ANSYS动力学分析的几个入门例子

1、问题一：悬臂梁受重力作用发生大变形，求其固有频率。基本过程：1、建模2、静力分析NLGEOM,ONSTRES,ON3、求静力解4 、开始新的求解： modalSTRES,ONUPCOORD,1,ON 修正坐标SOLVE.5、扩展模态解6、察看结果 /PREP7ET,1,BEAM189 ! 使用 beam189 梁单元 MPTEMP,MPTEMP,1,0MPDATA,EX,1,210e9MPDATA,PRXY,1,0.3MPDATA,DENS,1,7850SECTYPE, 1, BEAM, RECT, secA, 0! 定义梁截面 secASECOFFSET, CENTSECDATA,0.005

2、,0.01,0,0,0,0,0,0,0,0K, ,! 建模与分网K, ,2,K, ,2,1,LSTR, 1, 2LATT,1, ,1, ,3, ,1LESIZE,1, , ,20, , , , ,1LMESH, 1FINISH/SOL!静力大变形求解ANTYPE,0NLGEOM,1PSTRES,ON! 计及预应力效果DK,1, , , ,0,ALL, , , , , ,ACEL,0,9.8,0,! 只考虑重力作用TIME,1AUTOTS,1NSUBST,20, , ,1KBC,0SOLVEFINISH/SOLUTIONANTYPE,2MSAVE,0MODOPT,LANB,10MXPAND,10

3、, , ,0PSTRES,1MODOPT,LANB,10,0,0, ,OFFUPCOORD,1,ONPSOLVE,TRIANGPSOLVE,EIGLANBFINISH/SOLUEXPASS,1PSOLVE,EIGEXPFINISH!进行模态求解!取前十阶模态!打开预应力效应!修正坐标以得到正确的应力!三角化矩阵!提取特征值和特征向量!扩展模态解/POST1SET,LISTFINISH!观察结果secAg=9. 8id/s2问题二：循环对称结构模态分析这是ANSYS HELP里的例子，但那个命令流似乎有些问题，下面是整理过的命令流。基本过程:1、建模2、define cyclic3、定义约束4、

4、求模态解5、展开并察看结果r1=5r2=10d1=2nsect=24alpha_deg=360/nsect alpha_rad=2*acos(-1)/nsect/prep7csys,1k,1,0,0,0k,2,0,0,d1k,3,r1,0,0k,4,r1,0,d1l,3,4arotat,1,1,2,alpha_deg/2k,7,r2,0,0k,8,r2,0,d1l,7,8arotat,5,1,2,alpha_deg/2 arotat,2,1,2,alpha_deg/2 arotat,6,1,2,alpha_deg/2 a,5,6,10,9mshkey,1et,1,181r,1,0.20r,2,

5、0.1mp,ex,1,10e6mp,prxy,1,0.3mp,dens,1,1e-4esize,0.5asel,1,4aatt,1asel,5aatt,2allselCYCLIC, , , ,CYCLICAMESH,all! 建模!定义基本扇区!分网FINISH/PREP7! 建模ANTYPE,2MODOPT,LANB,10MXPAND,10, , ,0PSTRES,0MODOPT,LANB,10,0,0, ,OFFDK,5, , , ,0,U Z,SOLVEFINISH/POST1SET,LISTSET, , ,1, , , ,4,/CYCEXPAND, ,ON!观察扩展模态PLNS,U,S

6、UMFINISHIKjlLiANM* LC M44ITIF1AS ynTEO-MC-vrai uwiLsn4MeTtlr 鼻*亚.E,求结构响应10N，频率范围 5Hz70Hz问题三：三角平台受谐波载荷作用谐波载荷为作用在平台上面一点的集中力，幅值为 基本过程：1、建模2. 求模态解3、用模态叠加法作谐分析4. 观察结果ET,1,BEAM189ET,2,SHELL93R,1,0.01, , , , , ,MP,EX,1,210e9MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE, 1, BEAM, RECT , secA, 0SECOFFSET, CENT SECDATA,

