山东科技大学面向对象程序设计c++答案(共13页)

1、精选优质文档-倾情为你奉上Problem A: 平面上的点Point类 (IV)Description在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定。现在我们封装一个“Point类”来实现平面上的点的操作。根据“append.cc”，完成Point类的构造方法和show()、showCounter()、showSumOfPoint()方法；实现showPoint()函数。 接口描述：showPoint()函数：按输出格式输出Point对象，调用Point:show()方法实现。Point:show()方法：按输出格式输出Point对象。Point:showCounter()方

2、法：按格式输出当前程序中Point对象的计数。Point:showSumOfPoint()方法：按格式输出程序运行至当前存在过的Point对象总数。Input输入多行，每行为一组坐标“x,y”，表示点的x坐标和y坐标，x和y的值都在double数据范围内。Output对每个Point对象，调用show()方法输出其值，或者用showPoint()函数来输出（通过参数传入的）Point对象的值：X坐标在前，Y坐标在后，Y坐标前面多输出一个空格。每个坐标的输出精度为最长16位。调用用showCounter()方法和showSumOfPoint()输出Point对象的计数统计，输出格式见sample

3、。C语言的输入输出被禁用。Sample Input1,23,32,1Sample OutputPoint : (1, 2)Current : 2 points.Point : (3, 3)Current : 2 points.Point : (2, 1)Current : 2 points.In total : 4 points.Current : 3 points.Point : (0, 0)Point : (1, 1)Point : (0, 0)In total : 6 points.#include<iostream>#include<iomanip>using

4、namespace std;class Pointprivate: double x_,y_; static int sum,num;public: Point():x_(0),y_(0)num+;sum+; Point(double xx):x_(xx),y_(1)num+;sum+; Point(double xx,double yy):x_(xx),y_(yy)num+;sum+; Point(const Point&p)x_=p.x_;y_=p.y_;num+;sum+; Point()num-; void show()cout<<setprecision(16)&

5、lt;<"Point : ("<<x_<<", "<<y_<<")"<<endl; static void showCounter()cout<<setprecision(16)<<"Current : "<<num<<" points."<<endl; static void showSumOfPoint()cout<<setprecision(16)<

6、;<"In total : "<<sum<<" points."<<endl;void showPoint(Point &a,Point &b,Point &c) a.show();b.show();c.show();int Point:sum=0;int Point:num=0;int main() char c; double a, b; Point q; while(std:cin>>a>>c>>b) Point p(a, b); p.show()

7、; p.showCounter(); q.showSumOfPoint(); Point q1(q), q2(1); Point:showCounter(); showPoint(q1, q2, q); Point:showSumOfPoint();Problem A: 复数类的构造、析构和输出Description封装一个复数类CPLX，用来处理复数功能和运算，支持以下操作：1. CPLX:CPLX(double, double)构造：参数为实部、虚部，用传入的参数初始化对象，产生一行以“CREATE()”开始的输出，并输出复数的实部和虚部；2. CPLX:CPLX()析构：产生一行以“RE

8、LEASE()”开始的输出，并输出复数的实部和虚部；3. CPLX:print()：产生一行以“PRINT()”开始的输出，并以格式“(a, bi)”的形式输出复数；-你设计一个CPLX类，使得main()函数能够运行并得到正确的输出。调用格式见append.ccInput输入的第一个整数n，表示用n组测试样例。每组测试输入两个实数，分别为实部和虚部。Output每组测试数据对应一组输出，两组输出之间用若干“=”分割，详细格式见sample。Sample Input52 310 00 1001 -1-7 -7Sample Output=CREATE(): 2 3PRINT(): (2, 3i)

9、RELEASE(): 2 3=CREATE(): 10 0PRINT(): (10, 0i)RELEASE(): 10 0=CREATE(): 0 100PRINT(): (0, 100i)RELEASE(): 0 100=CREATE(): 1 -1PRINT(): (1, -1i)RELEASE(): 1 -1=CREATE(): -7 -7PRINT(): (-7, -7i)RELEASE(): -7 -7=#include<iostream>#include<iomanip>using namespace std;class CPLXprivate: doubl

10、e x,y;public : CPLX(double xx,double yy) x=xx;y=yy; cout<<"CREATE(): "<<x<<" "<<y<<endl; CPLX() cout<<"RELEASE(): "<<x<<" "<<y<<endl; void print() cout<<"PRINT(): ("<<x<<&q

