[!] CC++层序设计教程 课后实验答案(第一章~第七章).doc

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C/C+层序设计教程 课后实验答案(第一章第七章)实验1.1#include iostream.h#include iomanip.hvoid main() int x; cinx; int y; y=x*x; coutx*x=hexyendl;实验1.2#include iostream.hvoid main() float x=1,y=2,h=3,s; s=h*(x+y)/2.0; cout上底为1，下底为2，高为3的梯形面积为：sendl;实验1.3#include iostream.hvoid main() float x,y,z,s; cout请输入三门成绩x,y,z：xyz; s=(x+y+z)/3; cout三门课平均成绩为：sendl;实验2.1#include iostream.h#include iomanip.hvoid main() float s1,s2,s3; double aver; cout输入三个数据：s1s2s3; aver=(s1+s2+s3)/3; aver=aver*100+0.5; aver=(int)aver; aver=aver/100; cout平均值=averendl;实验2.2#include iostream.h#include math.hvoid main() double x,y,z; cout请输入直角三角形的两直角边长：xy; z=sqrt(x*x+y*y); cout该直角三角形的斜边长为：zendl;实验2.4#include iostream.hvoid main()double a,b,c,t,ave;cout请输入三个数abc;if (ab) t=a;else t=b;if (tc) t=t;else t=c;ave=(a+b+c)/3;cout三个数的平均值为ave，其中最小的数为：tendl;实验2.3#include iostream.hvoid main()double x,y,r,t;cout请输入x yxy;r=x*x+y*y;if (r=4) t=12*3.1415926;else t=0;couttendl;实验2.5#include iostream.hvoid main()char c1=f,c2=l,c3=y;coutc1c2c3z) c1=c1-26;if(c2z) c2=c2-26;if(c3z) c3=c3-26;coutc1c2c3xy; if(x=0|y=0) coutinput errory) r1=x/y; r2=x%y; else r1=y/x; r2=y%x; cout商= r1 余数= r2endl; 实验3.2#include iostream.hvoid main() int x,y; cout请输入上网时间x:x; if(x=65) y=130; else if(x=50) y=x*2; else if(x=10) y=x*2.5; else y=30;cout上网费用y为：yendl;实验3.3#include iostream.hvoid main() float x,y1,y2; int xp; coutx; if(x=3000) y1=0.7*x; else if(x=2000) y1=0.8*x; else if(x=1000) y1=0.9*x; else y1=x; xp=(int)x/1000 switch(xp) case 实验3.5#include iostream.hvoid main()double x,y,a;char z;cout请输入您要计算的式子xzy;if(z=42)a=x*y;coutxy=aendl;else if(z=43)a=x+y;coutxy=aendl; else if(z=45)a=x-y;coutxy=aendl;else if(z=47)a=x/y;coutxy=aendl;elsecout你输入了非法的运算符。endl;图太多， 不截了。实验3.6#include iostream.h#include math.hvoid main()int a,b,c;double x1,x2;cout请输入一元二次方程的系数a、b、c：abc;if(b*b-4*a*c)0)x1=(-b+sqrt(b*b-4*a*c)/(2*a);x2=(-b-sqrt(b*b-4*a*c)/(2*a);cout方程的解为：x1=x1;x2=x2endl;else if(b*b-4*a*c)=0)x1=x2=(-b)/(2*a);cout方程的解为：x1=x1=x2=x2endl;elsecout方程无解endl;实验 4.1#include iostream.hvoid main()int n,sum(0);for(n=1; ;n+=2)sum=sum+n; if(n=19) break;coutsum=sumendl;实验 4.6#include iostream.hvoid main()int i,j,k;for(i=0;i=9;i+)for(j=0;j=9;j+) for(k=0;k100)coutijkendl;实验 4.9#include iostream.h#include math.hvoid main() double x1,x0,x; int a; cout请输入a：a; x1=a; do x0=x1; x1=2/3.0*x0+a/(3.0*x0*x0); while (fabs(x1-x0)1.0e-5); cout用迭代法算出a的立方根x为：x1endl; x=a; x=pow(x,1/3.0); cout用pow(x,1/3)公式算出a的立方根x为：xendl;实验4.2#include iostream.hvoid main()int a,b,c,d,e,f;cout请输入要逆序的数：a;b=a/1000;c=a%1000/100;d=a%100/10;e=a%10; if(b=0 & c!=0)f=100*e+10*d+c;else if(c=0 & d!=0)f=10*e+d;else if(d=0 & e!