基于51单片机的五路抢答器.doc

实习(设计)报告姓 名 班 级 学 号 实习(设计)科目 基于51单片机的五路抢答器 实习(设计)地点 实习(设计)时间 电气工程及自动化学院school of electrical engineering & automation一 实验安排1. 设计一个八路抢答器。2. 必须有主持人按钮，当主持人按下按钮，开始30秒倒计时，这30秒内即是八位选手抢答的时长，若30秒内无人抢答，则视为所有选手弃权。3. 倘若主持人按下开始的30秒内有人抢答，定时到10秒，同时在一屏幕上显示该抢答选手号码，当主持人按下开始答题键时，则倒计时从10秒开始，同时选手号码清零。若10秒内无法回答，则该选手视为题目回答错误。/*五路抢答器c语言程序设计*/#include #define uchar unsigned char#define uint unsigned intsbit wela_hao=p30; /显示选手的数码管位选sbit wela1=p31;sbit wela2=p37;sbit qing=p35;sbit host=p36;sbit answer=p34;sbit key1=p10;sbit key2=p11;sbit key3=p12;sbit key4=p13;sbit key5=p14;uchar hao,shu,shi,ge,t0,start,flag;uchar code table=0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71;void init();/*初始函数申明*/void display(uchar shi,uchar ge,uchar hao);void delay(uint z);void keyscan();void main() init(); while(1) if(host=0)/主持人 delay(5); if(host=0) shu=30; hao=0; flag=1; start=1; delay(5); while(!host); if(qing=0)/清零 delay(5); if(qing=0) while(1) shu=0; shi=shu/10; ge=shu%10; tr0=0; delay(5); hao=0; wela1=0; wela2=0; wela_hao=0; delay(1); display(shi,ge,hao); if(host=0)break; delay(5); while(!qing); if(answer=0) /开始答题 delay(5); if(answer=0) flag=1; shu=10; start=1; hao=0; delay(5); while(!answer); if(flag=1) if(start=0) /选手按下，定时10秒 shu=10; shi=shu/10; ge=shu%10; wela1=0; wela2=0; wela_hao=0; delay(1);tr0=0; display(shi,ge,hao); delay(1); if(start=1) /主持人按下，倒计时30秒 wela1=1; wela2=1; wela_hao=1; delay(1); tr0=1; display(shi,ge,hao); delay(1);keyscan(); void init() /*初始化*/ t0=0; t1=0; shi=shu/10; ge=shu%10; flag=0; shu=30; wela_hao=1; hao=0; tmod=0x11; th0=(65536-50000)/256; tl0=(65536-50000)%256; ea=1; et0=1; tr0=0;void display(uchar shi,uchar ge,uchar hao) /*数码管动态扫描*/ wela1=1; wela2=0; p0=tablege; delay(5); wela2=1; wela1=0; p0=tableshi; delay(5); wela_hao=0; p2=tablehao; delay(5);void keyscan() /*按键扫描函数*/ if(key1=0) delay(5);if(key1=0) hao=1; p2=tablehao; start=0; delay(5); while(!key1); if(key2=0) delay(5);if(key2=0) hao=2; p2=tablehao; start=0; delay(5); while(!key2); if(key3=0) delay(5);if(key3=0) hao=3; p2=tablehao; start=0; delay(5); while(!key3); if(key4=0) delay(5);if(key4=0) hao=4; p2=tablehao; start=0; delay(5); while(!key4); if(key5=0) delay(5);if(key5=0) hao=5; p2=tablehao; start=0; delay(5); while(!key5); void delay(uint z) /*延时函数*/ uint x,y; for(x=z;x0;x-) for(y=110;y0;y-);void time0() interrupt 1 /*定时器0*/ th0=(65536-50000)/256; tl0=(65536-50000)%256; shi=shu/10; ge=shu%10; t0+; if(t0=20) t0=0; shu-; shi=s