11、uot;, "<<y<<"i)"<<endl; ;int main() int cases; cin >> cases; for(int i = 1; i <= cases; +i) double a, b; cin >> a >> b; cout << "=" << endl; CPLX cplx(a, b); cplx.print(); cout << "=" << endl; Problem B

12、: 复数类的成员访问Description封装一个复数类CPLX，用来处理复数功能和运算，支持以下操作：1. CPLX:CPLX()构造：初始化一个实部、虚部均为0的复数，产生一行以“CREATE()”开始的输出，并输出复数的实部和虚部；2. CPLX:CPLX()析构：产生一行以“RELEASE()”开始的输出，并输出复数的实部和虚部；3. CPLX:real()：返回实部；   CPLX:imag()：返回虚部。4. CPLX:real(double)：传参修改实部；   CPLX:imag(double)：传参修改虚部；-你设计一个CPLX类，使得

13、main()函数能够运行并得到正确的输出。调用格式见append.ccInput输入的第一个整数n，表示用n组测试样例。每组测试输入两个实数，分别为实部和虚部。Output每组测试数据对应一组输出，两组输出之间用若干“=”分割，详细格式见sample。Sample Input52 310 00 1001 -1-7 -7Sample Output=CREATE(): 0 0Complex real part is 2, imaginary part is 3.RELEASE(): 2 3=CREATE(): 0 0Complex real part is 10, imaginary part i

14、s 0.RELEASE(): 10 0=CREATE(): 0 0Complex real part is 0, imaginary part is 100.RELEASE(): 0 100=CREATE(): 0 0Complex real part is 1, imaginary part is -1.RELEASE(): 1 -1=CREATE(): 0 0Complex real part is -7, imaginary part is -7.RELEASE(): -7 -7=#include<iostream>#include<iomanip>using n

15、amespace std;class CPLXprivate: double x,y;public : CPLX(double xx=0,double yy=0)this->x=xx;this->y=yy; cout<<"CREATE(): "<<x<<" "<<y<<endl; CPLX() cout<<"RELEASE(): "<<x<<" "<<y<<endl; double r

16、eal() return x; double imag()return y; CPLX &real(double xx); CPLX &imag(double yy); ; CPLX& CPLX:real(double xx) x=xx; return *this; CPLX& CPLX:imag(double yy) y=yy; return *this; int main() int cases; cin >> cases; for(int i = 1; i <= cases; +i) double a, b; cin >> a

17、 >> b; cout << "=" << endl; CPLX cplx; cplx.real(a); cplx.imag(b); cout << "Complex real part is " << cplx.real() <<", imaginary part is " << cplx.imag() << "." << endl; cout << "=" <<

18、 endl;Problem A: 立体空间中的点（I）Description设计一个平面上的点Point类和3维的点Point_3D类，满足Point_3D类继承自Point类，用于读取输入的数据，输出所构造的两种点的坐标。设计Point类需支持一下操作：Point:Point()无参构造。Point:Point(double,double)两个坐标参数构造。Point:showPoint()按格式输出Point对象设计Point_3D类需支持一下操作：Point_3D:Point_3D()无参构造。Point_3D:Point_3D(double,double,double)三个坐标参数构造

19、。Point_3D:showPoint()按格式输出Point_3D对象。-你设计Point类和Point_3D类，使得main()函数能够正确运行。函数调用格式见append.cc。append.cc中已给出main()函数。Input输入的第一个整数n，表示有n组测试数据，后面的输入每行为一组测试数据。每组测试数据的第一行是一个整数m，m有两种取值：2、3；m为2时，后面有两个浮点数x、y，表示一个平面上的点的坐标(x,y)；m为3时后面有3个浮点数x、y、z，表示一个3维的点的坐标(x,y,z)。Output每组测试数据对应一行输出。若输入为平面上的点，则输出：“2D Point (x,

20、y)”，x和y为输入的坐标值。若输入为3维的点，则输出：“3D Point (x,y,y)”，x、y和z为输入的坐标值。Sample Input53 1 2 33 0 0 02 -1 13 -1 -1 -12 0 0Sample Output3D Point (1,2,3)3D Point (0,0,0)2D Point (-1,1)3D Point (-1,-1,-1)2D Point (0,0)#include<iostream>using namespace std;class Pointprotected:int x,y;public:Point():x(0),y(0)Po

21、int(double x1,double y1):x(x1),y(y1) void showPoint()cout<<"2D Point ("<<x<<","<<y<<")"<<endl;class Point_3D:public Point /Point_3D从Point中派生protected:int z;public:Point_3D():z(0)Point_3D(double x1,double y1,double z1):Point(x1,y1),z(z

