计算机C++编程答案(1).doc

2.8题#include using namespace std;int main()char c1=C, c2=h, c3=i, c4=n, c5=a;c1+=4;c2+=4;c3+=4;c4+=4;c5+=4;coutpassword is:c1c2c3c4c5endl;return 0;3.2题#include #include using namespace std;int main ( )float h,r,l,s,sq,vq,vz;const float pi=3.1415926;coutrh;l=2*pi*r;s=r*r*pi;sq=4*pi*r*r;vq=3.0/4.0*pi*r*r*r;vz=pi*r*r*h;coutsetiosflags(ios:fixed)setiosflags(ios:right)setprecision(2);coutl= setw(10)lendl;couts= setw(10)sendl;coutsq=setw(10)sqendl;coutvq=setw(10)vqendl;coutvz=setw(10)vzendl;return 0;3.3题#include using namespace std;int main ()float c,f;coutf;c=(5.0/9.0)*(f-32); /注意5和9要用实型表示,否则5/9值为0cout摄氏温度为:cendl;return 0;3.4题#include using namespace std;int main ( )char c1,c2;cout请输入两个字符c1,c2:;c1=getchar(); /将输入的第一个字符赋给c1c2=getchar(); /将输入的第二个字符赋给c2cout用putchar函数输出结果为:;putchar(c1);putchar(c2);coutendl;cout用cout语句输出结果为:;coutc1c2endl;return 0;3.4题另一解#include using namespace std;int main ( )char c1,c2;cout请输入两个字符c1,c2:;c1=getchar(); /将输入的第一个字符赋给c1c2=getchar(); /将输入的第二个字符赋给c2cout用putchar函数输出结果为:;putchar(c1);putchar(44);putchar(c2);coutendl;cout用cout语句输出结果为:;coutc1,c2endl;return 0;3.5题#include using namespace std;int main ( )char c1,c2;int i1,i2; /定义为整型couti1i2;c1=i1;c2=i2;cout按字符输出结果为:c1 , c2endl;return 0;3.8题#include using namespace std;int main ( ) int a=3,b=4,c=5,x,y;coutc & b=c)endl;cout(a|b+c & b-c)endl;coutb) & !c|1)endl;cout(!(x=a) & (y=b) & 0)endl;cout(!(a+b)+c-1 & b+c/2)endl;return 0;3.9题include using namespace std;int main ( )int a,b,c;coutabc;if(ab)if(bc)coutmax=c;elsecoutmax=b;else if (ac)coutmax=c;elsecoutmax=a;coutendl;return 0;3.9题另一解#include using namespace std;int main ( )int a,b,c,temp,max ;coutabc;temp=(ab)?a:b; /* 将a和b中的大者存入temp中 */max=(tempc)?temp:c; /* 将a和b中的大者与c比较，最大者存入maxcoutmax=maxendl;return 0;3.10题#include using namespace std;int main ( )int x,y;coutx;if (x1)y=x;coutx=x, y=x=y;else if (x10) / 1x10y=2*x-1;coutx=x, y=2*x-1=y;else / x10y=3*x-11;coutx=x, y=3*x-11=y;coutendl;return 0;3.11题#include using namespace std;int main ()float score;char grade;coutscore;while (score100|score0)coutscore;switch(int(score/10)case 10:case 9: grade=A;break;case 8: grade=B;break;case 7: grade=C;break;case 6: grade=D;break;default:grade=E;coutscore is score, grade is gradeendl;return 0;3.12题#include using namespace std;int main ()long int num;int indiv,ten,hundred,thousand,ten_thousand,place;/*分别代表个位,十位,百位,千位,万位和位数*/coutnum;if (num9999)place=5;else if (num999)place=4;else if (num99)place=3;else if (num9)place=2;else place=1;coutplace=placeendl;/计算各位数字ten_thousand=num/10000;thousand=(int)(num-ten_thousand*10000)/1000;hundred=(int)(num-ten_thousand*10000-thousand*1000)/100;ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10;indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);coutoriginal order:;switch(place)case5:coutten_thousand,thousand,hundred,ten,indivendl;coutreverse order:;coutindivtenhundredthousandten_thousandendl;break;case 4:coutthousand,hundred,ten,indivendl;coutreverse order:;coutindivtenhundredthousandendl;break;case 3:couthundred,ten,indivendl;coutreverse order:;coutindivtenhundredendl;break;case 2:coutten,indivendl;coutreverse