




下载本文档
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
1、1. Moon Micro is a small manufacturer of servers that currently builds all of its product in Santa Clara, California. As the market for servers has grown dramatically, the Santa Clara plant has reached capacity of 10,000 servers per year. Moon is considering two options to increase its capacity. The
2、 first option is to add 10,000 units of capacity to the Santa Clara plant at an annualized fixed cost of $10,000,000 plus $500 labor per server. The second option is to have Molectron, an independent assembler, manufacture servers for Moon at a cost of $2,000 for each server (excluding raw materials
3、 cost), raw materials cost $8,000 per server, and Moon sells each server for $15,000.Moon must make this decision for a two-year time horizon. During each year, demand for Moon servers has an 80 percent chance of increasing 50 percent from the year before and a 20 percent chance of remaining the sam
4、e as the year before. Molectron prices may change as well. They are fixed for the first year but have a 50 percent chance of increasing 20 percent in the second year and a 50 percent chance of remaining where they are.Using a decision tree to determine whether Moon should add capacity to its Santa C
5、lara plant or if it should outsource to Molectron. What are some other factors that would affect this decision that we have not discussed.Assume that a discount factor is 10 percent.注意:Moon已有设备产能为10,000,对两种方案都是一样提供该产能,所以比较增量需求 禾I润即可。Option ABase year 0Year 1Year 2Probability64%16%16%Year 2Revenue=(2
6、0,000-10,000)*15,000*0.64+(15,000-10,000)*150,000*(0.16+0.16)+(10,000-10,000)*15,000*0.04Variable cost = (20,000-10,000)*500*0.64 +(15,000-10,000)*500*(0.16+0.16) +(10,000-10,000)*500*0.04Fixed cos2=10,000,000Total cos2= Variable cost+ Total costProfit2= Revenues- Total costYear 1Revenue =(15,000-10
7、,000)*15,000*0.8+(10,000-10,000)*150,000*0.2Variable cost=(15,000-10,000)*500*0.8+(10,000-10,000)*500*0.2Fixed cost=10,000,000Total cost= Variable cost+ Total costProfit1 = Revenue- Total costBase Year 0Profit0=0NPVa = profit 0 profit 11 -kprofit12(1 k)Option B丫 :ar 240% Dam a ndM ole ctro n cost/se
8、rver22.500$ 2.000Probability32% 一DemandDennsindl 1 D1,00040% DBrnandl15jDOO y- Molactrcin cast/ssrveir22.5QD$ 2,40032%110% DsmandMolectron cost/seiwr110% DemandMolectrcin cost/serverMolectron cost/serverDemand15.000S 2.00015.ODD$ 2.4DQ15.000$ 2 .ODD15J00D$ 2.40010.000$ 2,000WJOOO$ 2.40口8%B%8%8%2%Yea
9、r 2Revenue=(22,500-10,000)*15,000*(0.32+0.32)+(15,000-10,000)*15,000*(0.08+0.08+0.08+0.08) +(10,000-10,000)*15,000*(0.02+0.02)Cost2 =(22,500-10,000)*(2000+8000) *0.32+(22,500-10,000)*( 2400+8000) *0.32 +(15,000-10,000)*(2000+8000)*(0.08+0.08)+(15,000-10,000)* (2400+8000)*(0.08+0.08) +(10,000-10,000)
10、*(2000+8000)*0.02 +(10,000-10,000)* (2400+8000)*0.02Profit2 = Revenue- Total Cost同理可得Year 1 ,Year 0利润,代入下式: ,11NPVB = profit 0 profit 1 profit 2 1k(1 k)2比较NPVa, NPVb大者为最优方案!2. Weekly sales of Hot Pizza are as follows:WeekDemand ($)WeekDemand ($)WeekDemand($)110859691122116611910102311879611924124810
11、21291Estimate demand for the next four weeks using a four-week moving average and simple exponential smoothing with o=0.1. Evaluate the MAD, MAPE, MSE, bias, and TS in each case. Which of the two methods do you prefer? Why?Refer to excel!3. Harley Davidson has its assembly plant in Milwaukee and its
12、 motorcycle assembly plant in Pennsylvania. Engines are transported between the two plants using trucks, with each trip costing $1000. The motorcycle plant assembles and sells 300 motorcycles each day. Each engine costs $500, and Harley incurs a holding cost of 20 percent per year. How many engines
