〕=4.2AWL2支路：荧光灯12只×〔3×18〕W。那么：Pe2=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.2=KdPe2=0.8×777.6=622.08WI30.2=P30.2/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL3支路：荧光灯12只×〔3×18〕W。那么：Pe3=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.3=KdPe3=0.8×777.6=622.08WI30.3=P30.3/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL4支路：荧光灯12只×〔3×18〕W。那么：Pe4=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.4=KdPe4=0.8×777.6=622.08WI30.4=P30.4/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL5支路：荧光灯7只×〔2×32〕W,10只×〔3×16〕W。那么：Pe5=∑Pa〔1+α〕=[7×〔2×32〕+10×〔3×16〕]×〔1+0.2〕=1113.6WP30.5=KdPe5=0.8×1113.6=890.88WI30.5=P30.5/〔Upcosψ〕=890.88/〔220×0.9〕=4.5AWL6支路：防水防尘吸顶灯5只×28W。那么：Pe6=∑Pa〔1+α〕=5×28×〔1+0.2〕=168WP30.6=KdPe6=0.8×168=134.4WI30.6=P30.6/〔Upcosψ〕=134.4/〔220×0.9〕=0.7AWL7支路：指示灯7只×〔2×8〕W；应急灯6只×〔2×3〕W，3只×36W。那么：Pe7=∑Pa〔1+α〕=7×〔2×8〕+6×〔2×3〕+3×36=2656WP30.=KdPe7=0.8×256=204.8WI30.7=P30.7/〔Upcosψ〕=204.8/〔220×0.9〕=1.1AWL8支路：插座5只，每只按500W。那么：Pe8=∑Pa〔1+α〕=5×500=2500WP30.8=KdPe8=0.8×2500=2000WI30.8=P30.8/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL9支路：插座4只，每只按500W。那么：Pe9=∑Pa〔1+α〕=4×1500=2000WP30.9=KdPe9=0.8×2000=1600WI30.9=P30.9/〔Upcosψ〕=1600/〔220×0.9〕=8.1AWL10支路：插座5只，每只按500W。那么：Pe10=∑Pa〔1+α〕=5×500=2500WP30.10=KdPe10=0.8×2500=2000WI30.10=P30.10/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL11支路：插座4只，每只按500W。那么：Pe11=∑Pa〔1+α〕=4×500=2000WP30.11=KdPe11=0.8×2000=1600WI30.11=P30.11/〔Upcosψ〕=1600/〔220×0.9〕=8.1AWL12支路：荧光灯1只×〔3×16〕W。那么：Pe12=∑Pa〔1+α〕=1×〔3×16〕×〔1+0.2〕=57.6WP30.12=KdPe12=0.8×57.6=46.08WI30.12=P30.12/〔Upcosψ〕=46.08/〔220×0.9〕=0.3ALa-b：Pe=∑〔Pe1+Pe2+Pe3+……+Pe12〕=1036.8+777.6+777.6+777.6+1113.6+168+256+2500+2000+2500+2000+57.6=13964.8WP30=KdPe=0.8×13964.8=11171.84WI30=P30/〔Upcosψ〕=11171.84/〔220×0.9〕=56.5A十四层照明设备容量WL1支路：荧光灯16只×〔3×18〕W。那么：Pe1=∑Pa〔1+α〕=16×〔3×18〕×〔1+0.2〕=1036.8WP30.1=KdPe1=0.8×1036.8=829.44WI30.1=P30.1/〔Upcosψ〕=829.44/〔220×0.9〕=4.2AWL2支路：荧光灯12只×〔3×18〕W。那么：Pe2=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.2=KdPe2=0.8×777.6=622.08WI30.2=P30.2/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL3支路：荧光灯12只×〔3×18〕W。那么：Pe3=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.3=KdPe3=0.8×777.6=622.08WI30.3=P30.3/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL4支路：荧光灯12只×〔3×18〕W。