=0)f=e;elsef=1000*e+100*d+10*c+b;if(b9)cout你输入的数太大，请重新输入；endl;else cout所求得的逆序数为：f;0.0001;i+)t+=i;s+=(1/t);coutsendl;实验4.4#include iostream.hvoid main()int n;double s=2,a,i;cout请输入n值：n;for(i=1;in;i+)a=(2*i)*(2*i)/(2*i-1)*(2*i+1);s=s*a;coutsendl;实验4.5#include iostream.h#include iomanip.hvoid main()int i,j;for(i=1;i10;i+)coutsetw(11-i);for(j=0;j2*i-1;j+)couti;coutendl;coutendl;char c;for(i=0;i9;i+)c=i+A;coutsetw(i+2);for(j=0;j2*(9-i);j+)coutc;coutendl;实验4.7#include iostream.hvoid main()int i,j,k,t=0;for(i=1;i5;i+)for(j=i+1;j6;j+)for(k=5;k7;k+)if(jk)couti j kendl;t+;cout满足条件的方案数为：tendl;实验4.8#include iostream.h#include stdlib.h#include stdio.h#include time.hvoid main()int i,a,n,temp,s=0;srand(unsigned)time(NULL);a=rand()%9+1;n=rand()%6+5;temp=0;for(i=1;i=n;i+)temp=temp*10+a;s+=temp;couta n sendl;不要问我为什么这么写随机函数，我也不知道为什么，我是上网找了一个很高级很高级的产生随机函数的方法，然后套进来的。实验5.1#include iostream.h#include stdlib.hvoid main() int a10,i,min,max; double ave=0; for(i=0;i10;i+) ai=int(rand()%71+30); for(i=1,min=a0;iai)min=ai; for(i=1,max=a0;i10;i+) if(maxai)max=ai; for(i=0;i10;i+) coutaiendl; ave+=ai; ave=ave/10; cout最大值为：max；最小值为：min；平均值为：ave;实验5.8#include iostream.h#include string.h#include stdio.hvoid main() char a80,b80; int i; gets(a); for(i=0;*(a+i)!=0;i+) if(ai=a)bi=ai-32;elsebi=ai;bi=0;for(i=0;*(b+i)!=0;i+)coutbi;coutendl;cout用strupr函数求得：strupr(a)endl;实验5.2#include iostream.h#include stdlib.h#include stdio.h#include time.h void main( )int i,j,t,s20;srand(unsigned)time(NULL);for(i=0;i20;i+)si=rand()%100+1;for(i=0;i19;i+)t=si;for(j=i+1;jt)si=sj;sj=t;t=si;for(i=0;i20;i+)coutsiendl;实验5.3#include iostream.h#include stdlib.h#include stdio.h#include time.hvoid main()int i,s110,s210,m;srand(unsigned)time(NULL);for(i=0;i10;i+)s1i=rand()%100+1;cout移动前数据endl;for(i=0;i10;i+)couts1i ;coutendl输入右移位数m;for(i=0;i10;i+)if(i+m10)s2i+m=s1i;elses2i+m-10=s1i;cout右移m位后数据endl;for(i=0;i10;i+)couts2i ;coutendl;实验5.4这是我迄今为止做过的最麻烦的一道题#include iostream.h#include stdlib.h#include stdio.h#include time.h#include iomanip.hvoid main()/建立A、B矩阵：int i,j,k,s144,s244,s344,s444,s544,t3;srand(unsigned)time(NULL);for(i=0;i4;i+)for(j=0;j4;j+)s1ij=rand()%41+30;cout矩阵A为：endl;for(i=0;i4;i+)for(j=0;j4;j+)coutsetw(6)s1ij;coutendl;for(i=0;i4;i+)for(j=0;j4;j+)s2ij=rand()%35+101;coutendl矩阵B为：endl;for(i=0;i4;i+)for(j=0;j4;j+)coutsetw(6)s2ij;coutendl;for(i=0;i4;i+)for(j=0;j4;j+)s3ij=s1ij+s2ij;/拷贝一下矩阵A，方便做第四问：for(i=0;i4;i+)for(j=0;j4;j+)s4ij=s1ij;s5ij=s1ij;/第一问：coutendl矩阵C为：endl;for(i=0;i4;i+)for(j=0;j4;j+)coutsetw(6)s3ij;coutendl;/第二问：t0=s300;for(i=0;i4;i+)for(j=0;jt0)t1=i;t2=j;t0=s3ij;coutendlC矩阵中最大值为：t0其下标为(t1,t2)endl;/第三问之A的下三角：for(i=0;i3;i+)for(j=i+1;j4;j+)for(k=0;k4;k+)s1jk=s1jk-s1ik/s1ii*s1ji;coutendl以下三角显示矩阵A得：endl;for(i=0;i4;i+)for(j=0;j4;j+)coutsetw(6)s1ij;cout0;i-)for(j=i-1;j=0;j-)for(k=0;k4;k+)s2jk=s2jk-s2ik/s2ii*s2ji;coutendl以下三角显示矩阵B得：endl;for(i=0;i4;i+)for(j=0;j4;j+)coutsetw(6)s2ij;coutendl;/第四问：for(i=0;i4;i+)t0=s40i;s40i=s42i;s42i=t0;coutendl1、3行互换后A矩阵得：endl;for(i=0;i4;i+)for(j=0;j4;j+)coutsetw(6)s4ij;coutendl;/第五问：t1=0;t2=0;for(i=0;i4;i+)t1+=s5ii;t2+=s53-i3-i;t0=t1+t2;coutendl两对角线之和为：t0endl;实验5.5#include