下面程序是1位十进制计数器的VHDL描述.doc

下面程序是1位十进制计数器的VHDL描述，试补充完整。 2. 下面是一个多路选择器的VHDL描述，充完整。LIBRARY IEEE;USE IEEE.STD_LOGIC_1164.ALL;USE IEEE.STD_LOGIC_UNSIGNED.ALL;ENTITY CNT10 ISPORT ( CLK : IN STD_LOGIC ; Q : OUT STD_LOGIC_VECTOR(3 DOWNTO 0) ;END CNT10;ARCHITECTURE bhv OF CNT10 ISSIGNAL Q1 : STD_LOGIC_VECTOR(3 DOWNTO 0);BEGINPROCESS (CLK) BEGINIF CLKEVENT AND CLK = 1 THEN- 边沿检测IF Q1 10 THENQ1 0);- 置零ELSEQ1 = Q1 + 1 ;- 加1END IF;END IF;END PROCESS ;Q = Q1;END bhv;LIBRARY IEEE;USE IEEE.STD_LOGIC_1164.ALL;ENTITY bmux ISPORT (sel : IN STD_LOGIC;A, B : IN STD_LOGIC_VECTOR(7 DOWNTO 0);Y: OUT STD_LOGIC_VECTOR(7 DOWNTO 0) ;END bmux;ARCHITECTURE bhv OF bmux ISBEGINy = A when sel = 1 ELSE B;END bhv;三、VHDL程序改错仔细阅读下列程序，回答问题LIBRARY IEEE;- 1USE IEEE.STD_LOGIC_1164.ALL;- 2ENTITY LED7SEG IS- 3PORT (A : IN STD_LOGIC_VECTOR(3 DOWNTO 0);- 4CLK : IN STD_LOGIC;- 5LED7S : OUT STD_LOGIC_VECTOR(6 DOWNTO 0);- 6END LED7SEG;- 7ARCHITECTURE one OF LED7SEG IS- 8SIGNAL TMP : STD_LOGIC;- 9BEGIN- 10SYNC : PROCESS(CLK, A)- 11BEGIN- 12IF CLKEVENT AND CLK = 1 THEN- 13TMP LED7S LED7S LED7S LED7S LED7S LED7S LED7S LED7S LED7S LED7S LED7S = 0000000;四、阅读下列VHDL程序，画出原理图（RTL级）LIBRARY IEEE;USE IEEE.STD_LOGIC_1164.ALL;ENTITY HAD ISPORT (a : IN STD_LOGIC;b : IN STD_LOGIC;c : OUT STD_LOGIC;d : OUT STD_LOGIC);END ENTITY HAD;ARCHITECTURE fh1 OF HAD ISBEGINc = NOT(a NAND b);d 0);ELSIF CLK = 1 AND CLKEVENT THENIF LOAD = 1 THEN Q1 := DATA;ELSEIF EN = 1 THENQ1 := Q1 + 1;END IF;END IF; END IF;Q = Q1;END PROCESS;END ONE;2 看下面原理图，写出相应VHDL描述LIBRARY IEEE;USE IEEE.STD_LOGIC_1164.ALL;ENTITY TRI_STATE ISPORT (E, A : IN STD_LOGIC;Y : INOUT STD_LOGIC;B : OUT STD_LOGIC);END TRI_STATE;ARCHITECTURE BEHAV OF TRI_STATE ISBEGINPROCESS (E, A, Y)BEGINIF E = 0 THENB = Y;Y = Z;ELSEB = Z;Y = A;END IF;END PROCESS;END BEHAV;六、综合题下图是一个A/D采集系统的部分，要求设计其中的FPGA采集控制模块，该模块由三个部分构成：控制器（Control）、地址计数器（addrcnt）、内嵌双口RAM（adram）。控制器（control）是一个状态机，完成AD574的控制，和adram的写入操作。Adram是一个LPM_RAM_DP单元，在wren为1时允许写入数据。试分别回答问题下面列出了AD574的控制方式和控制时序图CECSRCK12_8A0工 作 状 态0XXXX禁止X1XXX禁止100X0启动12位转换100X1启动8位转换1011X12位并行输出有效10100高8位并行输出有效10101低4位加上尾随4个0有效AD574逻辑控制真值表（X表示任意）AD574工作时序：1. 要求AD574工作在12位转换模式，K12_8、A0在control中如何设置K12_8为1，A0为02. 试画出control的状态机的状态图类似书上图8-43. 对地址计数器模块进行VHDL描述输入端口：clkinc 计数脉冲 cntclr计数器清零输出端口：rdaddrRAM读出地址，位宽10位library ieee;use ieee.std_logic_1164.all;use ieee.std_logic_unsigned.all;entity addr_cnt isport (clkinc, cntclr : in std_logic;wraddr : out std_logic_vector (9 downto 0) );end addr_cnt;architecture one of addr_cnt issignal tmp : std_logic_vector (9 downto 0);beginprocess (clkinc, cntclr)beginif clkincevent and clkinc = 1 thenif cntclr = 1 thentmp 0);elsetmp = tmp + 1;end if;end if;end process;wraddr = tmp;end one;4. 根据状态图，试对control进行VHDL描述library ieee;use ieee.std_logic_1164.all;use ieee.std_logic_unsigned.all;entity control isport (addata : in std_logic_vector (11 downto 0);status, clk : in std_logic;cs, ce, a0, rc, k12_8, clkinc : out std_logic;rddata : out std_logic_vector (11 downto 0) );end control;architecture behav of control istype con_st is (s0, s1, s2, s3, s4);signal cst, nst : con_st;signal lock : std_logic;signal reg12 : std_logic_vector (11 downto 0);begina0 = 0;k12_8 = 1;ce = 1;cs = 0;REGP : process (clk)beginif clkevent and clk = 1 thencst rc = 1; lock = 0; nst rc = 0; lock = 0; nst if status = 1 then nst = s3; end if;rc = 1; lock rc = 1; lock = 1; nst rc = 1; lock = 0; nst nst = s0;end case;end process;LOCKP : process (lock)beginif lock = 1 and lockevent thenreg12 = addata;end if;end process;rddata = reg12;clkinc addata, status = status,clk = clk, cs = cs, ce = ce, a0 = a0, rc = rc,k12_8 = k12_8, clkinc = clkinc, rddata = rds);u2 : addr_cntport map (clkinc = clkinc, cntclr = cntclr, wraddr = wraddr);u3 : adramport map (data = rds, wraddress = wraddr,rdaddress = rdaddr, wren = 1, q = rddata);end one;LIBRARY IEEE;USE IEEE.STD_LOGIC_1164.ALL;ENTITY three I