7、0.005,0.008,0,0,0,0,0,0,0,0 K, ,-0.5,K, ,0.5,K, ,1,K, ,1,1,K, ,-0.5,1,K, ,0.5,1,K, ,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1, ,7, ,1LSEL, , , ,ALLLESIZE,ALL, , ,10, , , , ,1LMESH,4,6TYPE, 2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOL ! 为了使用模态叠加法谐分析ANTYPE,2MODOPT,LANB,20 ! 先取结构前 20 阶模态MXP

8、AND,20, , ,0MODOPT,LANB,20,0,0, ,OFFKSEL,S,KP,1,3DK,ALL, , , ,0,ALL, , , , , ,SOLVEFINISH!/POST1! 最好事先看一下模态结果!SET,LISTFINISH!以了解模态频率范围/SOLANTYPE,3 HROPT,MSUPHROUT,ON HROPT,MSUP,20, HROUT,ON,OFF,0F,177,FY,-10,HARFRQ,5,70,NSUBST,200,KBC,1ALPHAD,5, SOLVEFINISH/POST26FILE,rfrqNUMVAR,20 NSOL,2,139,U,Y ,P

9、LVAR,2FINISH!模态叠加法谐响应分析!施加10N的力在节点177的负丫方向!载荷的强制频率范围!察看位移响应0VALU世. 1 *rrt r 41. EJX.A00J*LS451ftCl问题四：三角平台受一地震谱激励，求应力分布和支反力基本过程：1、建模2、求模态解3、求谱解4、扩展模态5、模态合并6、观察结果/PREP7! 建模ET,1,BEAM189ET,2,SHELL93R,1,0.01, , , , , ,MP,EX,1,210e9MP,PRXY,1,0.3 MP,DENS,1,7850SECTYPE, 1, BEAM, RECT , secA, 0 SECOFFSET, C

10、ENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K, ,-0.5,K, ,0.5,K, ,1,K, ,1,1,K, ,-0.5,1,K, ,0.5,1,K, ,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1, ,7, ,1LSEL, , , ,ALLLESIZE,ALL, , ,10, , , , ,1LMESH,4,6TYPE, 2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOL ! 取前十阶模态ANTYPE,2MODOPT,LANB,10KSEL,S,KP,1,3D

11、K,ALL, , , ,0,ALL, , , , , ,SOLVEFINISH/SOL ! 谱分析ANTYPE,8SPOPT,SPRS,10,1SVTYP,3SED,0,1,0,! 给出激励方向FREQ,0.25,1.34,6.73,14.6,28.9,0,0,0,0! 激励谱SV,0,0.00073,0.00016,0.00034,0.00034,0.00052,SOLVEFINISH/SOL ! 扩展模态ANTYPE,2EXPASS,1MXPAND,10,0,0,1,0.001,SOLVEFINISH/SOL ! 模态合并ANTYPE,8SRSS,0.001,DISPSOLVE/POST1

12、 ! 观察结果SET,LIST/INPUT ,mcomPRRSOL,FFINISH，如7问题五：三角平台受时程载荷作用，求应力分布和变形过程基本过程：1、建模2. 施加随时间变化载荷，定义载荷步3、求解4. 在P0ST1和POST26中观察结果/PREP7!建模ET,1,BEAM189ET,2,SHELL93R,1,0.01,MP,EX,1,210e9MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE, 1, BEAM, RECT, secA, 0SECOFFSET, CENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K, ,-0.5,K, ,0.

13、5,K, ,1,K, ,1,1,K, ,-0.5,1,K, ,0.5,1,K, ,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR, 2, 6 LSEL,S,LINE,4,6 LATT,1,1,1, , 7, ,1LSEL, , , ,ALL LESIZE,ALL, , ,10, , , , ,1LMESH,4,6TYPE, 2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOLANTYPE,4TRNOPT,FULLKSEL,S,KP,1,3 DK,ALL, , , ,0,ALL, , , , , ,OUTRES,ALL,1 ALPHAD,5,TIME,2AUTOTS,1NSUBST,50, , ,1KBC,0 SFA,AL