版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
。《交通规划》课程设计任务书设计目的设计内容⑴无约束重力模型进行交通分布预测⑵交通网络的计算机建模⑶非平衡分配法(包括全无全有交通分配、容量限制-增量加载分配、多路径概率分配)和平衡分配进行交通分配预测设计题目⑴现有一规划区域,共划分为5OD1,2,3,分析计算得到未来各交通区间的交通出行时间见4,试用无约束重力模型进行交通分布预测,收敛条件为3。表1交通区12345110005003002001002450150050010015033502008003005041501503007005058010050705002。表2交通区123451510182030212410252031510815354202515103053525353512交通区表3产生量吸引量150004000240004500330003500425002500520002000表4交通区12345151012152021048202031010710304152010820530203030101、3、7、91和通行能力如表2,交通阻抗函数为tt V/C)。i 0i i i请用平衡分配法确定各路段的交通量3。Ⅰ Ⅱ1 2 3Ⅲ Ⅳ Ⅵ Ⅶ4 5 6Ⅷ Ⅸ Ⅹ7 8 9Ⅺ Ⅻ图交通网络图表1OD表137910202050330040107403002093040300表2各路段零流量的出行时间和通行能力表ⅠⅡⅢⅣⅠⅡⅢⅣⅤⅥⅦⅧⅨⅩⅪⅫ033542180605050100C 80
3 3100
2 4100 50
3 250 1004.设计成果每一关键步骤的计算。成果文件、程序流程图和必要说明(包括变量说明等)。⑶采用软件计算必须有输入和输出文件和详细的计算界面。4。课程设计成果设计一无约束重力模型进行交通分布预测使用软件:SPSS、Excel。设计步骤:根据无约束重力模型qij
Oi
2cj ij应先求出代标定参数α、β、β1 2
和γ,再根据模型计算一遍分布交通量,最后通过数次平均系数法迭代得到最终分布交通量。一、使用Excel处理数据并进行运算根据重力模型,两边取对数得ln(q)=lnα+βln(O)+βln(D)-γln(c)转换式子为
ij 1 i 2 j ijy=aaxaxax0+1111+1212+22
=β
=β
=ln(O
=ln(D),x=ln(c
ij 0
1 1 12 2 2
11 i 12 j2 ijODt转化为目录型表格。根据参数定义和OD表数据,计算出各OD点对的对应样本数据如下:5。。样本数据iJQijOiDjcijyxllx12x21110002100203056.90787.649776157910721.60941250021002450106.21467.649778038433042.30261330021001950185.70387.649775755846522.89041420021001370205.29837.649772225660192.9957151002100850304.60527.649767452363493.40122145027002030126.10927.901076157910722.48492215002700245047.31327.901078038433041.38632350027001950106.21467.901075755846522.30262410027001370254.60527.901072225660193.2189251502700850205.01067.901067452363492.99573135017002030155.85797.438476157910722.70813220017002450105.29837.438478038433042.3026338001700195086.68467.438475755846522.07943430017001370155.70387.438472225660192.708135501700850353.91207.438467452363493.55534115013502030205.01067.207976157910722.99574215013502450255.01067.20797.8038433043.21894330013501950155.70387.20797.5755846522.70814470013501370106.55117.20797.2225660192.302645501350850303.91207.20796.7452363493.401251808002030354.38206.684676157910723.5553521008002450254.60526.684678038433043.218953508001950353.91206.684675755846523.555354708001370354.24856.684672225660193.555355500800850126.21466.684667452363492.4849二、使用SPSS软件进行回归得到参数值将计算得到的y、x、x、x数据复制到SPSS软件中进行线性回归分析11 12 2惯mtlstksmmm填轼但〉牡堰但)转坎0分析色)直销也)图形色)实用程序但)9芒H邑四贮勹宜兰耄n环陛霉先圉忒令、、 可见6.917657.621616.2176578()25.707.657582.895307657223006.917657.621616.2176578()25.707.657582.895307657223004617656.753406.117OO7,622487317.907139621790758246179()7223225.017.906.753.005B67447622.71.910'"125'"125.30744780136.687447.5814570744722153.917.446.75165.017217175.017.217802082.713.563003.221B 570 721 758 2.7119 6.55 7.21 722 2.“3.3.9143878886.75762340356t4616.687803.223916687583564256687223566.216.686.752.48212224252728293031323356
