用两个74HC164驱动两个四位的数码管

1、用两个74HC164 驱动两个四位的数码管 （一个简易电子钟） 2 / 111 / 11 几天前我发一了帖寻求用两74HC164做动态扫描数码管今天我折腾了一天终于把它难 弄出来了 其电路图是在一本书上找到的由于还没学会用protel 99画图，所以就只有将就一下了 我的程序如下: #i nclude sbit DAT=P1A1; sbit CLK=P1A2; unsigned char code tab=0 x3f,0 x06,0 x5b,0 x4f,0 x66,0 x6d,0 x7d,0 x07,0 x7f,0 x6f,0 x40; 显示09 unsignedchar code ff=0

2、xfe,0 xfd,0 xfb,0 xf7,0 xef,0 xdf,0 xbf,0 x77;位选； unsigned char a,b,c,d,e,f,ch,hour,minite,second; 开启计时 void loading() TMOD=Ox22; TR0=1; ET0=1; EA=1; 以下是显示程序，共八个，因为有八个数码管 void sendbyte(unsignedchar byte) unsigned char num,c; num=tabbyte; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num=Oxfe; for(c=0;c8;c+)

3、CLK=O; DAT=num; CLK=1; num =1; void sendbyte_1(unsigned char byte) unsigned char num,c; num=tabbyte; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; num=0 xfd; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; 4 / 114 / 11 void sendbyte_2(unsigned char byte) unsigned char num,c; num=tabbyte; for(c=0;c8;c+)

4、CLK=0; DAT=num CLK=1; num =1; num=0 xfb; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; void sendbyte_3(unsignedchar byte) unsigned char num,c; num=tabbyte; for(c=0;c8;c+) DAT=num CLK=1; num =1; num=0 xf7; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; void sendbyte_4(unsignedchar byte) unsigned char nu

5、m,c; num=tabbyte; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; num=0 xef; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; void sendbyte_5(unsignedchar byte) unsigned char num,c; num=tabbyte; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; num=0 xdf; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; void sendby

6、te_6(unsignedchar byte) unsigned char num,c; num=tabbyte; for(c=0;c8;c+) CLK=O; DAT=num CLK=1; num =1; num=0 xbf; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; void sendbyte_7(unsignedchar byte) unsigned char num,c; num=tabbyte; for(c=0;c8;c+) CLK=0; DAT=num CLK=1; num =1; num=0 x7f; for(c=0;c8;c+) C

7、LK=O; DAT=num CLK=1; num =1; /延时 void delay() unsigned int j; for(j=0;j250;j+) main () load in g(); while(1) a=hour/10; b=hour%10; c=mi nite/10;d=mi ni te%10; e=sec on d/10;f=sec on d%10; ch=10; sen dbyte(f); delay(); sen dbyte_1(e); delay(); 9 / 111 / 11 sen dbyte_2(ch); delay(); sen dbyte_3(d); delay(); sen dbyte_4(c); delay(); sen dbyte_5(ch); delay(); sen dbyte_6(b); delay(); sen dbyte_7(a); delay(); void time(void) interrupt 1 unsigned int tt; tt+; if(tt=3600) tt=0; second+; if(sec on d=60) se