面向对象程序设计实验九

温州大学物理与电子信息工程学院 面向对象程序设计实验报告实验名称：实验九：运算符重载班 级：计算机科学姓 名：钱旭北学 号：07202043217实验地点：5B305日 期：一、实验目的：1、理解运算符重载的本质和意义。2、掌握成员函数方式的运算符重载。3、掌握友元方式的运算符重载二、实验环境：windows 2000, visual c+6.0或c-free三、实验内容和要求：扩展实验五中Complex类的内容，增加1、单目运算符负号：的重载；2、双目运算符、*、/、=、!=的友元重载；3、双目运算符、*、/的成员重载;4、插入运算符 的重载四、预习内容：1、 什么样的运算符应重载为成员？左操作数属于本类 2、运算符对应的函数名是什么？Operator 运算符 五、实验步骤（各源程序文件）：#includeusing namespace std;class complex double re, im ; public: complex(double a=0,double b=0):re(a),im(b) complex operator -()return complex(-re,-im); complex operator +=(const complex& y); complex operator -=(const complex& y); complex operator *=(const complex& y); complex operator /=(const complex& y); friend complex operator +(const complex& x,const complex& y); friend complex operator -(const complex& x,const complex& y); friend complex operator *(const complex& x, const complex& y); friend complex operator /(const complex& x, const complex& y); friend bool operator =(const complex& x,const complex& y); friend bool operator !=(const complex& x,const complex& y); friend ostream& operator (istream& i, complex& a); void display();istream& operator (istream& i, complex& a) ia.rea.im; return i;ostream& operator (ostream& o, complex a)o(; if(a.re!=0) o0) o+; if(a.im!=0) if(a.im!=-1 & a.im!=1) oa.im; else if(a.im0) o-; oi; else if(a.re=0) o0; o); return o;complex complex:operator +=(const complex& y) return complex(re+=y.re,im+=y.im);complex complex:operator -=(const complex& y) return complex(re-=y.re,im-=y.im);complex complex:operator *=( const complex& y) double a,b; a=re*y.re-im*y.im ; b=re*y.im+im*y.re; re=a;im=b; return complex(re,im);complex complex:operator /=( const complex& y)double a,b; a=1.0/(y.re*y.re+y.im*y.im)*(re*y.re+im*y.im); b=1.0/(y.re*y.re+y.im*y.im)*(im*y.re-re*y.im); re=a;im=b; return complex(re,im);complex operator +(const complex& x,const complex& y) return complex(x.re+y.re,x.im+y.im);complex operator -(const complex& x,const complex& y) return complex(x.re-y.re,x.im-y.im) ;complex operator *(const complex& x, const complex& y) return complex(x.re*y.re-x.im*y.im,x.re*y.im+x.im*y.re);complex operator /(const complex& x, const complex& y) return complex(1.0/(y.re*y.re+y.im*y.im)*(x.re*y.re+x.im*y.im), 1.0/(y.re*y.re+y.im*y.im)*(x.im*y.re-x.re*y.im);bool operator =(const complex& x,const complex& y) if(x.re=y.re& x.im=y.im)return true; else return false ;bool operator !=(const complex& x,const complex& y) if(x.re!=y.re| x.im!=y.im)return true; else return false ;void complex:display() cout(re,im)endl;void main() complex a(3.0,2.0),b(1.0,2.0),c,d; couta=;a.display(); coutb=;b.display(); c=-a; cout-a=;c.display(); c=a+b; couta+b=;c.display(); c=a-b; couta-b=;c.display(); c=a*b; couta*b=;c.display(); c=a/b; couta/b=;c.display(); if(a=b) couta=b; else couta!=bendl; if(a!=b) couta!=bendl; else couta=bendl; a+=b; couta+=b,a=;a.display(); a-=b; couta-=b,a=;a.display(); a*=b; couta*=b,a