项目三银行账户管理系统

1、工程三 个人银行账户管理系统、设计要求设计一个个人银行账户管理程序，能够显示帐户信息、存款、取款、余额、结算利息等操作。要求：个人根据实际能力进行设计，可以在根本功能的实现的前提下尽可能充实完善自己的程序。二、设计思想1、类的结构图 < 见右>2?程序主要功能说明： amou nt=floor(amount*100+0.5)/100将计算结果保存到小数点后两位. void record(i nt date,double amoun t):期为止的存款金额按日累计值 in terest=accumulate(date)*rate/365三、源代码获得到指定的日利息计算.#in clu

2、de<iostream>#in clude<cmath>using n amespace std;class Sav in gsAcco unt / private: 储蓄账户类int id; / 账号 double bala nee; / int lastDate; / double rate; /余额 上次变更余额的时期存款的年利率余额按日累加之和double accumulati on; /记录一笔账，date为日期，amount为金额,说明 desc为Savin gsacco unt-id:i nt-shijia n:i nt-shijia n 1:i nt-s

3、hijia n 2:i nt-ri:i nt-float : lilv-zhanghao : int-bala n ce:double-rate:double-lastDate:i nt-accumulati on: double-record:(date : int,amount ; double)-accumulate ( date:int ) :double +getBala n ce():double+getrate():double+show()+deposit(date:int,amount: double)+withdraw(date:i n t,am oun t:double)

4、+settle(date:i nt)void record(i nt date,double amoun t);/获得到指定的日期为止的存款金额按日累计值double accumulate(i nt date) const retur n accumulatio n+bala n ce*(date-lastDate);public: /构造函数Savin gsAcco un t(i nt date,i nt id,double rate);int getId() retur n id;double getBala n ce() retur n bala nee ;double getRate(

5、) return rate;void deposit (i nt date , double amoun t);/存入现金void withdraw (int date, double amoun t);/取出现金/计算利息每年1月1日调用一次函数void settle(i nt date);/显示账户信息void show();/SavingsAccount 类相关成员的实现 SavingsAccount:SavingsAccount (int date,int id, double rate): id(id),balance(0),rate(rate),lastDate(date),acc

6、umulation(0) cout<<date<<"t#"<<id<<"is created"<<endl;void SavingsAccount:record(int date,double amount) accumulation=accumulate(date); lastDate=date;amount=floor(amount*100+0.5)/100;/ 保存小数点后两位 balance+=amount; cout<<date<<"t#"&

7、lt;<id<<"t"<<amount<<"t"<<balance<<endl;void SavingsAccount:deposit(int date,double amount) record(date,amount);void SavingsAccount:withdraw(int date,double amount) if (amount>getBalance() cout<<"Error: not enoughmoney"<<e

8、ndl;else record(date,-amount);void SavingsAccount:settle(int date) double interest=accumulate(date)*rate/365; /计算利息 if(interest!=0)record(date,interest);accumulation=0;void SavingsAccount:show() cout<<"#"<<id<<"tBalance: "<<balance;int main()int shijian,sh

9、ijian1,shijian2;int ri,zhanghao;float lilv;int jine,jine1;cout<<"Create a account"<<endl;cout<<"Enter the account cteated date： "cin>>ri;cout<<"Enter account number ： "cin>>zhanghao; cout<<"One year of Interest rates ： &quo

10、t;/ 年利率cin> >lilv;Savin gsAcco unt sa(ri,zhan ghao,lilv); cout«"E n ter the deposit time cin> >shijia n;cout<<"E n ter deposit amount cin ?ji ne;sa.deposit(shijia n,jin e); cout<<"E nter withdrawals time:"/取款时间cin> >shijia n1;cout<<"E

11、 n ter the amount you want to withdrawals cin ?ji n e1;sa.withdraw(shijia n 1,ji n e1);cout<<"E n ter how long you acco un ted already cin> >shijia n2;sa.settle(shijia n 2);/取款金额:"/开户至今时间sa.show();coutvve n dl;return 0;、士四、测试结nwwtemp.exereate a acco untn ter the acco unt cteated date 1 nteracco unt nu mber:1234 ine year ofInterest rates : 0. 1 312341s created theEdeposit time:deposit amount : ?1234(En ter h10000withdrawals t ime1000010000En ter：100IEnter the amount you want to withdrawalst 9000 51234 100-90001000Enter how long you accounted already : 1