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1、阅读使人充实,会谈使人敏捷,写作使人精确。培根微观计量经济学模型( Model of Microeconometrics)1.1 Generalized Linear Mod elsThree aspects of the lin ear regressi on model for a con diti on ally no rmallydistributed resp onse y are:(1)The linear predictor i xT - through which 二 E(yi|xj.2(2) yi | Xi is N (叫,二)(3) iGLMs: extends (2)an
2、d(3) to more general families of distributions for y.Specifically, y | x may follow a density:f (y;日冲)=expt y日+ c(y;$)二:canonical parameter, depends on the linear predictor.:dispersion parameter, is often known.Also i and 叫 are related by a monotonic transformation,g(m iCalled the link fun ction of
3、the GLM.Selected GLM families and their canonical linkFamilyCanonical linkNamebi no miallog(曰(1 一巴)logitgaussia nide ntitypoiss onlog卩log1.2 Binary Depend ent VariablesModel:E(% |人)=Pi =F(x),i =1,2,nIn the probit case: f equals the standard normal CDFIn the logit case: F equals the logistic CDFExamp
4、le:DataConsidering female labor participation for a sample of 872 women fromSwitzerla nd.The depe ndent variable: participati onThe expla in variables:in come,age,educatio n,youn gkids,oldkids,foreig ny esa ndageH.R:library(AER)data(SwissLabor)summary(SwissLabor)participation no :471 yes:401incomeMi
5、n. : 7.187 1st Qu.:10.472ageMin. :2.0001st Qu.:3.200educationMin. : 1.0001st Qu.: 8.000youngkidsMin. :0.00001st Qu.:0.0000Median :0.0000Median :10.643Mean :10.6863rd Qu.:10.887Max. :12.376 oldkidsMin. :0.00001st Qu.:0.0000Median :1.0000Median :3.900Mean :3.9963rd Qu.:4.800Max. :6.200 foreign no :656
6、 yes:216Median : 9.000Mean : 9.307 3rd Qu.:12.000 Max. :21.000Mean :0.3119Mean :0.98283rd Qu.:0.0000Max. :3.00003rd Qu.:2.0000Max. :6.0000(2) EstimationR:swiss_prob=glm(participatio n.+l(ageA2),data=SwissLabor,family=bi no mial(li nk=pro bit)summary(swiss_prob)Call:glm(formula = participatio n . + I
7、(ageA2), family = bi no mial(li nk = probit),data = SwissLabor)Deviance Residuals:Min1Q Median3Q Max-1.9191 -0.9695 -0.4792 1.0209 2.4803Coefficients:Estimate Std. Error z value Pr(|z|)(Intercept) 3.749091.406952.665 0.00771 *income-0.666940.13196-5.054 4.33e-07 *age2.075300.405445.119 3.08e-07 *edu
8、cation0.019200.017931.071 0.28428youngkids-0.714490.10039-7.117 1.10e-12 *oldkids-0.146980.05089-2.888 0.00387 *foreignyes0.714370.121335.888 3.92e-09 *I(ageA2)-0.294340.04995-5.893 3.79e-09 *学冋是异常珍贵的东西,从任何源泉吸收都不可耻。阿卜日法拉兹阅读使人充实,会谈使人敏捷,写作使人精确。培根6学冋是异常珍贵的东西,从任何源泉吸收都不可耻。阿卜日法拉兹Signif. codes: 0 * 0.001 *
9、 0.01 *0.05. 0.1 1(Dispersio n parameter for bi no mial family take n to be 1)Null devia nee: 1203.2 on 871 degrees of freedomResidual devia nee: 1017.2 on 864 degrees of freedomAIC: 1033.2Number of Fisher Seoring iterations: 4(3) VisualizationPlott ing partieipatio n versus ageR:plot(partieipati on
10、 age,data=SwissLabor,ylevels=2:1)oQUscda4e g a阅读使人充实,会谈使人敏捷,写作使人精确。培根(x)(4) Effects:Xj学冋是异常珍贵的东西,从任何源泉吸收都不可耻。阿卜日法拉兹(x)rAverage margi nal effects:The average of the sample marg inal effects:R:fav=mea n(d no rm(predict(swiss_prob,type=li nk) fav*coef(swiss_prob)(In tercept)in comeageeducati onyoun gki
11、dsoldkidsforeig nyesI(ageA2)The average marginal effects at the average regressor:Rav=colMea ns(SwissLabor,-c(1,7)av=data.frame(rbi nd(swiss=av,foreig n=av),foreig n=factor(c( no,yes|) av=predict(swiss_prob, newdata=av,type=li nk)av=d no rm(av)avswiss*coef(swiss_prob)-7avforeig n*coef(swiss_prob)-7s
12、wiss:(In tercept)in comeage educati on youn gkidsoldkids I(ageA2)阅读使人充实,会谈使人敏捷,写作使人精确。培根Foreig n:(In tercept)in comeageeducati onyoun gkidsoldkidsI(ageA2)(5) Goodness of fit and predictionPseudo-R2:R2=1C)(?) as the log-likelihood for the fitted model, 0 )( ?) as the log-likelihood for the model cont
13、aining only a constant term.R:swiss_prob0=update(swiss_prob,formula=.1)1- as.vector(logLik(swiss_prob)/logLik(swiss_prob0) 1 0.1546416Perce nt correctly predicted:R:table(true=SwissLabor$participatio n,pred=ro un d(fitted(swiss_prob)predtrue01no337134yes14625567.89%ROC curve:TPR(c):the nu mber of wo
14、me n participati ng in the labor force that areclassified as participat ing compared with the total nu mber of wome n participati ng.FPR(c):the nu mber of wome n not participati ng in the labor force that are classified as participat ing compared with the total nu mber of wome n not participati ng.R