22、1)void showPoint()cout<<"3D Point ("<<x<<","<<y<<","<<z<<")"<<endl; int main() int cases; cin>>cases; for(int i = 1; i <= cases; i+) double x, y, z; int point_type; cin>>point_type; if(point_type =

23、 2) cin>>x>>y; Point p(x, y); p.showPoint(); if(point_type = 3) cin>>x>>y>>z; Point_3D p(x, y, z); p.showPoint(); Problem A: 立体空间中的点（IIDescription设计一个平面上的点Point类和3维的点Point_3D类，满足Point_3D类继承自Point类，用于读取输入的数据，输出所构造的两种点的坐标。并统计输入的两种点的个数。设计Point类需支持一下操作：Point:Point()无参构造。Poi

24、nt:Point(double,double)两个坐标参数构造。Point:x()返回x坐标Point:y()返回y坐标Point:x(int)修改x坐标并返回Point:y(int)修改y坐标并返回Point:showPoint()按格式输出Point对象Point:showNumber()返回Point对象总数的静态函数设计Point_3D类需支持一下操作：Point_3D:Point_3D()无参构造。Point_3D:Point_3D(double,double,double)三个坐标参数构造。Point_3D:z()返回z坐标。Point_3D:z(int)修改z坐标并返回。Poin

25、t_3D:showPoint()按格式输出Point_3D对象。Point_3D:setPoint(double,double,double)根据三个坐标参数修改Point_3D对象的坐标。Point_3D:showNumber()返回Point_3D对象总数的静态函数。-你设计Point类和Point_3D类，使得main()函数能够正确运行。函数调用格式见append.cc。append.cc中已给出main()函数。Input输入的第一个整数n，表示有n组测试数据，后面的输入每行为一组测试数据。每组测试数据的第一行是一个整数m，m有两种取值：2、3；m为2时，后面有两个浮点数x、y，表示

26、一个平面上的点的坐标(x,y)；m为3时后面有3个浮点数x、y、z，表示一个3维的点的坐标(x,y,z)。Output开始部分为由main()函数产生的固定输出，用于测试对象的某些方法的调用情况。输出“Test data output :”之后为测试数据对应的输出：每组测试数据对应一行输出。若输入为平面上的点，则输出：“2D Point (x,y)”，x和y为输入的坐标值。若输入为3维的点，则输出：“3D Point (x,y,y)”，x、y和z为输入的坐标值。最后，分别输出总共输入的平面上的点数和3维的点数。Sample Input53 1 2 33 0 0 02 -1 13 -1 -1 -

27、12 0 0Sample OutputInvariable test output :3D Point (-100,0,100)Point (0,100,100)Test data output :3D Point (1,2,3)3D Point (0,0,0)2D Point (-1,1)3D Point (-1,-1,-1)2D Point (0,0)Number of 2D Points : 2Number of 3D Points : 3#include<iostream>using namespace std;class Pointprotected:int X,Y;st

28、atic int n; static int m; /n,m被初始化为0public:Point():X(0),Y(0)n+; /无参构造Point(double x1,double y1):X(x1),Y(y1)n+;int x()return X;int y()return Y;int x(int x1)X=x1;return X;int y(int y1)Y=y1;return Y;static int showNumber()return n;void showPoint()cout<<"2D Point ("<<X<<"

29、;,"<<Y<<")"<<endl; class Point_3D:public Point /Point_3D从Point派生protected:int Z;public:Point_3D():Z(0)m+;Point_3D(double xx,double yy,double zz):Point(xx,yy),Z(zz)m+; /构造函数初始化列表int z()return Z;int z(int zz)return Z;void showPoint()cout<<"3D Point ("&l

30、t;<X<<","<<Y<<","<<Z<<")"<<endl;void setPoint(double xx,double yy,double zz)X=xx;Y=yy;Z=zz;static int showNumber()return m;int Point:n=0;int Point:m=0;int main() cout<<"Invariable test output :"<<endl; Point_3

31、D p3d; p3d.setPoint(-100, 0, 100); p3d.showPoint(); p3d.x(0); p3d.y(100); cout<<"Point ("<<p3d.x()<<","<<p3d.y()<<","<<p3d.z()<<")"<<endl; cout<<"nTest data output :"<<endl; int cases; cin&g

32、t;>cases; for(int i = 1; i <= cases; i+) double x, y, z; int point_type; cin>>point_type; if(point_type = 2) cin>>x>>y; Point p(x, y); p.showPoint(); if(point_type = 3) cin>>x>>y>>z; Point_3D p(x, y, z); p.showPoint(); cout<<"Number of 2D Points :