量--变量,一变量
量』尸交量气孟一女--安置+ +t tt|IBMSPSS3P|*末标题1[数据集OJ-IBMSPSSStatistics数据编铝串心i文件也)编吨)视图01..)数据但)转换C!:)分析)直销也)图形但)实用程序但)百口笆)蒂助心i雪究驾三三三匀H号驾尸勹雪究驾三三三描述统计 表[T)y_J| x11
x1比轻均值也))
7.65
一般线性棋型笆)621 7655.70 7.655.30 7.654.61 7.65
广义线性谟型 ------'-t相关) 6.11 7.907.31 7.906.21 7.90_11501 7215.70 7.216.55 7.213.91 7.214.38 6.68
但)4.617.90分类4.617.90分类(!:)5.017.90降雏5.867.44度噩(S)5.307.44(!-1.)6.687.44预叽尼)5.707.44生存函数但)391744多垂响应也)函U)心lf!IROC仅J..U
心自动线性建模包)品线性化)谥曲线估计贮)圈部分铜小平方二元LogisticLogistic有序祀!:robit囡非线性(!:'!)函权重估计也)胧两阶呆小二乘法Q)最佳同度(CATREG)卜4.61 6.68卜3.91 4.25 6.686.21
7.807.587.226.75
3.22卜++3.56卜+++3.56++2.48+迫线性回归 工因变量但)
[统计量但)]#x11#x12#x2
口块1的1己己i自变量O)
l绘制U)l保存(S)l选项@)ootstrap(B)」方法也)
1进入
趋纽生回归:统计量回归系数
玉冈模型拟合度也)、选择变量但)
规jillj(.)
化巴置信区间
巴R方变化岱)巴描述性 、 WLS 、 巨 已 皿 己 已
水平(%):95巴协方差矩阵仅)残差巴D「bin-Watson(U)巴个案诊断贮)@离群值(Q)@所有个案
巴部分相关和偏相关性贮)巴共线性诊断心3标准差3------------------71!1'i'I1!1汜:
;石■O分析色)l!I彤@邑四C勹已艺品逋心:"
回归11
11飞|行动双 '|氓臣沁叮扭戏 1: 1:1产1比1勹
岱二总*总*|,,邓I出气.j',I,,勺'"'ooo008' 系数a 非标准化系数 标准系数模型B标准误差试用版tSig.1 (常量)9.9672.4963.993.001x11-.019.187-.008-.102.920x12-.012.200-.005-.061.952x2-1.551.142-.954-10.909.000a.因变量:y8。由SPSS软件得出a
=-0.019,a
=-0.012,a=-1.5510 11 12 2根据参数定义算得参数值为α=21311.455,β=-0.019,β=-0.012,γ=1.5511 2标定的无约束重力模型为q 21311.455O0.019ij i
0.012cj
1.551三、使用Excel求解已标定重力模型的交通量由重力模型和样本数据,使用Excel计算分布交通量得到下表9。四、使用Excel进行平均系数法迭代第一次迭代:取重力模型分布交通量中的V/D和U/O数据,根据平均系数法得到各点对应的系数ijFOFD平均系数111.9006135941.4963050871.698459341121.9006135941.3987357581.649674676131.9006135941.4503817421.675497668141.9006135941.5085414771.704577535151.9006135941.8798086941.890211144211.1746796871.4963050871.335492387221.1746796871.3987357581.286707722231.1746796871.4503817421.312530714241.1746796871.5085414771.341610582251.1746796871.8798086941.52724419311.2825726671.4963050871.389438877321.2825726671.3987357581.340654213331.2825726671.4503817421.366477204341.2825726671.5085414771.395557072351.2825726671.8798086941.581190681411.4403907581.4963050871.468347923421.4403907581.3987357581.419563258431.4403907581.4503817421.44538625441.4403907581.5085414771.474466118451.4403907581.8798086941.660099726512.1877854491.4963050871.842045268522.1877854491.3987357581.793260603532.1877854491.4503817421.819083595542.1877854491.5085414771.848163463552.1877854491.8798086942.0337970710。