



全文预览已结束
下载本文档
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
精品论文推荐weighted boundedness in morrey spaces forsublinear operators1hou weijie, liu mingjubeijing university of aeronautics and astronautics (100191)abstractthe classical morrey spaces were introduced by morrey to study the local behaviour of solutions tosecond order elliptic partial differential equations. since then these spaces play a very import role in studying the regularity of solutions to second order elliptic partial differential equations.as morrey spaces may be considered as an extension of lebesgue spaces, it is natural and important to study the weighted boundedness for operaters in morrey spaces. much work in this direction has been done.the studying of sublinear operators is very active these years, in this paper, the authors introduce a type of topological structure in the cartesian product and a set function, and in advance discuss weighted boundedness of sublinear operators in morrey spaces. the result improve and extend the known results. keywords: sublinear operator; morrey spaces; weight functionclc number: o177.31. introduction and the main resultsthe classical morrey spaces were introduced by morrey to study the local behaviour of solutions to second order elliptic partial differential equations. as morrey spaces may be considered as an extension of lebesgue spaces, it is natural and important to study the weightedboundedness for operaters in morrey spaces. much work in this direction has been done- 4 -(145), our results extend that in this papers. in the following,x e denotes the characteristicfunction of the set e , c is a constant, not necessarily the same in each line.let be a positively growth function on (0, )and satisfy a doubling condition, thatis (2r ) d (r) , where d is a constant independent of r , is a weight function onrn .assumethatvisasetandrn vhassometopologicalstructure.letrn v = ( x, t ) : x rn , t v , is the borel measure on rn v . is a funtionmapping the balls inrn into the borel sets innrn vand satisfies:(1) ifb1 , b2are balls inrwith b1 i b2 = , then (b1 ) i (b2 ) = ;(2) ifb1 b2 , then ( b1 ) (b2 ) ;(3) for anyx rn ,u (b( x, r ) = rn v .r 0*let be a young function and satisfy the conditon 2 or p , that is for anyt 0 , (2t ) c (t ) , or there existsk 1 , such that (2t) 2k p (t)for anyt 0and0 p 0 (r)we define the generalized morrey spaces onrn vas follows1 本课题得到国家自然科学基金(10726008)的资助。l(rv , ) = f :| f | , . , nl ( )let g be a locally integrable function on rn , ifrn v = rn ,d ( y, t ) = ( x)dx , then weobtain the generalized morrey spaces onrn .l , (rn , ) = g :| g |= sup1 (| g ( y) |) ( y)d 0 (r) b ( x,r )if (r) = r , 0 , (t) = t pspace(see3)., thenlp , = lp , which is the classical morreyin the following we will give the main results of this paper.theoremsuppose that t is a sublinear operator and(, ) c1 ( ) , that issup ( (b) c ( x)a.e.xb (b)if t is bounded froml (rn , ) tol (rn v , ) , i.e. (| tf ( y, t ) |)d ( y, t) c (| f ( y) |) ( y)d ,rn vrnthen t is also bounded froml , (rn , )to l , (rn v , ) , that is| tf | , c | f | , .l ( )l ( )where c is a constant, not necessarily the same in each line.2. proof of the theoremlet us first give two lemmas before we prove our theorem.nlemma 1 let(, ) c1 ( ) , 1 d 2, for a locally integrable function g onrn v, letg* ( x) = sup1| g ( y, t) | d ( y, t ), then for anyb = b( x, r )andxb (b)young function ,we have ( b ) (| f ( y) |) x *( y)d c (r) | f |.rn ( b )l , ( )lemma 2 letg 0be a locally integrable function onrn vand be a positiveborel measure onrn v . if for any(, ) c1 ( ) , the sublinear operator t is boundedfrom l ( rn , ) tol (rn v , ) ,then (| tf ( y, t ) |) g ( y, t)d ( y, t) c (| f ( y) |) g* ( y)d .rn vrnproof of lemma 1 by(, ) c1 ( )x *( y) = sup1| x( x, t ) | d ( x, t) ( b )yq (q) (q ) ( b )= sup1 ( (q) i ( b)yq (q) sup1 ( (q)yq (q) c ( y)then we have (| f ( y) |) x *( y)d rn= b ( b )* (| f ( y) |) x ( b )( y)d +* 2k +1 b / 2k bk =0 (| f ( y) |) x ( b )( y)d c b (| f ( y) |) ( y)d + c 2k +1 b / 2k bk = 0 (| f ( y) |) ( y)d c (| f ( y) |) ( y)d + c 2 kn (| f ( y) |) ( y)d b c2 kn2k bk =1 (| f ( y) |) ( y)d 2k bk =0 c 2 kn (2kr) | f | , l ( )k =0 c 2 knkd (r ) | f | , l ( )k =0 c (r ) | f | , l ( )the last inequality holds because of the fact that the series0 2 n d 1 . (2 n d)kk = 0is covergent sinceproof of lemma 2 let haved ( x, t) = g ( x, t )d ( x, t ), ( x) = g * ( x) ,by the definition ofg* , weg* ( y) = sup1| g ( y, t ) | d ( y, t )yb (b) ( b )= sup1 ( (b)yb (b) c ( y)(c 1)fromit is obvious that(, ) c1 ( ) ,then by the assumption of lemma 2,t is boundedl ( rn , ) tol (rn v , ) ,we get (| tf ( y, t) |) g ( y, t)d ( y, t ) = (| tf ( y, t) |)d ( y, t)rn v rn v . c rn (| f ( y) |) ( y)d crn (| f ( y) |) g* ( y)d now let us turn to the proof of our theorem.fix a ballb = b( x, r) rn , and takingg ( y, t ) = x ( b )( y, t)in lemma 2 and by usinglemma 1, we have ( b ) (| tf ( y, t ) |)d ( y, t )= rn v (t | f ( y, t ) |) x ( b ) ( y, t)d ( y, t ) c rn (| f ( y) |) x *( y)d c (r ) | f | , ( b )l ( )that is| tf | , c | f | , .l ( )l ( )the proof of the theorem is complete.+remark.(1) ifrn v = rn+1 , (t ) = t p , (b) = b% = ( y, t ) rn+1 : y b, 0 t r ,we get the theorem in 4.+(2) ifrn v = rn+1 , (b) = b% , our result is the same as that in 5.(3) as maximal operators are included in sublinear operators, so our results partly extend the one in 6references1 mizuhara l t. boundedness of some classical operators on generalized morrey spaces in harmonic analysis, icm-90 conference proceedings(ed.s.igari), tokyo:springer-verlag, 1991:183-1892 j.o.stromberg. bounded mean oscillation with orlicz
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 小学一年级上册-北师大数学第四单元检测卷
- (二模)淄博市2024-2025 学年度部分学校高三阶段性诊断检测生物试卷(含标准答案)
- 2024年纺织品设计师考试经验分享和试题答案
- 培养思维的2024年纺织品检验员证书的试题及答案
- 2024年国际商业美术设计师考试试题及答案精要
- 柿饼钓鱼测试题及答案
- 改革对社会发展的作用
- 机织与针织物检测的差异试题及答案
- 字形美感测试题及答案
- 广告理论与实务助理广告师考试试题及答案
- 2024年全国青少年航天创新大赛航天知识竞赛试题
- DB11∕2075-2022 建筑工程减隔震技术规程
- 铅锌矿的冶炼技术进展与设备改进
- 煤矿劳动组织管理培训课件
- 仓储绩效考核实施细则仓库人员绩效考核内容与评分标准
- 混凝土拌合物凝结时间自动计算记录
- 2022睡眠医学中心建设指南
- 地磅允许误差
- 《母鸡》作业设计-统编版语文四年级下册
- 乡土中国第二课
- 【高中物理竞赛专题大全】竞赛专题1力学50题竞赛真题强化训练解析版
评论
0/150
提交评论