iostream.h#include iomanip.hvoid main()int n,i,j,a1010;for(i=0;i10;i+)for(j=0;j10;j+)aij=1;coutn;for(i=2;in;i+)for(j=1;ji;j+)aij=ai-1j-1+ai-1j;for(i=0;in;i+)for(j=0;ji+1;j+)coutsetw(5)aij;coutendl;for(i=0;in;i+)for(j=0;jn-i;j+)cout ;for(j=0;ji+1;j+)coutsetw(6)aij;coutendl;实验5.6#include iostream.h#include string.hvoid main()char s1=VISUAL C+ PROGRAM,s2=VISUAL C+ PROGRAM,*p,*q,t;int i,l;cout原数组为：endl;for(i=0;s1i;i+)couts1i;coutendl;l=strlen(s1);for(i=0;il/2;i+)t=s1i;s1i=s1l-i-1;s1l-i-1=t;cout用下标法倒置得：endl;for(i=0;s1i;i+)couts1i;coutendl;p=s2;q=&s2l-1;for(;pq;p+,q-)t=*p;*p=*q;*q=t;cout用地址法倒置得：endl;for(i=0;s2i;i+)couts2i;coutendl;实验5.7#include iostream.hvoid main()int i,j;char s40=asdfghjkloiIuuyVVYTFtcu,t;for(i=0;si;i+)coutsi;coutendl;cout输入要删除的字符：t;for(i=0;si;i+)if(si=t)for(j=i;sj;j+)sj=sj+1;for(i=0;si;i+)coutsi;coutendl;实验6.1#include iostream.hbool isprime(int m)int i,j;for(i=1,j=0;im;i+)if(m%i!=0)continue;j+;if(j=1)return true;elsereturn false;void main()int i,count=0;for(i=3;count10;i+)if(isprime(i) & isprime(i+2)cout(i,i+2)=10000 & x=100000 & x=999999)s=x/100000+x/10000%10*10+x/1000%10*100+x/100%10*1000+x/10%10*10000+x%10*100000;return s;void main()int x,i;for(i=10000,x=0;x10;i+)if(i=reverse(i)coutiendl;x+;实验6.3#include iostream.h#include stdio.hint palindrome(char s)char s140;int i,n;for(i=0,n=-1;si;i+)n+;for(i=0;si;i+)s1i=sn-i;for(i=0,n=0;si;i+)if(si!=s1i)n+;if(n=0)return 1;elsereturn 0;void main()char s40;cout请输入字符串：endl;gets(s);if(palindrome(s)cout该字符串回文。endl;elsecout该字符串不回文。endl;实验6.4（1）#include iostream.hint fun(int s,int n,int *x) int i,j,t,imax,n1,x1; n1=n;x1=*x; n=0;*x=0; for(i=0;in1-1;i+) imax=i; for(j=i+1;jsimax)imax=j; t=si; si=simax; simax=t; for(i=0;in1;i+) if(si=90)n+; return n;void main()int n,x,i,n1;cout请输入学生数：n;n1=n;int *s=new intn1;cout请输入n1个同学的成绩：endl;for(i=0;isi;cout请输入及格分：x;n=fun(s,n,&x); for(i=0;in1;i+)coutsi ;coutendl; cout优秀成绩的人数为：nendl; cout不及格人数为：xendl;实验6.4（2）#include iostream.hvoid fun(int s,int n,int &x,int &y) int i,j,t,imax,n1,x1; x1=x;x=0; for(i=0;in-1;i+) imax=i; for(j=i+1;jsimax)imax=j; t=si; si=simax; simax=t; for(i=0;in;i+) if(si=90) y+; void main()int n,x,i,y(0);cout请输入学生数：n;int *s=new intn; cout请输入n个同学的成绩：endl;for(i=0;isi;cout请输入及格分：x;fun(s,n,x,y); for(i=0;in;i+)coutsi;coutendl; cout优秀成绩的人数为：yendl; cout不及格人数为：xendl;实验6.8#include iostream.h#include math.hdouble dish(int x1,int x2,int y1, int y2)double s;s=sqrt(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);return s;double dish(double x1,double x2,double y1,double y2)double s;s=sqrt(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);return s;void main() double x1,x2,y1,y2; cout请输入A点横坐标x1:x1; cout请输入A点纵坐标y1:y1; cout请输入B点横坐标x2：x2; cout请输入B点纵坐标y2：y2; if(x1=(int)x1 & x2=(int)x2 & y1=(int)y1 & y2=(int)y2) coutdish(int)x1,(int)