order:;coutindivtenendl;break;case 1:coutindivendl;coutreverse order:;coutindivendl;break;return 0;3.13题#include using namespace std;int main () long i; /i为利润float bonus,bon1,bon2,bon4,bon6,bon10;bon1=100000*0.1; /利润为10万元时的奖金bon2=bon1+100000*0.075; /利润为20万元时的奖金bon4=bon2+100000*0.05; /利润为40万元时的奖金bon6=bon4+100000*0.03; /利润为60万元时的奖金bon10=bon6+400000*0.015; /利润为100万元时的奖金couti;if (i=100000)bonus=i*0.1; /利润在10万元以内按10%提成奖金else if (i=200000)bonus=bon1+(i-100000)*0.075; /利润在10万元至20万时的奖金else if (i=400000)bonus=bon2+(i-200000)*0.05; /利润在20万元至40万时的奖金else if (i=600000)bonus=bon4+(i-400000)*0.03; /利润在40万元至60万时的奖金else if (i=1000000)bonus=bon6+(i-600000)*0.015; /利润在60万元至100万时的奖金elsebonus=bon10+(i-1000000)*0.01; /利润在100万元以上时的奖金coutbonus=bonusendl;return 0;3.13题另一解#include using namespace std;int main ()long i;float bonus,bon1,bon2,bon4,bon6,bon10;int c;bon1=100000*0.1;bon2=bon1+100000*0.075;bon4=bon2+200000*0.05;bon6=bon4+200000*0.03;bon10=bon6+400000*0.015;couti;c=i/100000;if (c10) c=10;switch(c)case 0: bonus=i*0.1; break;case 1: bonus=bon1+(i-100000)*0.075; break;case 2:case 3: bonus=bon2+(i-200000)*0.05;break;case 4:case 5: bonus=bon4+(i-400000)*0.03;break;case 6:case 7:case 8:case 9: bonus=bon6+(i-600000)*0.015; break;case 10: bonus=bon10+(i-1000000)*0.01;coutbonus=bonusendl;return 0;3.14题#include using namespace std;int main ()int t,a,b,c,d;coutabcd;couta=a, b=b, c=c,d=db)t=a;a=b;b=t;if (ac)t=a; a=c; c=t;if (ad)t=a; a=d; d=t;if (bc)t=b; b=c; c=t;if (bd)t=b; b=d; d=t;if (cd)t=c; c=d; d=t;coutthe sorted sequence:endl;couta, b, c, dendl;return 0;3.15题#include using namespace std;int main ()int p,r,n,m,temp;coutnm;if (nm)temp=n;n=m;m=temp; /把大数放在n中, 小数放在m中p=n*m; /先将n和m的乘积保存在p中, 以便求最小公倍数时用while (m!=0) /求n和m的最大公约数r=n%m;n=m;m=r;coutHCF=nendl;coutLCD=p/nendl; / p是原来两个整数的乘积return 0;3.16题#include using namespace std;int main ()char c;int letters=0,space=0,digit=0,other=0;coutenter one line:=a & c=A & c=0 & c=9)digit+;elseother+;coutletter:letters, space:space, digit:digit,other:otherendl;return 0;3.17题#include using namespace std;int main ()int a,n,i=1,sn=0,tn=0;coutan;while (i=n)tn=tn+a; /赋值后的tn为i个a组成数的值sn=sn+tn; /赋值后的sn为多项式前i项之和a=a*10;+i;couta+aa+aaa+.=snendl;return 0;3.18题#include using namespace std;int main ()float s=0,t=1;int n;for (n=1;n=20;n+)t=t*n; / 求n!s=s+t; / 将各项累加cout1!+2!+.+20!=sendl;return 0;3.19题#include using namespace std;int main ()int i,j,k,n;coutnarcissus numbers are:endl;for (n=100;n1000;n+)i=n/100;j=n/10-i*10;k=n%10;if (n = i*i*i + j*j*j + k*k*k)coutn ;coutendl;return 0;3.20题#include using namespace std;int main()const int m=1000; / 定义寻找范围int k1,k2,k3,k4,k5,k6,k7,k8,k9,k10;int i,a,n,s;for (a=2;a=m;a+) / a是21000之间的整数，检查它是否为完数n=0; / n用来累计a的因子的个数s=a; / s用来存放尚未求出的因子之和，开始时等于afor (i=1;ia;i+) / 检查i是否为a的因子if (a%i=0) / 如果i是a的因子n+; / n加1，表示新找到一个因子s=s-i; / s减去已找到的因子，s的新值是尚未求出的因子之和switch(n) / 将找到的因子赋给k1,.,k10case 1:k1=i; break; / 找出的笫1个因子赋给k1case 2:k2=i; break; / 找出的笫2个因子赋给k2case 3:k3=i; break; / 找出的笫3个因子赋给k3case 4:k4=i; break; / 找出的笫4个因子赋给k4case 5:k5=i; break; / 找出的笫5个因子赋给k5case 6:k6=i; break; / 找出的笫6个因子赋给k6case 7:k7=i; break; / 找出的笫7个因子赋给k7case 8:k8=i; break; / 找出的笫8个因子赋给k8case 