悬臂梁ansys有限元分析求最大挠度

1、悬臂梁ansys有限元分析求最大 挠度(一)悬臂梁ansys有限元分析求最大挠度问题：悬臂梁长1000mm,宽50mm,高10mm左端固定，求其在自重作用下的最大挠度?解：弯矩方程：微分方程：EIzy=iq(l-x)2积分求解:弘“2W宀“宀非4+c+dELy =O.5ql2x-O.5qlx2 +qx3+C由边界条件：x = 0, 0A = yA = 0;儿=0 得：C=0 9D=0SEJ1=I=l/12*23*b，h为梁截面的高,b为梁截面的宽。q= p *g*a*h*l材料力学公式求：Y= p =5733mmSEIANSYS模拟求：Y=5. 5392mm,详细见下步ANSYS软件设置及其具

2、体过程如下:步骤1：建立一个模型，在model下creat 一个长1,宽0. 05,高0. 01的长方体实体。（单位默认为m）rial Propsons slingateKeypointsLinesAreas VolumesEJ Arbitrary 曰 BlockJ5 By 2 Comers & Z 沪 By Centr.Comr.Z g Jrjmnrg 田 Cylinder步骤2：材料属性设置。密度：7800,杨氏模量：2E11,泊| c= if S松比0.3。/ Define Material Model Behavior Material Edit Favorite HelpMateri

3、al Models DefinedMaterial Models AvailableMaterial Model Number 1jJM Favorites Structural 卷 Jnear卷 Elastic金 OrthotropicIsotropic金 ArtisotropicA linear kotropic Properties or Material Number 1Linear Isotropic Material Properties for Material Number 1 T1TemperaturesEX|2E11PRXY0.3Material Edit Favorite

4、 TdpMaterial Models Definedaterial Model Number 1 Lirear lso:ropiciwi FavoritesA Dersity for Material Number 1渗 S:ructural渗 Linear矗 SlastDensity for Material Number 1T1Temperatures嗣 NonlinearDENS Thermal E 血 Damping金匚f；厂*；c尸rf “1Add Temperature | Delete Tcmpcoturu |Material Models Available步骤3：划分网格。

5、设置网格单元为structure solid brick8node 185, mesh tool 中设网格大小为0. 002, HEX下点击 meshoA Library of Element TypesS3Library of Elemenl TypesStructural Mass Link BeamAi-har 4node 25Snode 83 3dck Snode 45J1PipeSnode 185|Solid20nodc 186ShellVSnode 185Element type refererce number1OKAoplyCancelHelp |Element Attribu

6、tes:| Global3 Set厂 Smart SizeJJFine6CoarseSi2e Controls:GlobalSetClear 1AreasSet |Clear 1LinesSet |Clear 1Copy |Flip |LayerSet |Cle刮 |KeyptsSet |Clear |炳駁h： | Volume?三Shape: C Tet Q Hex孑 Mapped - Swe即| 3 or 4 $idedMe$h步骤4：施加载荷；在preprocessor中inertia中设置重力加速度Y方向为9. 8o在左面施加固定约束（三个方向固定）alysis Type t Sol

7、n Optn fine LoadsSettings Apply O StructuralEl凶 田曰Displaceme Forco/Mom Pressure Temporatur Inertia ffl Angular El Angular同 Coriolis Effects Gravityloba固&Sections Modeling Meshing Checking Ctrls Numbering Ctrls Archive Model Coupling / Ceqn FLOTRAN Set Up Multi-field Set Up Loads 田 Analysis Type 园 Fa

8、st Sol n Optn Define Loads0 Settings日 Apply Structural Displacement歹 On Linesn Area刀 On Keypoints 莎 On Nodes園 On Components 旨 Inertia Relief步骤 5:：求解。在 solve 下 solve current LS。 SolutionE Analysis TypeE Dcfino LoadsS Load Step Opts田 SE Management 9800BO.WWWNOPRINTOUTDfiTAIMSE OUTPUT CONTROLSALL DATA

9、WRITTENFOR THE LAST SUBSTEPformed Sha步骤6：后处理查看。在result中plot result,查看nodesdisplacemento List查看文本，观察nodes的最大位移点。PreferencesI PreprocessorI SolutionI General Postproc E Data & File Opts 胃 Results Summary E) Road Results田 Failure CriteriaB Plot Results Contour Plot Vector PlotEl Plot Path Item Concrete

10、 Plot ThinFilmB List ResultsNODAL SOLUTIONSTEP=1SUB =1TIME=1U3UM(AVG)RSYS=0DMX =.0055393MX =.005539ANSYSSEP 9 201218:26:46.001231.002462.003693.004924.615E-03.001846.003077.004300p 丄乙 j 乙丄 jcurmu乙匕.么rrjLje丄巳.03 tJ7 XLU 乙.00553914043-0.12321E-04-0.55097E-020.85716E-100.55097E-0214044-0.12321E-04-0550

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