33、 "<<Point:showNumber() - Point_3D:showNumber()<<endl; cout<<"Number of 3D Points : "<<Point_3D:showNumber() - 1<<endl;Problem B: 还会用继承吗？Description定义一个Base类，包括1个int类型的属性，以及满足输出格式要求的构造函数、拷贝构造函数和析构函数。定义Base类的子类Derived，包括1个int类型的属性， 以及满足输出格式要求的构造函数、拷贝构造函数和析构

34、函数。Input第1行N>0表示测试用例个数。每个测试包括2个int类型的整数。Output见样例。Sample Input110 20Sample OutputBase = 10 is created.Base = 10 is copied.Base = 10 is created.Derived = 20 is created.Base = 10 is copied.Derived = 20 is copied.Derived = 20 is erased.Base = 10 is erased.Derived = 20 is erased.Base = 10 is erased.B

35、ase = 10 is erased.Base = 10 is erased.#include<iostream>using namespace std;class Basepublic: int a; Base(int t):a(t)cout<<"Base = "<<a<<" is created."<<endl; /拷贝构造函数 Base()cout<<"Base = "<<a<<" is erased."<&

36、lt;endl; /析构函数 Base(const Base& b)a=b.a;cout<<"Base = "<<a<<" is copied."<<endl;class Derived: public Base /Derived从Base中派生public: int b; Derived(int t):Base(t)cout<<"Derived = "<<b<<" is created."<<endl; Der

37、ived()cout<<"Derived = "<<b<<" is erased."<<endl; /析构函数 Derived(const Derived& d):Base(d),b(d.b)cout<<"Derived = "<<b<<" is copied."<<endl; Derived(int x,int y):Base(x),b(y)cout<<"Derived = "&

38、lt;<b<<" is created."<<endl;int main() int cases, data1, data2; cin>>cases; for (int i = 0; i < cases; i+) cin>>data1>>data2; Base base1(data1), base2(base1); Derived derived1(data1, data2), derived2(derived1); Problem A: 动物类-抽象类Description每种动物都有自己的叫声，如狗

39、的叫声是"汪汪汪"，猫的叫声是"喵喵喵"，老鼠的叫声是"吱吱吱"。构造类Animal，Dog，Cat，Mouse，他们都有成员数据name和sex，表示名字和性别。一个成员函数cry()，输出他们的叫声，在main函数中采用多态性调用他们。Input动物的姓名和性别Output动物的信息Sample InputJerry mJemmy fTom mDroopy mSample Output我叫Jerry，是一只男老鼠，我的叫声是：吱吱吱！我叫Jemmy，是一只女老鼠，我的叫声是：吱吱吱！我叫Tom，是一只男猫，我的叫声是：喵喵喵！我叫

40、Droopy，是一条男狗，我的叫声是：汪汪汪！#include<iostream>using namespace std;class Animalpublic: string name; char sex; virtual void cry()=0;/纯虚函数;/分号必不可少class Mouse: public Animalpublic: string name; char sex; Mouse(string n,char m)name=n;sex=m;if(sex='m') cout<<"我叫"<<name<&l

41、t;"，是一只男老鼠，" else cout<<"我叫"<<name<<"，是一只女老鼠，" void cry()cout<<"我的叫声是：吱吱吱！"<<endl;/分号必不可少class Dog: public Animalpublic: string name; char sex; Dog(string n,char m)name=n;sex=m;if(sex='m') cout<<"我叫"<<

42、;name<<"，是一条男狗，" else cout<<"我叫"<<name<<"，是一条女狗，" void cry()cout<<"我的叫声是：汪汪汪！"<<endl; /分号必不可少class Cat: public Animalpublic: string name; char sex; Cat(string n,char m)name=n;sex=m;if(sex='m') cout<<"我叫&qu

43、ot;<<name<<"，是一只男猫，" else cout<<"我叫"<<name<<"，是一只女猫，" void cry()cout<<"我的叫声是：喵喵喵！"<<endl;/分号必不可少int main( ) string nam; char s; cin>>nam>>s; Animal *p; Mouse m1(nam, s); p=&m1; p->cry(); cin>>n

44、am>>s; Mouse m2(nam, s); p=&m2; p->cry(); cin>>nam>>s; Cat c1(nam, s); p=&c1; p->cry(); cin>>nam>>s; Dog d1(nam, s); p=&d1; p->cry(); return 0;Problem B: 平面上的点Point类 (II)Description在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定。现在我们封装一个“Point类”来实现平面上的点的操作。根据“appe

