微型计算机原理与接口技术测试题

1.在XXX单元中存放一个数x(«x<15),请用查表法的方法计算乂的平方，并将结果保存到丫丫丫单元中。datasegmenttablesqdb0,1,4,9,16,25,36,64db81,100,121,144,169,196,225xxxdb3yyydb?dataendscodesegmentassumecs:code,ds:datamainprocfarstart:pushdsmovax,0pushaxmovax,datamovds,axmovbx,offsettablesqmovah,0moval,xxxaddbx,axmoval,[bx]movyyy,alint20hmainendpcodeendsendstart方法二(参考课本程序)：datasegmenttabqdb0,1,4,9,16,25,36,64db81,100,121,144,169,196,225xxxdb2yyydb?dataendscodesegmentassumecs:code,ds:datastart:movax,datamovds,axmovsi,offsettabqmovah,0moval,xxxaddsi,axmoval,[si]movyyy,al

int20hcodeendsendstart2.已知数组由100个字组成，存放在数据段中以偏移地址为ARY开始的内存中，试编写程序求出这个数组元数之和，结果存放在的数据段中以偏移地址为SUM开始的内存中。datasegmentarydw100dup(?)sumdw?dataendscodesegmentassumecs:code,ds:datastart:movax,datamovds,axcallraddmovah,4chint21hraddprocnearpushaxpushbxpushcxpushdxleabx,arymovcx,10xorax,axmovdx,axcll:addax,[bx]jnccl2incdxcl2:addbx,2loopcllmovsum,axmovsum+2,dxpopdxpopcxpopbxpopaxretraddendpcodeendsendstart3.试编写一程序，将数据段中偏移地址为BUF1开始的100个数据传送到偏移地址为BUF2开始的连续内存单元中去。STACKSEGMENTSTACK'STACK'DW100DUP(?)

STACKENDSDATASEGMENTBUF1 DB 100DUP(?)BUF2 DB 100DUP(?)SRCADR DW?DSTADR DW?LENDW?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATA,SS:STACK,ES:DATAMAINPROCSTART:MOVAX,DATAMOVDS,AXMOVES,AXLEAAX,BUF1MOVSRCADR,AXMOVLEN,100CALLMVDATMOVAX,4CHINT21HMAINENDPMVDATPROCMOVSI,SRCADRMOVDI,DSTADRMOVCX,LENCLDCMPSI,DIJADONESTDADDSI,CXDECSIADDDI,CXDECDIDONE:REPMOVSBRETMVDATENDPCODEENDSENDSTART4.编写一个程序，实现SUM=a1+a2+……+a20。已知@1一@20依次存放在以8评为首址的数据区，每个数据占两个字节，SUM也是两个字节。datasegmentdatdw2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2sumdw

dataendscodesegmentmainprocfarassumecs:code,ds:datastart:movax,datamovds,axmovax,0movsum,axmovsi,offsetdatmovcx,20lp1:addax,[si]incsiincsilooplp1movsum,axmovah,4chint21hmainendpcodeendsendstart5.试编写一程序，将AX中的各位去反，然后统计出人*中“0”的个数，将结果存到社中。CODESEGMENTMAINPROCFARASSUMECS:CODESTART:MOVAX,0E001HMOVDL,0MOVCL,16NOTAXRETEST:ANDAX,AXJSSKIPINCDLSKIP:SHLAX,1LOOPRETESTMOVCL,DLEXIT:MOVAH,4CHINT21HMAINENDPCODEENDSENDSTART6.在内存数据段存储器中，从ADDR单元开始存有一个字符串，它以“$”符号作为结束标

志，试编写程序统计该字符串的长度($字符不计入长度)，并把长度值存入:^^字单元。DATASEGMENTADDRDB'LIUBIN$'LETHDW?DATAENDSSTACKSEGMENTPARASTACK'STACK'DB100DUP(?)STACKENDSCODESEGMENTASSUMECS:CODE,DS:DATA,SS:STACKSTART:MOVAX,DATAMOVDS,AXMOVBX,OFFSETADDRMOVCX,0LP:MOVAL,[BX]CMPAL,'$'JEDONEINCCXINCBXJMPLPDONE:MOVADDR,CXMOVAH,4CHINT21HCODEENDSENDSTART7.试编写一程序，要求实现将ASCII码表示的两位十进制数转换为一字节二进制数，其中高地址单元存放十位数。codesegmentassumecs:codestart:movah,1int21hmovdl,0dhmovah,2int21hmovdl,0ahmovah,2int21hmovbl,almovcx,8next:shlbl,1movdl,30hadcdl,0movah,2

int21hloopnextmovdl,'a'movah,2int21hmovah,4chint21hcodeendsendstart8.某存储区中存有20个单字节数，试编写一汇编程序分别求出其绝对值并将结果放回原处。datasegmentnumdb1,-1,1,1,1,-1,1,1,1,1,1,1,-1,1,1,1,1,1,1,1dataendscodesegmentassumecs:code,ds:datastartprocfarpushdsxorax,axpushaxmovax,datamovds,axmovcx,20movsi,offsetnumlp1:moval,[si]andal,aljnsdonenegaldone:mov[si],alincsilooplp1movah,4chint21hstartendpcodeendsendstart方法二：DSEGSEGMENTMUMDB1,2,3,-9,0,7,5,-4,-7,-11,34,-67,-44,-51,1,3,6,8,9,3DSEGENDSCSEGSEGMENT

