平抛运动实验报告英文版

1、IB PhysicsInternal Assessment CoverAssessment Title: Confirmation of Projectile Motion Name:XXXDate Due: Exam Year: 2013 Teacher: Date Handed In:DesignAspects LevelsCommentsComplete/2Partial/1Not at all/0Aspect 1Defining the problemand selectingvariablesFormulates a focusedproblem/researchquestion a

2、nd identifies the relevant variables.Formulates a problem/research question that is incomplete or identifies only some relevant variables.Does not identify aproblem/researchquestion and does not identify any relevant variables.Aspect 2Controlling variablesDesigns a method for the effective control o

3、f the variables.Designs a method that makes some attempt to control the variables.Designs a method that does not control the variables.Aspect 3Developing a methodfor collection of dataDevelops a method that allows for the collection of sufficient relevant data.Develops a method that allows for the c

4、ollection of insufficient relevant data.Develops a method that does not allow for any relevant data to be collected.MarksTotal Marks Data collection and Processingspects LevelsCommentsComplete/2Partial/1Not at all/0Aspect 1Recording raw dataRecords appropriatequantitative andassociated qualitativera

5、w data, including units and uncertainties whererelevant.Records appropriatequantitative andassociated qualitativeraw data, but with some mistakes or omissions.Does not record anyappropriate quantitativeraw data or raw data is incomprehensible.Aspect 2Processing raw dataProcesses the quantitative raw

6、 data correctly.Processes quantitativeraw data, but with some mistakes and/or omissions.No processing ofquantitative raw data is carried out or major mistakes are made inprocessing.Aspect 3Presenting processed dataPresents processeddata appropriately and, where relevant, includes errors and uncertai

7、nties.Presents processed data appropriately, but with some mistakes and/or omissions.Presents processeddata inappropriately orincomprehensibly.MarksTotal MarksConclusion and EvaluationAspects LevelsCommentsComplete/2Partial/1Not at all/0Aspect 1ConcludingStates a conclusion,with justification,based

8、on a reasonableinterpretation of thedata.States a conclusionbased on a reasonable interpretation of the data.States no conclusion or the conclusion is based on an unreasonableinterpretation of the data.Aspect 2Evaluating proceduresEvaluates weaknessesand limitations.Identifies some weaknesses and li

9、mitations, but the evaluation is weak or missing.Identifies irrelevantweaknesses and limitations.Aspect 3Improving the investigationSuggests realisticimprovements inrespect of identified weaknesses and limitations.Suggests onlysuperficial improvements.Suggests unrealistic improvements.MarksTotal Mar

10、ksManipulative SkillsAspects LevelsCommentsComplete/2Partial/1Not at all/0Aspect 1Following InstructionsFollows instructionsaccurately, adaptingto new circumstances(seeking assistance when required).Follows instructions but requires assistance.Rarely follows instructions or requires constant supervi

11、sion.Aspect 2Carrying out techniquesCompetent and methodical in the use of a range of techniques and equipment.Usually competent and methodical in the use of a range of techniques and equipment.Rarely competent and methodical in the use of a range of techniques and equipment.Aspect 3Working safelyPa

12、ys attention to safety issues.Usually pays attention to safety issues.Rarely pays attention to safety issues.MarksTotal MarksI confirm this assessment is my own work.Student signature: _Date: _General Comments:Teacher signature: _Aim: Utilize the relationship of horizontal displacement and vertical

13、displacement of little iron ball to verify if it is a projectile motion? Independent variable: vertical displacement, XDependent variable: horizontal displacement, YControlled variable: initial speed of iron ball when it leaves the track.initial direction of iron ball when it leaves the track. Metho

14、d of controlling variable:. Release the ball from the same height of a track; for example, release it from the top of the track every time. So the initial velocity can be sure to be the same each time. Use the air bubble at the bottom of the facility to check if the facility is in horizon. If the ai

15、r bubble is in exact middle of its area, the facility is horizontal. Steps (methods of collecting data)1. Pave the carbon paper behind the white paper together on the iron board using magnet to make it stick to the board. 2. Check if the air bubble is exactly in its central area. If not, use floor l

16、eveler to adjust the facility until facility is horizontal.3. After the facility is horizontal, release the ball from the top of the track. (Make sure it has the same initial speed each time.)4. Elevate the baffle plate upward some distance.5. Redo step 3 and 4 for 5times 6. Use ruler measure the do

17、ts on the white paperExperiment apparatus: clean white paper, carbon paper, ruler, little iron ball, iron board and iron tape, a facility shown below. The graph of apparatus: Row Data 12345horizontal displacement ( ±0.05com) X18.016.414.813.211.3Vertical displacement (±0.05)cm Y17.815.012.

18、09.36.7Method for verifying if it is a projectile motionExplanation: For projectile motion which has no vertical velocity, it can be divided into 2 separate parts, horizontal part and vertical part to analyze. Horizontally, it is a constant linear motion. Vertically, it is a free fall motion. Mathem

19、atically,x=v0t y=0.5gt2 t=(2y/g)0.5x=v0(2y/g)0.5And each v0=x(g/2y)0.5if v01= v02= v03= v04= v05, it is satisfies the relationship in projectile motion. Data process (g=980cm/s2)1st dotv01= x1(g/2y1)0.5=18.0(980/2×17.8) 0.5=94.4×10 cm/sUncertainty: x1:0.05/18.0=0.278% y1:0.05/17.8=0.281% S

20、um of percentage error: 0.5y1+x1=0.5×0.281%+0.278%=0.428%Absolute error: 94.4×10cm/s×0.428%=±4.04 cm/sv01=944±4.04 cm/s2nd dot v02= x2(g/2y2)0.5=16.4(980/2×15.0) 0.5=93.7×10 cm/sUncertainty: x2:0.05/16.4=0.305% y2:0.05/15.0=0.333% Sum of percentage error: 0.5y2 +x2

21、=0.5×0.333%+ 0.305% =0.472% Absolute error: 93.7×10×0.472%=4.42m/s V02=937 ± 4.42m/s3rd dot v03= x3(g/2y3)0.5 =14.8(980/2×12.0) 0.5=94.6×10cm/s Uncertainty: x3:0.05/14.8=0.338% Y3:0.05/12.0=0.417% Sum of percentage error: 0.5y3 +x3=0.547% Absolute error: 94.6×10

22、15;0.547%=5.17 cm/s V03= 946 ± 5.17 cm/s4th dotv04= x3(g/2y4)0.5 =13.2(980/2×9.3) 0.5=95.8×10cm/sUncertainty: x4:0.05/13.2=0.379% y4:0.05/9.3=0.538%Sum of percentage error: 0.5y4 +x4=0.5×0.538%+0.379%=0.648%Absolute error: 958×0.648%=6.21 cm/sV04=958±6.21 cm/s5th dot v05= x5(g/2y5)0.5=11.3(980/2×6.7) 0.5=96.6×10cm/sUncertainty: x5:0.05/11.3=0.442% y4:0.05/6.7=0.746% Sum of percentage error: 0.5y5 +x5=0.5×0.746%+0.442%=0.815%Absolute error: 966