第—次迭代计算。u第—次迭代计算。uil2353.7138778.4294597.5087431.8665308.28384469.802350001.118617717i2628.59172502.8341873.6826216.523724789924469.531340000.894948426i3659.7571635.15741128.7805665.7965138.05453227546030000.929498749i4373.3862230.5282689.66839987076273.03632565.326525000.974534818i5161.4543294.1239159.5187162.7568989.9402176779392000l.131353602D4176.90314441.07293449.15872475.65111957.214116500.0000V4000450035002500200016500系数V/D0.9576472961.0132686551.014740191.009835361.021860616ijijFOFD平均系数111.1186171170.9576472961.038132506121.1186177171.0132686551.065943186131.1186177171.014740191.066678953141.1186177171.009835361.064226538151.1186171171.0218606161.010239166210.8949484260.9576472960.926297861220.8949484261.0132686550.954108541230.8949484261.014740190.954844308240.8949484261.009835360.952391893250.8949484261.0218606160.958404521310.9294987490.9576472960.943573023320.9294987491.0132686550.971383702330.9294981491.014740190.972119469340.9294981491.009835360.969667054350.9294987491.0218606160.975679682410.9745348180.9576472960.966091057420.9145348181.0132686550.993901136430.9745348181.014740190.994637504440.9745348181.009835360.992185089450.9745348181.0218606160.998197717511.1313536020.9576472961.044500449521.1313536021.0132686551.072311128531.1313536021.014740191.073046896541.1313536021.009835361.070594481551.1313536021.021860616l.0766071091。未达到收敛标准ε=3%,继续进行迭代。第三次迭代:ijFOFD平均系数111.0638027330.9574822451.010642489121.0638027331.027577181.045689957131.0638027331.0215902111.042696472141.0638027331.0094608961.036631815151.0638027330.9801312461.02196699210.9415591820.9574822450.949520714220.9415591821.027577180.984568181230.9415591821.0215902110.981574696240.9415591821.0094608960.975510039250.9415591820.9801312460.960845214310.9624274790.9574822450.959954862320.9624274791.027577180.995002329330.9624274791.0215902110.992008845340.9624274791.0094608960.985944187350.9624274790.9801312460.971279362410.9845371310.9574822450.971009688420.9845371311.027577181.006057156430.9845371311.0215902111.003063671440.9845371311.0094608960.996999013450.9845371310.9801312460.982334189511.0552833070.9574822451.006382776521.0552833071.027577181.041430244531.0552833071.0215902111.038436759541.0552833071.0094608961.032372102551.0552833070.9801312461.0177072772。未达到收敛标准ε=3%,继续进行迭代。