9:k9=i; break; / 找出的笫9个因子赋给k9case 10:k10=i; break; / 找出的笫10个因子赋给k10if (s=0) / s=0表示全部因子都已找到了couta is a 完数endl;cout1) coutk1,1表示a至少有2个因子if (n2) cout,2表示至少有3个因子，故应再输出一个因子if (n3) cout,3表示至少有4个因子，故应再输出一个因子if (n4) cout,5) cout,6) cout,7) cout,8) cout,9) cout,k10;coutendlendl;return 0;3.20题另一解#include using namespace std;int main()int m,s,i;for (m=2;m1000;m+)s=0;for (i=1;im;i+)if (m%i)=0) s=s+i;if(s=m)coutm is a完数endl;coutits factors are:;for (i=1;im;i+)if (m%i=0) couti ;coutendl;return 0;3.20题另一解#include using namespace std;int main()int k11;int i,a,n,s;for (a=2;a=1000;a+)n=0;s=a;for (i=1;ia;i+)if (a%i)=0)n+;s=s-i;kn=i; / 将找到的因子赋给k1k10if (s=0)couta is a 完数endl;coutits factors are:;for (i=1;in;i+)coutki ;coutknendl;return 0;3.21题#include using namespace std;int main()int i,t,n=20;double a=2,b=1,s=0;for (i=1;i=n;i+)s=s+a/b;t=a;a=a+b; / 将前一项分子与分母之和作为下一项的分子b=t; / 将前一项的分子作为下一项的分母coutsum=sendl;return 0;3.22题#include using namespace std;int main()int day,x1,x2;day=9;x2=1;while(day0)x1=(x2+1)*2; / 第1天的桃子数是第2天桃子数加1后的2倍x2=x1;day-;couttotal=x1endl;return 0;3.23题#include #include using namespace std;int main()float a,x0,x1;couta; / 输入a的值x0=a/2;x1=(x0+a/x0)/2;dox0=x1;x1=(x0+a/x0)/2;while(fabs(x0-x1)=1e-5);coutThe square root of a is x1endl;return 0;3.24题#include using namespace std;int main()int i,k;for (i=0;i=3;i+) / 输出上面4行*号for (k=0;k=2*i;k+)cout*; / 输出*号coutendl; /输出完一行*号后换行for (i=0;i=2;i+) / 输出下面3行*号for (k=0;k=4-2*i;k+)cout*; / 输出*号coutendl; / 输出完一行*号后换行return 0;3.25题#include using namespace std;int main()char i,j,k; /* i是a的对手;j是b的对手;k是c的对手*/for (i=X;i=Z;i+)for (j=X;j=Z;j+)if (i!=j)for (k=X;k=Z;k+)if (i!=k & j!=k)if (i!=X & k!=X & k!=Z)coutA-i B-j C-kendl;return 0;4.1题#include using namespace std;int main()int hcf(int,int);int lcd(int,int,int);int u,v,h,l;cinuv;h=hcf(u,v);coutH.C.F=hendl;l=lcd(u,v,h);coutL.C.D=lu)t=u;u=v;v=t;while (r=u%v)!=0)u=v;v=r;return(v);int lcd(int u,int v,int h)return(u*v/h);4.2题#include #include using namespace std;float x1,x2,disc,p,q;int main()void greater_than_zero(float,float);void equal_to_zero(float,float);void smaller_than_zero(float,float);float a,b,c;coutabc;disc=b*b-4*a*c;coutroot:0)greater_than_zero(a,b);coutx1=x1,x2=x2endl;else if (disc=0)equal_to_zero(a,b);coutx1=x1,x2=x2endl;elsesmaller_than_zero(a,b);coutx1=p+qiendl;coutx2=p-qi0时方程的根 */x1=(-b+sqrt(disc)/(2*a);x2=(-b-sqrt(disc)/(2*a);void equal_to_zero(float a,float b) /* 定义一个函数，用来求disc=0时方程的根 */x1=x2=(-b)/(2*a);void smaller_than_zero(float a,float b) /* 定义一个函数，用来求disc0时方程的根 */p=-b/(2*a);q=sqrt(-disc)/(2*a);4.3题#include using namespace std;int main()int prime(int); /* 函数原型声明 */int n;coutn;if (prime(n)coutn is a prime.endl;elsecoutn is not a prime.endl;return 0;int prime(int n)int flag=1,i;for (i=2;in/2 & flag=1;i+)if (n%i=0)flag=0;return(flag);4.4题#include using namespace std;int main()int fac(int);int a,b,c,sum=0;coutabc;sum=sum+fac(a)+fac(b)+fac(c);couta!+b!+c!