ASSUMECS:CSEG,DS:DSEGSTARTPROCFARPUSHDSXORAX,AXPUSHAXMOVAX,DSEGMOVDS,AXMOVCX,20MOVSI,OFFSETMUMLP1:MOVAL,[SI]ANDAL,ALJNSDONENEGALDONE:MOV[SI],ALINCSILOOPLP1MOVAH,4CHINT21HSTARTENDPCSEGENDSENDSTART.编程在显示器上输出你自己的汉语拼音姓名的子程序。DATASEGMENTLBDB'liubin'NEQU$-LBDATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVES,AXLEADI,LBMOVCX,NCLDMOVAH,1INT21HREPNESCASBJZFOUNDMOVDL,'N'JMPDISPFOUND:MOVDL,'Y'DISP:MOVAH,2INT21HMOVAH,4CH

INT21HCODEENDSENDSTART.将数据0-63置入到内存中以8评为首址的连续64个字节单元中。datasegmentbufdb64dup(?)dataendscodesegmentassumecs:code,ds:datastart:movax,datamovds,axmovbx,offsetbufmoval,0movcx,63llp:mov[bx],alincalincbxloopllpmovah,4chint21hcodeendsendstart.试编写一程序统计出某一内存变量中‘1’的个数，并将结果存入内r8单元。datasegmentxdadw11firstdb?dataendscodesegmentassumecs:code,ds:datastart:movax,datamovds,axmovcl,0movax,xdalop:cmpax,0jzexitshlax,1jncnextincclnext:jmplopexit:movfirst,clint20hcodeendsendstart

课本考题P203：3-1、datasegmentstringdw2dup(3045h,0fd34h,0d3dh,9899h,0,3df2h,0,0ffdeh,93fdh,0de6ch)pdw20dup(?)mdw20dup(?)zdw20dup(?)dataendscodesegmentassumecs:code,ds:datastart:movax,datamovds,axxorbp,bpleasi,pleadi,mleabp,zpushsipushdipushbpleabx,stringmovcx,20ll:subdx,axshrdx,clmov[bp],dxpopaxmovdx,disubdx,axshrdx,clmov[di],dxpopaxmovdx,sisubdx,axshrdx,clmov[si],dxmovah,4chint21hl1:movax,[bx]pushaxaddax,axjzl1popax

pushaxsalax,1jc12popaxmov[si],axaddsi,2jmpla1a:addbx,2loop11xorcx,cxmovcx,2popaxmovdx,bppopaxmov[bp],axaddbp,2jmpla12:popaxmov[di],axadddi,2jmplacodeendsendstart3-2DATASEGMENTD1DB2,3,4,5,6,7,8,3,4,5D2DB?DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXLEASI,D1XORAX,AXMOVCX,10L1:ADDAL,[SI]AAAINCSILOOPL1MOVAH,4CHINT21HCODEENDSENDSTART

4-3.CODESEGMENTMAINPROCFARASSUMECS:CODEMOVCH,4ROT:MOVCL,4ROLBX,CLMOVAL,BLANDAL,0FHADDAL,30HCMPAL,3AHJLLBADDAL,7HLB:MOVDL,ALMOVAH,2INT21HDECCHJNZROTMOVAX,4C00HINT21HMAINENDPCODEENDSEND3-4.DATASEGMENTBLOCKDBNDUP(0)SIGNALDB00HADRDB00HDATAENDSCODESEGMENTASSUMEDS:DATA,CS:CODE,ES:DATASTART:MOVCLDDI.OFFSETBLOCKMOVCX,10MOVSL,IEHREPNISCASBJNZAAAMOVSIGNAL,0FFHMOVADR,IEHAAA:MOVSIGNAL,00H

CODEENDSCODEENDSENDSTART3-6.datasegmentnumdw100dup(10)sumdw?msgdb'Overflow!',13,10,'$'dataendsstacksegmentstackdb100dup(?)stackendscodesegment'code'assumecs:code,ds:data,ss:stackstart:mov ax, dataTOC\o"1-5"\h\zmov ds, axmov cx, 100leabx,nummov ax, 0again:add ax, [bx]incbxincbxjcerrloopagainmovsum,axjmpdoneerr:mov dx,offsetmsgmovah,09hint21hdone:movax,4c00hint21hcodeendsendstar出师表

两汉：诸葛亮先帝创业未半而中道崩殂，今天下三分，益州疲弊，此诚危急存亡之秋也。然侍卫之臣不懈于内，忠志之士忘身于外者，盖追先帝之殊遇，欲报