第四次迭代:ijFOFD平均系数111.0383499360.9662010571.002275497121.0383499361.0246682731.031509104131.0383499361.0180974161.028223676141.0383499361.0072733441.02281164151.0383499360.9762398891.007294913210.9633202270.9662010570.964760642220.9633202271.0246682730.99399425230.9633202271.0180974160.990708821240.9633202271.0072733440.985296785250.9633202270.9762398890.969780058310.9780290820.9662010570.972115069320.9780290821.0246682731.001348677330.9780290821.0180974160.998063249340.9780290821.0072733440.992651213350.9780290820.9762398890.977134485410.990292050.9662010570.978246554420.990292051.0246682731.007480161430.990292051.0180974161.004194733440.990292051.0072733440.998782697450.990292050.9762398890.98326597511.0306830150.9662010570.998442036521.0306830151.0246682731.027675644531.0306830151.0180974161.024390215541.0306830151.0072733441.018978179551.0306830150.9762398891.0034614523。达到收敛标准ε=3%。综上,满足要求的交通分布量如下表所示:交通区1234512475.0907895.0129683.3189487.3083339.64492533.38812337.0043811.2517198.2075221.38633580.9357614.72601086.4325631.8488127.83704342.6480232.2344690.9578986.7265263.24935169.4511337.5494182.0857183.30121088.40324。设计二平衡分配法进行交通分配预测使用软件:TransCAD。设计步骤:使用TransCAD的交通分配功能直接进行设计。软件使用步骤如下:打开软件,点击菜单栏file—newGeographicfilelinegeographic在属性窗口添加出行时间和通行能力,点击OK储存图层。5。。AttributesforNewLayer 已`FieldName Type WidthDecimalslndex出行盯间 Integer(4bytes)8
^|8ddeIdIOpleId| 囡SaveAs 已e
I上东二赶
习仁也~正 Mve白eldStoragelnforma订onName阻 厂Index二二。 Iype|Inter(4ytJ 初dth广 e二二。 Defau甘
TransCAD
2016/3/2015,21气g/ 气DisplayNameDescnghon[玉cordInformon厂AddR旦cords
生切ngs|
Fileaane; Fllesofe;F=phlcFlle(土,
习I |习 严|Tool—MapEditing—ToolboxMapEditing目线路序号的顺序,绘制路网:空Mapl-NewLa上工工1.. ,_.,_、..,·---_;;1 1.....检查路网连通性:点击菜单栏Tools—MapEditing—CheckLineConnectivity,选择6Threshold精度为0.01进行校准,点击OK得到NoConnectivityProblemsFound提示即可。CheckLineLayerConnectivityNodeLayer Line压Nod'eSel'ecbon庐lhreshol'd庐TIFeetNote
立| 0k |Cance||三]习O O NoConnectlVItyProb|emsFoundI 确定 1切换图层为NewEndpointLayer,点击菜单Selection—Settings,弹出窗口New EndpointLayerSelectionSetsSetsiriOrderofPriority SampleRecords
已|,CIose II |$tatus |邸dSet|e | LabeIs |Rename
Move丛p|IMove旦own|点击AddSet增加设置,并改名为ODNewEndpointLayerSelectionSets9SetsiriOrderofPriority SampleRecords9
己已layer:Newlayer:NewEndpol.•Active Igtatus |邸Set|_ _ 丿点击Style进行样式设置如下
Move丛p|IMove旦own|7Style(OD)[lype(itarc1
已r o'm IIcons 斥 font庐"SybolsCp[lrppointsI| 0k | Cance|| App|y | Reset|N窃wEndpN窃wEndp已的立electionODSampl'e()(}RecordsToolsselectbyPointingshift+1、3、798空Mapl-NewLaye, 三电压 创建新的节点矩阵OD表,如下设置 CreateMatriCreateMatrixFile|eNwEtyeM呕eIDsare1n二Rowsfromloo 习匕CnooseaTypeofFil'e可JDatav1ew
