2013年计算机等级考试三级PC技术上机（6） .doc

2013年计算机等级考试三级pc技术上机（6）请编制程序，其功能是：将内存中存放着20个数字09之间的ascii字符(包括数字0和9的ascii字符)或sp字符(20h)，请将数字09之间的ascii字符(包括数字0和9的ascii字符)转换为相应的八位二进制数，并将sp字符转换为 $ 字符(24h)。将按上述方法处理后得到的20个字节存入内存中。例如：内存中有 20h(sp),30h(0),31h(1),31h(1),20h(sp),32h(2),39h(9)(共20个ascii字符)结果为 24h($),00h,01h,01h,01h,24h($),02h(2),09h(9)(共20个字节)部分程序已给出, 其中原始数据由过程load从文件input1.dat中读入source开始的内存单元中。运算结果要求从result开始存放,由过程save保存到文件output1.dat中。填空begin和end之间已给出的一段源程序使其完整(空白已用横线标出,每行空白一般只需一条指令, 但采用功能相当的多条指令亦可),或删除begin和end之间原有的代码并自行编程来完成要求的功能。对程序必须进行汇编,并与io.obj链接产生prog1.exe执行文件,最终运行程序产生结果(无结果或结果不正确者均不得分)。调试中若发现整个程序中存在错误之处, 请加以修改。试题程序：extrn load:far,save:farn equ 20stac segment stackdb 128 dup(?)stac endsdata segmentsource db n dup(?)result db n dup(0)name0 db input1.dat,0name1 db output1.dat,0data endscode segmentassume cs:code,ds:data,ss:stacstart proc farpush dsxor ax,axpush axmov ax,datamov ds,axlea dx,source ;数据区起始地址lea si,name0 ;原始数据文件名mov cx,n ;字节数call load ;从input1.dat中读取数据;*begin*_mov di,0_chan: _sub al,20hjz changesub al,_mov resultdi,al_dec cxjz exitjmp chanchange: mov resultdi,24hinc diinc sijmp _exit : nop;*end*lea dx,result ;结果数据区首址lea si,name1 ;结果文件名mov cx,n ;字节数call save ;保存结果到文件retstart endpcode endsend 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