13、should Harley load onto each truck? What is the cycle inventory of engines at Harley?Solution:2DSThe economic order quantity is given by . In this problem:D = 109,500 (i.e., 300 units/day multiplied by 365 days/year)S = $1000/orderH = hC =0.2*500 = $100/unit/yearQ* = 2DS =1480hCSo, theEOQ value is 1
14、480 unitsD _ Q,TC S 一hC DC =$147,986 Q 2So the total yearly cost is $147,986.The cycle inventory value is EOQ/2 = 1480/2 =7404. Prefab, a furniture manufacturer, uses 20,000 square feet of plywood per month. Their trucking company charges Prefab $400 per shipment, independent of the quantity purchas
15、ed. The manufacturer offers an all unit quantity discount with a price of $1 per square foot for orders under 20,000 square feet, $0.98 per square foot for orders between 20,000 square feet and 40,000 square feet, and $0.96 per square foot for orders larger than 40,000 square feet. Prefab incurs a h
16、olding cost of 20 percent per year. What is the optimal lot size for Prefab? What is the annual cost of such a policy? What is the cycle inventory of plywood at Prefab? How does it compare with the cycle inventory if the manufacturer does not offer a quantity discount but sells all plywood at $0.96
17、per square foot?Solution(1) For, price = $1.00 per unitQi= EOQ =2 20000 12 4000.2 1=30,984Since Qi> 19,999We select Qi= 20,000 (break point) and evaluate the corresponding total cost, which includes purchase cost + holding cost + order costTotal Cost尸 DC。Q1 hC0 S 2Qi2000020000 12= 20000 12 0.98 0
18、.2 0.98 400 = $ 241,960220000(2) For, price = $0.98 per unitQ2= eoq =2 20000 12 400312980.2 0.98Q2 =31298 20000,40000)Total Cost2 = DC1 Q2hC1 S 2Q2= 20000 12 0.983129820000 120.2 0.98 400 = $241,334231298(3) For, price = $0.96 per unit0.2 0.96Q3= EOQ =2 20000 12 400 =31623Q3 =31623 :: 40000We select
19、 Q3= 40,000 (break point) and evaluate the corresponding total cost, which includes purchase cost + holding cost + order costTotal Cost3 = DC 2 Q3 hC2 2 S 2Q3= 20000 12 0.96316230.2 0.96 20000 12 400 =$236,640231623Total Cost3 <Total Cost 2 <Total Cost 1So, the optimal value of Q* = 40000 and
20、the total cost is $236,640The cycle inventory is Q*/2 = 40000/2 = 20000 (b) If the manufacturer did not offer a quantity discount but sold all plywood at $0.96 per square foot then Q = 31,623 and the total cost is $ 233,4365. Weekly demand for Motorola cell phones at a Best Buy store is normally dis
21、tributed, with a mean of 300 and a standard deviation of 200. Motorola takes two weeks to supply a Best Buy order. Best Buy is targeting a CSL of 95% and monitors its inventory continuously. How much safety inventory of cell phones should Best Buy carry? What should its ROP be.SolutionDl = LD = 2*30
22、0 = 600二 L = L O d = 200,2 = 283ss = Fs1 (CSL)二l = Fs1 (0.95)283 = 465(where, Fs1 (0.95) = NORMSINV (0.95)=1.6431)ROP = DL + ss = 600 + 465 = 10656. Assume that the Best Buy store in Exercise 1. The store manager has decided to review inventory every three weeks. Assuming a periodic review replenish
23、ment policy, evaluate the safety inventory that the store should carry to provide a CSL 95%. Evaluate the OUL for such a policy.SolutionDl = (T+L) D = (2+3)*300 = 1500oL = vfTLct D = 2002+3 = 447ss = Fs-1(CSL) ;=l = Fs-1(0.95) 447 = 736 (where,FS-1(0.95) = NORMSINV (0.95) =1.6431)OUL = D(T+L) + ss = 1500 + 736 = 2236Supply chain, cycle inventory, safety inventory, replenishment policy, continuous review, periodic review, produc
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 高中师说课件
- 2025年春季教导处工作计划(附2至6月工作安排)
- 高中东南亚课件听
- 知识产权许可与转让常年法律顾问服务协议
- 城市绿化工程合同签订条件及植物养护责任规定
- 离异家庭财产分割及子女教育基金协议
- 离婚协议书撰写参考:共同财产分割与子女监护权协议
- 如何在初高中生中进行性别平等教育
- 巴鲁兄弟的幽默漫画规程
- 优雅走向成功的商务礼仪课程
- 2025版煤矿安全规程宣贯培训课件
- (教科2024版)科学三年级上册2.1 水到哪里去了 课件(新教材)
- 2025国家能源集团招聘笔试历年参考题库附带答案详解
- 编织课件教学课件
- 认证机构保密管理办法
- 土建类安全员C2模拟试题及参考答案
- 上锁挂牌管理培训课件
- 公司财务报表分析技巧与方法
- 葡萄冷藏保鲜技术规程
- 新课标(水平三)体育与健康《篮球》大单元教学计划及配套教案(18课时)
- 建筑工人临时用工协议书
评论
0/150
提交评论