15、:lbrary(ROCR)pred=predictio n(fitted(swiss_prob),SwissLabor$participatio n)plot(performa nce(pred,acc)plot(performa nce(pred,tpr,fpr)ablin e(0,1,lty=2)Cutoff010s.oi ggo A 昌nCJov0.0O0.00.8False positive rate1.0QLIcoogo寸ofo 欝cltAESUdCItnHExtensions: Multinomial responsesFor illustrat ing the
16、most basic vers ion of the mult ino mial logit model, a model with only in dividual-specific covariates,.data(Ba nkWages)It contains, for employees of a US bank, an ordered factor job with levelscustodial, admin(for administration), and manage (forman ageme nt), to be modeled as afun cti on of educa
17、ti on (in years) and a factor min ority in dicati ng mi no rity status. There also exists a factor gender, but since there are no women in the category custodial, only a subset of the data corresponding to males is used for parametric modeling below.summary(BankWages)job education gender minority cu
18、stodial: 27 Min. : 8.00 male :258 no :370 admin :363 1st Qu.:12.00 female:216 yes:104 manage : 84 Median :12.00Mean :13.493rd Qu.:15.00 Max. :21.00summary(BankWages) edcat - factor(BankWages$education) edcat levels(edcat)3:10 - rep(c(14-15, 16-18, 19-21), + c(2, 3, 3) head(edcat)tab - xtabs( edcat +
19、 job, data = BankWages) head(tab) prop.table(tab, 1) head(BankWages)library(nnet) bank_mn2 |z|)(Intercept)0.2649934 0.0937222 2.8274 0.004692 *quality0.4717259 0.0170905 27.6016 2.2e-16 *skiyes0.4182137 0.0571902 7.3127 2.619e-13 *income-0.1113232 0.0195884 -5.6831 1.323e-08 *userfeeyes0.8981653 0.0
20、789851 11.3713 2.2e-16 *costC-0.0034297 0.0031178 -1.1001 0.271309costS-0.0425364 0.0016703 -25.4667 2.2e-16 *costH0.0361336 0.0027096 13.3353 0 and underdispersion to a 0.Com mon specificati ons of the tran sformatio n fun cti on h are h( 2 or卩)= 卩h( ) = . The former corresponds to a negative binom
21、ial (NB) model (seebelow) with quadratic variance function (called NB2 by Cameron andTrivedi 1998), the latter to an NB model with linear variance function(called NB1 by Cameron and Trivedi 1998). In the statistical literature,the reparameterizationVar(yi|xi) = (1 + a) 卩 i = dispersion of the NB1 mo
22、del is often called a quasi-Poisson model with dispersion parameter.R: dispersiontest(rd_pois)Overdispersion test data: rd_pois z = 2.4116, p-value = 0.007941 alternative hypothesis: true dispersion is greater than 1 sample estimates: dispersion6.5658R:dispersiontest(rd_pois, trafo = 2) Overdispersi
23、on testdata: rd_pois z = 2.9381, p-value = 0.001651 alternative hypothesis: true alpha is greater than 0 sample estimates:alpha 1.316051Both suggest that the Poisson model for the trips data is not wellspecified.One possible remedy is to consider a more flexible distribution that does not impose equ
24、ality of mean and variance.The most widely used distribution in this context is the negative binomial. It may be considered a mixture distribution arising from a Poisson distribution with random scale, the latter following a gamma distribution. Its probability mass function isR: library(MASS)rd_nb -
25、 glm.nb(trips ., data = RecreationDemand)coeftest(rd_nb)0.05 . 0.1z test of coefficients:quality0.72199900.040116517.9976 2.2e-16 *skiyes0.61213880.15030294.0727 4.647e-05 *income-0.02605880.0424527-0.6138 0.53933userfeeyes0.66916760.35302111.8955 0.05802 .costC0.04800870.00918485.2270 1.723e-07 *co
26、stS-0.09269100.0066534 -13.9314 |z|)(Intercept) -1.1219363 0.2143029 -5.2353 1.647e-07 *Signif. codes: 0 * 0.001* 0.01R:logLik(rd_nb)log Lik. -825.5576 (df=9)0 1 2 3 4 5 6 7 8 9学问是异常珍贵的东西,从任何源泉吸收都不可耻。阿卜 日 法拉兹阅读使人充实,会谈使人敏捷,写作使人精确。培根obs 417 68 38 34 17 13 11 2 8 1exp 370 87 37 26 21 17 14 11 9 8(4) Ze
27、ro-inflated Poisson and negative binomial modelsrbind(obs = table(RecreationDemand$trips)1:10, exp = round(+ sapply(0:9, function(x) sum(dpois(x, fitted(rd_pois)01 23456 78 9obs 41768 3834171311 281exp 277 146 68 41 30 23 17 13 1 0 7One such model is the zero-inflated Poisson (ZIP) model (Lambert 19
28、92), which suggests a mixture specification with a Poisson count component and an additional point mass at zero. With AI(y) denoting the indicator function, the basic idea isfzeroinfl (y) = Pi 1 0 (y) + (1 - Pi) fcount(y; ),we consider a regression of trips on all further variables for the count part (using a negative binomial distribution) and model the inflation Part as a function of quality and income:library(pscl)rd_zinb = zeroinfl(trips . | quality + income, data=RecreationDemand, dist=negbin) summary(rd_zinb )Call:ze
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