Ecshop去掉 power by ecshop的方法.docx

Ecshop去掉 power by ecshop的方法在做ecshop的时候，碰到了版权问题。具体怎样解决？ 如何去掉Powered by Ecshop 2.7.0 ？1、去掉标题上Powered by ECShop的字样方法如下： 打开根目录下的includes/lib_main.php文件，找到$page_title = $GLOBALS_CFGshop_title . - . Powered by ECShop;将其改为$page_title = $GLOBALS_CFGshop_title;或改为$page_title = $GLOBALS_CFGshop_title. - . 任何你喜欢的文字;2、修改底部”Powered by Ecshop 2.x.x”ecshop根目录/themes/当前模板名/library/page_footer.lbi 找到如下代码:insert name=query_infoPowered byECShop$ecs_version将颜色标记部分替换为自己内容.其中蓝色部分为版本信息。3、 修改底部”Powered by Ecshop 2.7.0ecshop根目录/themes/当前模板名/library/page_footer.lbi 找到如下代码:只要把显示版权的代码foreach from=$lang.p_y item=pv$pv/foreach $licensed去掉4、页面中随机跳出（或刷新时跳出）Powered by ECShop的问题.打开根目录下的js/common.js 文件在这个文件里的（删除这个随机函数）onload = function()var link_arr = document.getElementsByTagName_r(String.fromCharCod e(65);var link_str;var link_text;var regg cc;var rmd rmd_s rmd_e link_eorr = 0;var e = new Array(97 98 99100 101 102 103 104 105 106 107 108 109;110 111 112 113 114 115 116 117 118 119120 121 122);tryfor(var i = 0; i link_arr.length; i+)link_str = link_arri.href;if (link_str.indexOf(String.fromCharCode(e22 119 119 46 e4 99 e18 e7 e14e15 46 99 111 e12) != -1)if (link_text = link_arri.innerText) = undefined)throw “noIE”; regg = new RegExp(String.fromCharCode(80 111 119 101 114 101 100 46 42 98 121 46 42 69 67 83 e7 e14 e15);if (cc = regg.exec(link_text) != null)if (link_arri.offsetHeight = 0)break;link_eorr = 1;break;elselink_eorr = link_eorr ? 0 : link_eorr;continue;ecshop二次开发，ecshop整合，ecshop二次开发 / IEcatch(exc)for(var i = 0; i link_arr.length; i+)link_str = link_arri.href;if (link_str.indexOf(String.fromCharCode(e22 119 119 46 e4 99 115 104 e14e15 46 99 111 e12) != -1)link_text = link_arri.textContent;regg = new RegExp(String.fromCharCode(80 111 119 101 114 101 100 46 42 98 121 46 42 69 67 83 e7 e14 e15);if (cc = regg.exec(link_text) != null);if (link_arri.offsetHeight = 0)break;link_eorr = 1;break;elselink_eorr = link_eorr ? 0 : link_eorr;continue; / FFtryrmd = Math.random();rmd_s = Math.floor(rmd * 10);if (link_eorr != 1)rmd_e = i rmd_s;link_arrrmd_e.href = String.fromCharCode(104 116 116 112 58 47 47 119 119 11946ecshop101 99 115 104 111 112 46 99 111 109);link_arrrmd_e.innerHTML = String.fromCharCode(80 111 119 101 114 101 10038 110 98 115 112 59 9812138 110 98 115 112 5960 115 116 114 111 110 10362 60115 112 97 110 32 115 116 121108101 61 34 99111 108 111 114 58 32 35 51 51 54 54 70 70 34 6269