08-09学年第一学期无机化学期终试卷答案(B).doc

第一学期无机化学期终考试试卷答案(B)1-8章一、选择题 ( 共16题 16分 )1. (3972) (D)2. (3675) (C)3. (0974) (D)4. (6673) (D)5. (0672) (D) 盐效应使溶解度加大6. (3971) (C)7. (3418) (C)8. (0617) (D)9. (3693) (B)10. (3793) (B)11. (3439) (B)12. (0777) （A）13. (0975) (A)14. (3674) (C)15. (3333) (B)16. (0972) (B)二、填空题 ( 共 6题 14分 )1. (3746) (1) ，。 (2) Cl2，Fe3+，Ag+。 (3) 无。2. (0674) 减小，增大，小3. (0675) 增大，变小，变大，不变4. (6760)Ni(OH)3(s) + e- = Ni(OH)2(s) + OH-(aq) ；Cd(s) + 2OH-(aq) = CdO(s) + H2O(l) + 2e-5. (0447) G 0 为 +6. (0710) (1) (4) (2) (3)三、计算题 ( 共 4题 32分8,8,8,8 )1. (0523) 设PCl3的转化率为x PCl3 + Cl2 PCl5 达平衡时物质的量/mol (1.00-x) (1.00-x) x 物质的总量 = (2.00-x) mol kPa kPa = 0.54 解得 x = 0.19 = 0.45 = 0.102. (3704) (1) 5HBrO =+ 2Br2 + 2H2O + H+ (2) = 1.59 - 1.49 = 0.10 V = -= -4 96.5 0.10 = -39 (kJmol-1) (3) = -2.303RT lgK lgK = 6.84 所以 K 6.9 1063. (3333)Solution. Calculation of Ag+ at the point where AgCl precipitation starts:Ksp(AgCl) = Ag+Cl- = 1.7 * 10-10so Ag+ = Ksp/Cl- = 1.7 * 10-10/0.1 = 1.7 * 10-9 MCalculation of Br- consistent with this Ag+:Ksp(AgBr) = Ag+Br- = 5 * 10-13so Br- = Ksp(AgBr)/Ag+ = 5 * 10-13/(1.7 * 10-9)= 2.94 * 10-4 MAccording to this calculation, we can reduce the concentration of Br- from the initial value of 0.1 M to 2.94 * 10-4 M before AgCl starts to precipitate. The fraction of the original Br- left in solution is2.94 * 10-4/0.1 = 2.94 * 10-3.4. (3837) t1/2 =， k = 5.78 10-3 (min-1) t = 398 min四、问答题 ( 共 5题 38分6,8,6,6,12 ) 1. (7145)共有两种几何异构体，其结构示意图如下：，2. (0948)1s22s22p63s23p63d104s24p3n44444l00111m000-1+1ms+-+ +5， p， As2O3， 俗称砒霜。3. (6818) (1) 均相，(2) 非均相