C语言程式解答.

1、C 語言程式解答1.印出18的階乘值如1!=1,2!=2,3!=6,#include <stdio.h>#include<stdlib.h> int main() int k,i;long s;long fac(int n);for(i=1;i<=8;i+)printf("Enter an non-negative integer :"); scanf("%d",&k);s = fac(k);printf("%d! = %1dn",k,s);system("pause");lo

2、ng fac(int n)2.if(n<=1)return 1L; return n*fac(n-1);利用迴圈設計出下列數字圖案12 13 2 14 3 2 15 4 3 2 16 5 4 3 2 17 6 5 4 3 2 18 7 6 5 4 3 2 19 8 7 6 5 4 3 2 1 #include <stdio.h>#include<stdlib.h> int main() int i,j;for(i=1;i<=9;i+)for(j=i;j>=1;j-) printf("%d", j);printf("n&qu

3、ot;);system("pause");3. 計算1+2+3+4+10之和#include <stdio.h>#include<stdlib.h> int main() int k,s;int sum(int n);printf("input k:"); scanf("%d",&k); s = sum(k);printf("1+2+.+%d=%dn",k,s);system("pause");int sum(int n)int i,total=0;for(i=1

4、;i<=n;i+) total+=i;return total;4. 列出九九乘法表如 1x1=1,1x2=2,1x3=3.2x1=2,2x2=4,2x3=6 #include<stdio.h>#include<stdlib.h> int main() int i,j; printf(" "); for(i=1;i<=9;i+) printf("%3d",i); printf("n"); printf(" *");for(i=1;i<=9;i+)printf("&

5、quot;);printf("n");for(i=1;i<=9;i+)printf("%1d|",i); for(j=1;j<=9;j+) printf("%3d",i*j); printf("n");system("pause");5. 列出小於 1 00的所有質數 #include <stdio.h> #include<stdlib.h> int main()int i,j;printf("Please print prime number of

6、 1100?n");for(i=1;i<=100;i+) for(j=2;j<i;j+) if(i%j=0)break;if(j=i)printf("%d is a prime numbern",i);說明：j迴圈跑到jvi值都沒有成立i%j=O,代表i值無法被2i 之間的數整除system("pause");6利用動態陣列方式，計算10,11,12,的平方值，然後存於陣列中, 請輸入陣列大小 ：3輸出 100 , 121 , 144#include <stdio.h>#include<stdlib.h> int main()int size,i;int array100=0;printf("請輸入陣列大小："); scanf("%d", &size);for(