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Chapter5PrincipleofVirtualWorkandDisplacementofStructure
Section1Introduction1、DisplacementofstructurePositionofastructurewillbechangedundertheactionofload,temperature,foundationsettlementetc.(1)、linedisplacementahorizontaldisplacement:
Hbverticaldisplacement:V(2)、angulardisplacement:
(3)、Alldisplacementsdescribedabovearecalled“generalizeddisplacement”,forcescorrespondingto“generalizeddisplacement”are“generalizedforce”.
(4)、Examplesofdisplacements2、AimsatstructuredisplacementLimitthedisplacementofstr.i.edeflectionofmainbeamislimitedwithin(1/1000)L.(2)Solutestaticallyindeterminateproblemslater.Inotherwords,staticallyindeterminateproblemsmustberequireddisplacementofthestructures.3、ASSUMPTIONS(1)、MaterialmustcomplywithHuke’slaw.(2)、Onlysmalldisplacementstakeplaceinthestructure.(3)、Thereisnofrictioninlinkage.
PPBASection2RealworkPThestaticloadPisgraduallyappliedtoastructure,itcannotgiverisetoVibration.P:0P:0Therealwork:1,RealworkdonebyexternalloadAbeamissubjectedtoanexternalconcentratedstaticloadP.Displacement△takeplaceunderthestaticload.
2,Realworkdonebyinternalforces
Asmallsegmentdsisisolatedforanalyzing.a)realworkdonebyNWhere:Eistheelasticitymodulus;Aisthecross-sectionarea.
2,Realworkdonebyinternalforces
Asmallsegmentdsisisolatedforanalyzing.b)realworkdonebyMWhere:Iisthecross-sectionmomentofinertia
2,Realworkdonebyinternalforces
Asmallsegmentdsisisolatedforanalyzing.c)RealworkdonebyshearingforceQWhere:kisacoefficientassociatedwiththeshapeofcross-section.Gismodulusinshear.Rectangularcross-sectionCircularcross-section
ThetotalrealworkdonebyN,Q,MinthesegmentdsisAsmallsegmentdsisisolatedforanalyzing.
ThetotalrealworkdonebyN,Q,MinthesegmentdsisAsmallsegmentdsisisolatedforanalyzing.Forthemember
Forthestructure(allmembers)
Bytheconservationlawofenergy,thetotalexternalrealworkmustbeequaltotheinternalrealwork(strainenergy).Section3.Virtualwork
Abeamiselongatedalengthunderactingof,later,anotherloadisappliedtothebeam.Displacementiscausedby.Obviously,theworkdonebyinthedisplacementTherearetwosubscripts,thefirstsubscriptstandfor,thesecondsubscriptmeansthedisplacementthatiscausedbyiscalledvirtualwork
ThevirtualworkisdefinedastheproductoftheforcePandthecorrespondingdisplacementthatisproducedbyanyreasonotherthantheforceP.ThemagnitudeofvirtualworkisequaltotheshadedrectangularareashowninFigVirtualworkisdifferentfromrealworkinfollowingaspects:(1)Thereiscoefficientinrealworkexpression.Andinvirtualworkformula,thereisno.(2)Valueofreadworkisalwayspositive,virtualworkispositionornegative.ItisdeterminedbydirectionsbetweenPand.ForconditionshowninfollowingFig.,iscausedby,afterP2isappliedtostructure.ItcausesatpointP1andatpointP2.SothetotalworkdonebyexternalloadsP1,P2is:ThetotalworkdonebyinternalforcesisBytheconservationlawofenergy,thetotalexternalworkmustbeequaltothetotalinternalworkBytheconservationlawofenergy,thetotalexternalworkmustbeequaltothetotalinternalworkBecauseofTheformulashowsthatexternalvirtualworkisequaltotheinternalvirtualwork.ItiscalledthePrincipleofVirtualworkTheprincipleofvirtualworkcanbeusednotonlytostaticallydeterminatestructure,butalsostaticallyindeterminatestructure.Becausethetwogrouploadsareindependent,sowecandividetwogrouploadsintotwoindependentbalancestates:Section4Displacementanalysis1,DisplacementequationInordertousetheprincipleofvirtualworktosolutethedisplacement,WesetFig.asanexample.
AbeamABisactedbyload.Howcanwedeterminethedisplacementatthemiddlepointofthebeam?
