2020年高中数学专题测试32复数的概念及运算(最新整理)

1、一、基础训练32 复数的概念及运算1. 若复数 z = 1+ ai （ a r ， i 为虚数单位）对应的点在第四象限，且| z |= 3 ，则 a =2. 已知复数 z1 = 3 + 4i ， z2 = m + i ，若 z1 + z2 是纯虚数，则实数 m =3. 若复数 z1 = 4 + 29i ， z2 = 6 + 9i ，其中i 是虚数单位，则复数(z1 - z2 )i 的实部为 i - 24. 设复数 z =1+ i，则 z =5（2011 上海卷）已知复数 z1 满足(z1 - 2) (1+ i) = 1- i （ i 为虚数单位），复数 z2 的虚部为 2， z1 z2 是实数

2、，则 z2 =z6. 设复数 z = 3 + i ，则复数对应点的坐标是1+ i17. 设复数2 + i 与在复平面上的对应点分别是点 a ， b ，则aob =3 + i(1- 3i)23 + i8. 已知复数 z =， z 是 z 的共轭复数，则 z z =二、例题精讲例 1设复数 z1 = 2 + ai （其中 a r ）， z2 = 3 - 4i （1）若 z + z 是实数，求 z z 的值；（2）若 z1 是纯虚数，求| z | z121 212例 2已知复数 z = 1+ i ，求实数 a, b 使 az + 2bz = (a + 2z)2 例 3已知复数 z 满足| z + 2

3、 - 2i |= 1，求| z - 2 - 2i | 的最小值例 4设 z 为虚数，w= z +1 为实数，且-1 w 0 ， b 0 ），且3z2 + z2 = 0 ，求 z122和 z2 121“”“”at the end, xiao bian gives you a passage. minand once said, people who learn to learn are very happy people. in every wonderful life, learning is an eternal theme. as a professional clerical and t

4、eaching position, i understand the importance of continuous learning, life is diligent, nothing can be gained, only continuous learning can achieve better self. only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace of enterprise development and innovate to meet the needs of the market. this document is also edited by my studio professionals, there may be e