母线铜排载流量计算方法

1、母线铜排载流量和重量计算方法估算法 : 1、铜排重量二长x宽x厚度x铜密度 8932kg/m32、单条铜母排载流量= 宽度 (mm) x 厚度系数双母排载流量= 宽度 (mm) x 厚度系数 x 1.5( 经验系数 )铜排和铝排也可以按平方数来, 通常铜应该按5-8a/ 平方 ,铝应该按 3-5a/ 平方常用铜排的载流量计算方法：40 时铜排载流量=排宽 *厚度系数排宽(mm);厚度系数为：母排12厚时为20;10厚时为18;依次为:12-20 , 10 -18 , 8-16, 6-14, 5-13, 4-12.双层铜排 40=1.56-1.58 单层铜排 40 (根据截面大小定)3 层铜排

2、40 =2 单层铜排 40 4 层铜排 40 = 单层铜排 40 *2.45( 不推荐此类选择 , 最好用异形母排替代 )铜排 40 = 铜排 25 *0.85铝排 40 = 铜排 40 /1.3例如求tmy100*1瞰流量为：单层：100*18 8 =1800(a)查手册为 1860a;双层:2(tmy100*10)的载流量为：1860*1.58=2940(a);查手册为 2942a;三层：3(tmy100*10)的载流量为：1860*2 = 3720(a)查手册为 3780a以上所有计算均精确到与手册数据相当接近常用铜排的尺寸及载流量表铜母排截面25 35 平放 (a)竖放 (a)平放 (

3、a)竖放 (a)15x317618520x323324525x328530030x439441540x440442552255040x545247555158850x555658572176050x661765079784060x673177094099060x88589001101116060 x 1096010101230129580x693010101195130080x8106011551361148080x 101190129515311665100x61160126015571592100x81310142516741850100x 101470159518652025120x81

4、530167519402110120x 1016851830215223402(60 x 6)11261185145215302 (60 x 8)14601480150316002(60 10)16801170214022502(80 6)13201433170518552(80 8)16511795211725152(80 10)19502120257527352(100 6)15641700200021702(100 8)19302100247026902(100 10)23202500293531852(120 8)21402330275029952(120 10)26152840333

5、03620税计算后母畿的阻扰度相保阻抗列丁，表！费乐器母线规珞心二大%d=150d=2500=350do=2o。do-200do=1600容坦mmm il-mm u/mm i? .mm u ;mm n !mttl ll.md-250d=350d15okvatmylmytmyr llmytmyorlmytmyarlmytmyorlmytmyorlmytmyorlm0.526=69.432(kvar ) 4 y+ u6 s6 x2 t, o. w1 g( f& q, f2 o! t% d- x- n% f; f; q% _无功补偿容量计算系数表当前功率因目标功率因数：cos。20.80+ r4 a

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18、8570.9050.9661.108,t4 a0 m6* i7 d( n!v/ o8 - n,i( u8 o ld! w- i7f$ |& p, ec# q+ cu- c% be/ u# g+ _c8 f1.0780.680.3280.4590.5940.6230.6520.6830.7150.7500.7870.8280.8750.936& a f2& x6 u1 v* 8 v-$ w9 o a+ g7 # a% z;$ # o) g1:k1 f: a; !e$ a1 _:n2 x# n+ ay+ x m% qp; k8 xu# l; u; o+ n# 7w0.2990.4290.5650.

19、5930.6540.6860.7200.7570.8460.694 l( r$ _, 20.623! z# c: %,i* , h%;n. n70.7989 o+ n+ b& z30.9071.049,c3 t* d! c7.w; i! k2% x: - z3g5 a/ j( d10 e3 + c4 6 bx8 m f* d*r$ 7 _: am9 + n8 k,g% w+ 3k4 - d7 or) - s, d8 ?fg, # _ aq$ |7 qe- hq3 i/ s zo9 u. aq# r( g5 o0.700.2700.4000.5360.5650.5940.6250.6571.24

20、70.7290.7700.8170.8781.020,a( x |6 a. 3!t4 m( r79 n( b. f7* m- a( p6m5 j! _8 h7 - g$ dv. r) i6 m5gx d: a1 l i0.2420.71& r3 4 i$ x95 |5 x5 2 m& h2 - j0 g0.3720.5080.536f% m d4 0.566n$ f5 a2b t( m0.597c q) ln ? j) s1e) j& ?! h0.6290.6630.7000.7410.789* m, n0 p&/ 4 s2 |$ w6a4 c6 n, a 7 d; r% f6 yb, e;

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27、.7760.80-6 p7 t8 o: h# b;- l+ 2 w f;l! p n, mj6 i6 h w! i0.130八)e5 a* eh2 q, (3 x; r0.2660.3240.2945 j; e/ a8k% w( r&i0.3550.387,m# |; m0l# g a6 x10.4216 z- p2 x) f9k3 o7 x7 i0.458:?- o90.4990.547d6 # d n.n) g& h0.608% j8 z$ i( l,j& o8 x4 n0.7500.81-0.1040.2400.2680.2980.3290.3610.3950.4320.4730.521

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35、x7a6 b* b*y$ z0.0937 / t+ o%9 s9 q# n!m9 w0.1278 q# o6 y9p/ c z6 e-y z0.1641 n: j* e7 k:r6 t; :y9 ?( |0.2054 2 f6 j9$ u; c0.2533 e4 + e/ u2 k0.3137 q+ 16 e; o, _4 6 w .m0.456-0.4260.92-% a, t+ m& _30.0310.0630.0970.1340.1750.2230.284/ b9 y-t3 y9 h8 17 n7十 八+ y6b$ + a-k4 v. j: a23 l- 9 k9 |(:r; r- j:$ i) v e$ o, n( b( n/ q4t8 1 7 ae2 - #g+ z 1r7 i k ah qlu. l7 y