西安交通大学实验报告

C++1 10页别2011324日02 2011324日52(、做 )同人 教师审批签字一. .1.2内容（－）题目一：编写字符串反转函数mystrrev().1．要点分析略序源代码#include<iostream>#include<string>#include<cstring>usingnamespacestd;voidmystrrev(charstring[]){inti,n;charp;n=strlen(string);for(i=0;i<=int(n/2-1);i++){p=string[i];string[i]=string[n-1-i];string[n-1-i]=p;}}main(){charinti,n;cout<<";(s,20);n=strlen(s);cout<<";for(i=0;i<=n-1;i++)cout<<s[i];mystrrev(s);cout<<endl<<";for(i=0;i<=n-1;i++)cout<<s[i];cout<<endl;return0;}。1要点分析略程序源代码#include<iostream>usingnamespacestd;intimax(intarray[],intcount){inti,max;max=array[0];for(i=0;i<=count-1;i++)if(array[i]>max)max=array[i];returnmax;}intimin(intarray[],intcount){inti,min;min=array[0];for(i=0;i<=count-1;i++)if(array[i]<min)min=array[i];returnmin;}main(){constintinta[num];inti,j,n;一个"<<num<<"个数的数组："<<endl;for(i=0;i<=num-1;i++)cin>>a[i];cout<<"此数组中最大的元素为："<<imax(a,num)<<endl;cout<<"此数组中最小的元素为："<<imin(a,num)<<endl;return0;}isprime(inta)an个。要点分析略源代码#include<iostream>#include<cmath>usingnamespacestd;intisprime(inta){inti;if(a==1)return0;for(i=2;i<=sqrt(a);i++){if(ai==0)return0;}return1;}main(){inti;constintn[m];cout<<""<<m<<"for(i=0;i<=m-1;i++)cin>>n[i];cout<<"上几中的质for(i=0;i<=m-1;i++)if(isprime(n[i])==1)cout<<n[i]<<" ";cout<<endl;return0;}实验结果（四）实验题目四x0XX1略程序源代码#include<iostream>#include<cmath>usingnamespacestd;doublea[10];intn;doublef(doublex){doublef;inti;f=0;for(i=n;i>=0;i--)f+=a[i]*pow(x,i);returnf;}doublex(doublex0,doublex1){doublet,x2;t=1E-7;do{x2=(x0+f(x0)*(x0-x1)/(f(x1)-f(x0)));if(f(x2)*f(x0)>=0)x0=x2;elsex1=x2;cout<<f(x2)<<endl;}while(fabs(f(x2))>t);returnx2;}main(){inti;doublex0,x1;cout<<":";cin>>n;cout<<"为："<<endl;for(i=n;i>=1;i--)cout<<"a["<<i<<"]X^"<<i<<"+";cout<<"a[0]=0"<<endl;for(i=n;i>=0;i--)cin>>a[i];coutXo<X<X1"<<endl;cout<<"Xo=";cin>>x0;cout<<"X1=";cin>>x1;if(f(x0)*f(x1)<0)cout<<"X="<<x(x0,x1)<<endl;elsecout<<"<<x0<<"<<x1<<"上无解或有多个解！"<<endl;return0;}实验结果精度10-7。原型：doublenmysqrl(double x)1．要点分析略2#include<iostream>usingnamespacestd;#include<cmath>doublemysqrt(doublex){doublex1,x2,t;x1=1;x2=1;t=1E-7;while((fabs(x1*x1-x)>t)||(fabs(x1-x2)>t)){x1=x2-(x1*x1-x)/(2*x1);x2=x1;}returnx1;}main(){doublen;cout<<cin>>n;cout<<"sqrt("<<n<<")="<<mysqrt(n)<<endl;return0;}3六）实验题目六11223312345987809999999。略代码#include<iostream>#include<>#include<fstream>usingnamespaceintp(longn){intintnum=int(log10(n))+1;a[0]=n10;for(i=1;i<=num;i++){a[i]=int(n/pow(10,i))10;if(a[i-1]<a[i])return0;}return1;