那么：Pe4=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.4=KdPe4=0.8×777.6=622.08WI30.4=P30.4/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL5支路：荧光灯7只×〔2×32〕W,10只×〔3×16〕W。那么：Pe5=∑Pa〔1+α〕=[7×〔2×32〕+10×〔3×16〕]×〔1+0.2〕=1113.6WP30.5=KdPe5=0.8×1113.6=890.88WI30.5=P30.5/〔Upcosψ〕=890.88/〔220×0.9〕=4.5AWL6支路：防水防尘吸顶灯5只×28W。那么：Pe6=∑Pa〔1+α〕=5×28×〔1+0.2〕=168WP30.6=KdPe6=0.8×168=134.4WI30.6=P30.6/〔Upcosψ〕=134.4/〔220×0.9〕=0.7AWL7支路：指示灯7只×〔2×8〕W；应急灯6只×〔2×3〕W，3只×36W。那么：Pe7=∑Pa〔1+α〕=7×〔2×8〕+6×〔2×3〕+3×36=2656WP30.=KdPe7=0.8×256=204.8WI30.7=P30.7/〔Upcosψ〕=204.8/〔220×0.9〕=1.1AWL8支路：插座5只，每只按500W。那么：Pe8=∑Pa〔1+α〕=5×500=2500WP30.8=KdPe8=0.8×2500=2000WI30.8=P30.8/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL9支路：插座4只，每只按500W。那么：Pe9=∑Pa〔1+α〕=4×1500=2000WP30.9=KdPe9=0.8×2000=1600WI30.9=P30.9/〔Upcosψ〕=1600/〔220×0.9〕=8.1AWL10支路：插座5只，每只按500W。那么：Pe10=∑Pa〔1+α〕=5×500=2500WP30.10=KdPe10=0.8×2500=2000WI30.10=P30.10/〔Upcosψ〕=2000/〔220×0.9〕=10.1AWL11支路：插座4只，每只按500W。那么：Pe11=∑Pa〔1+α〕=4×500=2000WP30.11=KdPe11=0.8×2000=1600WI30.11=P30.11/〔Upcosψ〕=1600/〔220×0.9〕=8.1AWL12支路：荧光灯1只×〔3×16〕W。那么：Pe12=∑Pa〔1+α〕=1×〔3×16〕×〔1+0.2〕=57.6WP30.12=KdPe12=0.8×57.6=46.08WI30.12=P30.12/〔Upcosψ〕=46.08/〔220×0.9〕=0.3AL1-2：Pe=∑〔Pe1+Pe2+Pe3+……+Pe12〕=1036.8+777.6+777.6+777.6+1113.6+168+256+2500+2000+2500+2000+57.6=13964.8WP30=KdPe=0.8×13964.8=11171.84WI30=P30/〔Upcosψ〕=11171.84/〔220×0.9〕=56.5A十五层照明设备容量WL1支路：荧光灯12只×〔3×18〕W。那么：Pe1=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.1=KdPe1=0.8×777.6=622.08WI30.1=P30.1/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL2支路：荧光灯10只×〔3×18〕W。那么：Pe2=∑Pa〔1+α〕=10×〔3×18〕×〔1+0.2〕=648WP30.2=KdPe2=0.8×648=518.4WI30.2=P30.2/〔Upcosψ〕=518.4/〔220×0.9〕=2.6AWL3支路：荧光灯9只×〔3×18〕W。那么：Pe3=∑Pa〔1+α〕=9×〔3×18〕×〔1+0.2〕=583.25WP30.3=KdPe3=0.8×583.2=466.56WI30.3=P30.3/〔Upcosψ〕=466.56/〔220×0.9〕=2.4AWL4支路：荧光灯12只×〔3×18〕W。那么：Pe4=∑Pa〔1+α〕=12×〔3×18〕×〔1+0.2〕=777.6WP30.4=KdPe4=0.8×777.6=622.08WI30.4=P30.4/〔Upcosψ〕=622.08/〔220×0.9〕=3.2AWL5支路：荧光灯7只×〔2×32〕W,8只×〔3×16〕W。那么：Pe5=∑Pa〔1+α〕=[7×〔2×32〕+8×〔3×16〕]×〔1+0.2〕=998.4WP30.5=KdPe5=0.8×998.4=798.72WI30.5=P30.5/〔Upcosψ〕=798.72/〔220×0.9〕=4.1AWL6支路：防水防尘吸顶灯5只×28W。那么：Pe6=∑Pa〔1+α〕=5×28×〔1+0.2〕=168WP30.6=KdPe6=0.8×168=134.4WI30.6=P30.6/〔Upcosψ