45、nd.cc”，完成Point类的构造方法和show()方法，输出各Point对象的构造和析构次序。接口描述：Point:show()方法：按输出格式输出Point对象。Input输入多行，每行为一组坐标“x,y”，表示点的x坐标和y坐标，x和y的值都在double数据范围内。Output输出每个Point对象的构造和析构行为。对每个Point对象，调用show()方法输出其值：X坐标在前，Y坐标在后，Y坐标前面多输出一个空格。每个坐标的输出精度为最长16位。输出格式见sample。C语言的输入输出被禁用。Sample Input1,23,32,1Sample OutputPoint : (0,

46、 0) is created.Point : (1, 2) is created.Point : (1, 2)Point : (1, 2) is erased.Point : (3, 3) is created.Point : (3, 3)Point : (3, 3) is erased.Point : (2, 1) is created.Point : (2, 1)Point : (2, 1) is erased.Point : (0, 0) is copied.Point : (1, 1) is created.Point : (0, 0)Point : (1, 1)Point : (0,

47、 0)Point : (1, 1) is erased.Point : (0, 0) is erased.Point : (0, 0) is erased.#include<iostream>#include<iomanip>using namespace std;class Point private: double x_,y_;public:Point(double xx,double yy) x_=xx; y_=yy; cout<<"Point : ("<<setprecision(16)<<x_<&l

48、t;", "<<setprecision(16)<<y_<<")"<<" is created."<<endl;Point(double xx=0) x_=y_=xx; cout<<"Point : ("<<setprecision(16)<<x_<<", "<<setprecision(16)<<y_<<")"<<&qu

49、ot; is created."<<endl;void show() cout<<"Point : ("<<setprecision(16)<<x_<<", "<<setprecision(16)<<y_<<")"<<endl;Point(Point &p) x_=p.x_;y_=p.y_; cout<<"Point : ("<<setprecision(16)<

50、;<x_<<", "<<setprecision(16)<<y_<<")"<<" is copied."<<endl;Point();Point:Point() cout<<"Point : ("<<setprecision(16)<<x_<<", "<<setprecision(16)<<y_<<")"<&l

51、t;" is erased."<<endl; ;int main() char c; double a, b; Point q; while(std:cin>>a>>c>>b) Point p(a, b); p.show(); Point q1(q), q2(1); q1.show(); q2.show(); q.show();Problem C: 平面上的点Point类 (III)Description在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定。现在我们封装一个“Point类”来实现平面上的点的操作。根

52、据“append.cc”，完成Point类的构造方法和show()方法，输出各Point对象的构造和析构次序。实现showPoint()函数。接口描述：showPoint()函数按输出格式输出Point对象，调用Point:show()方法实现。Point:show()方法：按输出格式输出Point对象。Input输入多行，每行为一组坐标“x,y”，表示点的x坐标和y坐标，x和y的值都在double数据范围内。Output输出每个Point对象的构造和析构行为。showPoint()函数用来输出（通过参数传入的）Point对象的值：X坐标在前，Y坐标在后，Y坐标前面多输出一个空格。每个坐标的输

53、出精度为最长16位。输出格式见sample。C语言的输入输出被禁用。Sample Input1,23,32,1Sample OutputPoint : (0, 0) is created.Point : (1, 2) is created.Point : (1, 2) is copied.Point : (1, 2)Point : (1, 2) is erased.Point : (1, 2) is erased.Point : (3, 3) is created.Point : (3, 3) is copied.Point : (3, 3)Point : (3, 3) is erased.P

54、oint : (3, 3) is erased.Point : (2, 1) is created.Point : (2, 1) is copied.Point : (2, 1)Point : (2, 1) is erased.Point : (2, 1) is erased.Point : (0, 0) is copied.Point : (1, 1) is created.Point : (0, 0) is copied.Point : (1, 1) is copied.Point : (0, 0) is copied.Point : (0, 0)Point : (1, 1)Point :

55、 (0, 0)Point : (0, 0) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.Point : (0, 0) is erased.#include<iostream>#include<iomanip>using namespace std;class Pointprivate: double x,y;public: Point(double xx=0) x=y=xx; cout<&l

56、t;"Point : ("<<setprecision(16)<<x<<", "<<setprecision(16)<<y<<")"<<" is created."<<endl; Point(double,double);void show() cout<<"Point : ("<<setprecision(16)<<x<<", "<<setprecision(16)<<y<<")"<<endl; Point(Point &p) x=p.x;y=p.y; cout<<"Point : ("<<setprecision(16)<<x<<", &