=sumendl;return 0;int fac(int n)int f=1;for (int i=1;i=n;i+)f=f*i;return f;4.5题#include #include using namespace std;int main()double e(double);double x,sinh;coutx;sinh=(e(x)+e(-x)/2;coutsinh(x)=sinhendl;return 0;double e(double x)return exp(x);4.6题#include #include using namespace std;int main()double solut(double ,double ,double ,double );double a,b,c,d;coutabcd;coutx=solut(a,b,c,d)=1e-5);return(x);4.7题#include #include using namespace std;int main()void godbaha(int);int n;coutn;godbaha(n);return 0;void godbaha(int n)int prime(int);int a,b;for(a=3;a=n/2;a=a+2)if(prime(a)b=n-a;if (prime(b)coutn=a+bendl;int prime(int m)int i,k=sqrt(m);for(i=2;ik) return 1;else return 0;4.8题#include using namespace std;int main()int x,n;float p(int,int);coutnx;coutn=n,x=xendl;coutPn(x)=p(n,x)endl;return 0;float p(int n,int x)if (n=0)return(1);else if (n=1)return(x);elsereturn(2*n-1)*x*p(n-1),x)-(n-1)*p(n-2),x)/n);4.9题#include using namespace std;int main()void hanoi(int n,char one,char two,char three);int m;coutm;coutThe steps of moving m disks:endl;hanoi(m,A,B,C);return 0;void hanoi(int n,char one,char two,char three)/将n个盘从one座借助two座，移到three座void move(char x,char y);if(n=1) move(one,three);elsehanoi(n-1,one,three,two);move(one,three);hanoi(n-1,two,one,three);void move(char x,char y)coutxyendl;4.10题#include using namespace std;int main()void convert(int n);int number;coutnumber;coutoutput:endl;if (number0)cout-;number=-number;convert(number);coutendl;return 0;void convert(int n)int i;char c;if (i=n/10)!=0)convert(i);c=n%10+0;cout c;4.11题#include using namespace std;int main()int f(int);int n,s;coutn;s=f(n);coutThe result is sendl;return 0;int f(int n);if (n=1)return 1;elsereturn (n*n+f(n-1);4.12题#include #include using namespace std;#define S(a,b,c) (a+b+c)/2#define AREA(a,b,c) sqrt(S(a,b,c)*(S(a,b,c)-a)*(S(a,b,c)-b)*(S(a,b,c)-c)int main()float a,b,c;coutabc;if (a+bc & a+cb & b+ca)coutarea=AREA(a,b,c)endl;elsecoutIt is not a triangle!endl;return 0;4.14题#include using namespace std;/#define LETTER 1int main()char c;cinc;#if LETTERif(c=a & c=A & c=Z)c=c+32;#endifcoutcendl;return 0;4.15题#include using namespace std;#define CHANGE 1int main()char ch40;coutinput text:endl;gets(ch);#if (CHANGE)for (int i=0;i=a& chiA& chiZ)chi+=1;else if (chi=z|chi=Z)chi-=25;#endifcoutoutput:endlchendl;return 0;4.16题file#include using namespace std;int a;int main()extern int power(int);int b=3,c,d,m;coutenter an integer a and its power m:am;c=a*b;couta*b=cendl;d=power(m);couta*m=dendl;return 0;4.16题fileextern int a;int power(int n)int i,y=1;for(i=1;i=n;i+)y*=a;return y;5.1题#include #include using namespace std;#include int main()int i,j,n,a101;for (i=1;i=100;i+)ai=i;a1=0;for (i=2;isqrt(100);i+)for (j=i+1;j=100;j+)if(ai!=0 & aj!=0)if (aj%ai=0)aj=0; coutendl;for (i=1,n=0;i=100;i+)if (ai!=0)coutsetw(5)ai ;n+;if(n=10)coutendl;n=0;coutendl;return 0;5.2题#include using namespace std;/#include int main()int i,j,min,temp,a11;coutenter data:endl;for (i=1;i=10;i+)coutaiai; /输入10个数coutendlThe original numbers:endl;for (i=1;i=10;i+)coutai ; / 输出这10个数coutendl;for (i=1;i=9;i+) /以下8行是对10个数排序min=i;for (j=i+1;jaj) min=j;temp=ai; /以下3行将ai+1a10中最小者与ai 对换ai=amin;amin=temp;coutendlThe sorted numbers:endl;for (i=1;i=10;i+) / 输出已排好序的10个数coutai ;coutendl;return 0;5.3题#include using namespace std;int main()int a33,sum=0;int i,j;coutenter data:endl;for (i=0;