旋转的led时钟.doc

电气工程及其自动化创新设计设计名称： 旋转 led 时钟班 级： 姓 名： 学 号： 指导老师： 设计时间：2009年9月2号8号茂名学院计算机与信息学院自动化系 旋转的时钟一、原理分析 旋转时钟利用了视觉暂留原理。用LED灯排成一列，取中间一点为圆心，他们围绕圆心旋转，最外侧的发光二极管显示时间刻度，当时针在12点时我们假设角度为0，则每个小时时针之间的角度为360/12=30.于是当这一列发光二极管每旋转30，最外侧的发光二极管就点亮一个瞬间一呈现时间刻度。这样，如果在0.1s内这列发光二极管能旋转完一圈，则人眼就会产生错觉，而把先后产生的时间刻度连成12个完整的时间刻度。明确系统功能 系统的功能比较清楚：电机带动一系列发光二极管绕轴旋转，单片机控制发光二极管在旋转过程中的相应位置上点亮以指示时间和刻度，与此同时，单片机内部进行时钟的计时操作，以控制旋转时钟显示正确的走时。这种利用机械的带动分时显示数据信息的方法叫做机械扫描显示。硬件设计 旋转时钟主要有两部分组成：电机部分和单片机控制发光二极管显示部分，在单片本制作品用单片机控制，具体电路原理图如下：软件编程因学的是（不懂汇编）这里只提供语言源程序，并限制为无遥控功能。也可提供带遥控功能的hex文件。#include sbit gate11=P30;sbit gate12=P31;#define unit unsigned int#define uchar unsigned charuchar data BUFFER=0,0,0,0,1,1,7;uchar data M=31,28,31,30,31,30,31,31,30,31,30,31;uchar code NUM1 =0x80,0x7F,0xC0,0xFF,0x40,0x90,0x40,0x8C, / -0-0x40,0x82,0xC0,0xFF,0x80,0x7F,0x00,0x00,0x00,0x00,0x00,0x81,0x80,0x81,0xC0,0xFF, / -1-0xC0,0xFF,0x00,0x80,0x00,0x80,0x00,0x00,0x80,0xE0,0xC0,0xF0,0x40,0x98,0x40,0x8C, / -2-0x40,0x86,0xC0,0xC3,0x80,0xC1,0x00,0x00,0x80,0x40,0xC0,0xC0,0x40,0x84,0x40,0x84, / -3-0x40,0x84,0xC0,0xFF,0x80,0x7B,0x00,0x00,0x00,0x0C,0x00,0x0E,0x00,0x0B,0x80,0x89, / -4-0xC0,0xFF,0xC0,0xFF,0x00,0x88,0x00,0x00,0xC0,0x47,0xC0,0xC7,0x40,0x84,0x40,0x84, / -5-0x40,0x8C,0x40,0xFC,0x40,0x78,0x00,0x00,0x00,0x7F,0x80,0xFF,0xC0,0x84,0x40,0x84, / -6-0x40,0x84,0x00,0xFC,0x00,0x78,0x00,0x00,0xC0,0x00,0xC0,0x00,0x40,0xF0,0x40,0xF8, / -7-0x40,0x0C,0xC0,0x07,0xC0,0x03,0x00,0x00,0x80,0x7B,0xC0,0xFF,0x40,0x84,0x40,0x84, / -8-0x40,0x84,0xC0,0xFF,0x80,0x7B,0x00,0x00,0x80,0x03,0xC0,0x87,0x40,0x84,0x40,0x84, / -9-0x40,0xC4,0xC0,0x7F,0x80,0x3F,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x63, / -:-0x00,0x63,0x00,0x00,0x00,0x00,0x00,0x00,;uchar code NUM2= 0x00,0x00,0x7f,0x80,0xff,0xc0,0x82,0x40, / -0- 0x8c,0x40,0x90,0x40,0xff,0xc0,0x7f,0x80, 0x00,0x00,0x00,0x00,0x20,0x40,0x60,0x40, / -1- 0xff,0xc0,0xff,0xc0,0x00,0x40,0x00,0x40, 0x00,0x00,0x41,0xc0,0xc3,0xc0,0x86,0x40, / -2- 0x8c,0x40,0x98,0x40,0xf0,0xc0,0x60,0xc0, 0x00,0x00,0x40,0x80,0xc0,0xc0,0x88,0x40, / -3- 0x88,0x40,0x88,0x40,0xff,0xc0,0x77,0x80, 0x00,0x00,0x0c,0x00,0x1c,0x00,0x34,0x00, / -4- 0x64,0x40,0xff,0xc0,0xff,0xc0,0x04,0x40, 0x00,0x00,0xf8,0x80,0xf8,0xc0,0x88,0x40, / -5- 0x88,0x40,0x8c,0x40,0x8f,0xc0,0x87,0x80, 0x00,0x00,0x3f,0x80,0x7f,0xc0,0xc8,0x40, / -6- 0x88,0x40,0x88,0x40,0x0f,0xc0,0x07,0x80, 0x00,0x00,0xc0,0x00,0xc0,0x00,0x83,0xc0, / -7- 0x87,0xc0,0x8c,0x00,0xf8,0x00,0xf0,0x00, 0x00,0x00,0x77,0x80,0xff,0xc0,0x88,0x40, / -8- 0x88,0x40,0x88,0x40,0xff,0xc0,0x77,0x80, 0x00,0x00,0x70,0x00,0xf8,0x40,0x88,0x40, / -9- 0x88,0x40,0x88,0xc0,0xff,0x80,0x7f,0x00, 0x00,0x00,0x00,0xc0,0x01,0x80,0x03,0x00, / -/- 0x06,0x00,0x0c,0x00,0x18,0x00,0x30,0x00,;unit disp1,disp2,key1,key2;unit ii,jj;unit i,sw,xz;void Delay(unit ms) ms=ms*3; while(-ms);void num_led(int kk, int tt)int jj;for(jj=0;jj201+xz) BUFFER0=0; BUFFER1=BUFFER1+1;if (BUFFER1=60) BUFFER1=0; BUFFER2=BUFFER2+1; if (BUFFER2=60) BUFFER2=0; BUFFER3=BUFFER3+1; if (BUFFER3=24) BUFFER3=0; BUFFER4=BUFFER4+1; if (BUFFER4MBUFFER5-1) BUFFER4=1; BUFFER5=BUFFER5+1; if (BUFFER512) BUFFER5=1; BUFFER6=BUFFER6+1; if(BUFFER699) BUFFER6=0; M1=M1-1; void intersvr0(void) interrupt 0sw=1;