.... OK l
OK lCancelI/gjLayout/GeographicFi'l'e围TabIleCreateanewmatrixfile
CancellI
二 :Columnsfrom咖 二 :'际
IndicesISaSample(X)Recmds保存名为OD9囡SaveAs Lookin:[I荼二题L七 名称L
习 ~沪釭
已修改日期
TranD文件
2016/3/2015:21库桌面库计算机网络xirt泗庐远f:xirt泗庐远f:nao-siFiFLabel [NewEndpointle
习;;;狂e |习 cance1 || 4确定后按题目条件输入OD数据如下团Matrixl-NewEndpointLayerMatrixFile(Matrix1)11317111317190.0020.0020.0050.0030.0040.0010.000.0040_0030_00o_oo20_0030_0040_0030_00o_oonetwork/pathcreatenetwork,oknetCreateNetworkInputsCreatelinksfromCreateNetworkInputsCreatelinksfrom[Entirelinelayer囡SaveAs立习..m2它甲eadlengthfromDescription名称TransCAD文件修改日期2015:21桌面OtherNodeFields1iDLongitudeLatitude!!lFileno.Fi1esoftype·ItmorkFile二I Save |了 canc|,§吉0选择NewLayer图层,点击工具栏的AutomaticLabels ,如下所示填写从而对路网进行编号AutomaticLabels(Layer:NewLayer)bsIvlsIsIGenernllill1DPositiorilcernteiedaboveSmartStretch
匕习 save |习 Load |P-Alrowrota廿on厂AlowDrulspcingro---厂LimitLineso- CharactersndaI'usng.sanaN'ewngsanaUPCparalItarabicrabitTypesetting
....I S|18 丑国I Col'orfiiiiiiiiiii"3F,l丁 ta1c...1[stlAriIR叫tir | I:( | Cance|| App|y | Remove| |空Mapl-Nyer 芦言玉276七 寸, IO,276101011 121点击 NewDataview输入数据ataview6-Newyataview6-Newyer巨 玉
削闺行荔力1 21900 3 8021900 10017940 5017340 10017150 5021400 5021700 100◄730 801◄9◄0 6010 16240 502180D 5012 21610 100选择菜单栏planning—trafficassignment进行交通流的分配,按图中进行设置,点击okTrafficAssignmentLineLayer压五示Ikie庐卢 遁纬躺彴芒第二T|UseIEqui'lib斗MatrixF仆e|NewerMa妪4fieldsTfieldsTime佪气 ]Arpha!NoneBeta!NonePreload!None
— 己已0k |Cance||Settmgs|习lGl'obalsIt.era廿onsI2OConvergence!0.0100FunctionI
AlphaBetaErrorls.00002-囡StoreFlowlein 己-Lookin:11第二题 ..:J 仁国巴厅了名称 修改日期最近访问的位匣 交 I.BIN 2016/23:33匣桌面二....二库I计算机Q网络 Ill CancelFilena皿e: IASN_Linkl'low.bin 斗 Save CancelFilesoftype:Inxed-for皿atBinary 斗4- 团Result4- 团algTalgTie000003[Wam|ngsandReportLmesLogged丕 丕 54318 。600000 12625435431852500SnowWarnins Close2160D100252!1!1655
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 线下模型活动策划方案(3篇)
- 营销推广应急措施方案(3篇)
- 诚实友爱活动方案策划(3篇)
- 运输全员营销激励方案(3篇)
- 金属屋面项目施工方案(3篇)
- 门店营销纠正方案(3篇)
- 韩国蛋糕活动策划方案(3篇)
- 鱼塘换填土施工方案(3篇)
- 应急演练记录模板-1
- 涂装后处理工7S执行考核试卷含答案
- 2026-2030中国全氟聚醚行业发展方向及产销需求预测研究报告
- 2025年巴州事业单位面试真题及答案
- 污水处理化验员试题及答案
- 上海证券交易所公司债券预审核指南审核和发行程序及其实施
- 2025版高职院校人才培养方案指导意见
- 2026年内江市市中区社区工作者招聘笔试参考题库及答案解析
- 2026广西北部湾国际港务集团有限公司春季招聘273人建设考试参考题库及答案解析
- 2025~2026学年云南省师范大学附属中学呈贡学校九年级中考适应性(三)道德与法治试卷
- 检验科新进人员岗前培训
- DB13∕T 6225-2025 国内首次使用的化工工艺安全可靠性论证导则
- 2025湖南长沙市望城区人民医院面向社会公开招聘编外合同制专业技术人员20人笔试历年典型考题及考点剖析附带答案详解试卷2套
评论
0/150
提交评论