ThedisplacementcausedbyrealforcePatmiddlepointofthebeamis,theinternaldisplacementscausedbyrealforcePatsmallsegmentdsare:
TheexternalvirtualworkdonebyinthedisplacementcausedbyPis:
Tosolutethisproblem,wesetupanotherforcestate.Atthemiddleofthebeam,weapplyaforcetothebeamTheexternalvirtualworkdonebyinthedisplacementcausedbyPis:Theinternalvirtualworkdonebyinternalforces,,inthedisplacementdsduetoN,M,Qis
Forthebeam
ABAccordingtothePrincipleofvirtualwork,wehave:WhatvaluedoesPkhasforconveniencetocalculatethedisplacement?So,thedisplacementofthebeamcanbecalculatedbyusingformula:Formembersofastructure,wehave:Stepsindetailtosolutethedisplacement:(1)listequationsofN,M,Qcausedbyrealexternalloads.(2)Setupafictitiousstate.Unitloadorisappliedtothepointwherethedisplacementwillbedetermined,listequationsofallmembers’,,causedbyunitload.(3)SubstituteallinternalforcestoequationNote:①payattentiontosignsofN,Q,M.iftheordinatesofandMarethesameside,thesignofandMispositive,ifarenotthesameside,isnegative.②ifsignofispositive,itshowsthatthedirectionofdisplacementisidenticaltothedirectionof.2、Howtoapplyunitload(linedisp.、relativelinedisp.)
Thedirectionofunitloadisidenticaltothedirectioninwhichthedisp.isdesired2、Howtoapplyunitload(angulardisp.、relativeangulardisp
)
Section5Simplificationoftheequation1、Beamandframe(N,Qareomitted):2、Truss(onlyNinmembers):3、Forcompositestructure:4、EX.
EX.1Findverticaldisplacement
AVatpointA.EIofallmembersisconstant.Solution:(1)MequationsunderrealloadSegmentAB:SegmentBC:
(2)Setupfictitiousstate,unitloadisappliedtoA.(3)MequationsundertheunitloadinthefictitiousstateSegmentAB:SegmentBC:
(4)SubstituteMequationstodisplacementexpression
EX.2FindverticaldisplacementatjointC
CVintruss.EAisconstantSolution:(1)Findaxial(normal)forcesofalllinksinthetruss,theirvaluesaremarkedinthetruss.
(2)Setupfictitiousstate,unitloadisappliedtojointC,findallforces
underthisstate,marktheminFig.
(3)Substitutetheforces,toformula
EX.3FindverticaldisplacementatpointBinaquarterofring.RadialisR,EIisconstant.Solution:
(1)Isolateanarbitrarysmallsegmentds
fromthering,MequationinthearbitrarycrosssectionIswrittenas:
(2)Setupafictitiousstate,theMcanbeexpressedas:
(3)DisplacementFinddeflectionatmiddlepointCofthebeam.
Solution:(1)Reactions:
(2)PointAisassumedtobeoriginalpoint.Anarbitrarycross-sectionfarfrompointA,xisselected.Thebendingmomentinthecross-sectionis(3)setupafictitiousstateofexternalload.ShowninFig.P=1isexertedonpointCofthebeam.
Thereactions:
(4)Thebendingmomentinarbitrarycross-sectionis:Forthisbeam:Q,Nareomitted.
Theispositive.Thedirectionofdisplacementisdownward.
Findverticaldisp.AtpointCandangulardisp.AthingeAinthefollowingbeam.EIisconstant.PCBAl/2l/2CBAl/2l/2M(1)(2)Problems:P179.9—5(b),9--14Section6GraphMultiplicationThegraphmultiplicationcanbeappliedtodisplacementcalculationprovidedthat:
(1)
Theaxisofmemberisastraightline;(2)TherigidityEI(orGA,EA)isaconstant;(3)Oneofthetwointernalforcefoundationsisalinearfunction.Iftherearemanymembersinastructure,andintegralwillbecalculatedmanytimes.Graphmultiplicationcanbeusedeasily.1、CertificationConclusion:undertheconditionsdescribedabove,displacement
istheproductbetweenareaofadiagramandcentroidordinateoftheotherdiagram,thendividetheEI。3、Notice:
(1)、yomustbeobtainedfromalinerdiagramωjyoMMω1y1(2)、Iflinearfunctiondiagramconsistsofzigzagline,thecalculationmustbedonebydividingthelineintosegmentsω2y2MMω1y1(3)、Ifcrosssectionisnotuniform,calculationmustconductbysegmentsω2y2(4)、If2diagramsareonthesamesideofmember,theproductispositive,or,isnegativeMMωPyoωPyoMMω1y1ω2y2(5)、If2diagramsarebothliner,theareaandordinatecanbeobtainedfromeitherofthediagramsMM(6)、Ifthediagramiscomplex,thediagramcanbedividedinto2ormoreeasierdiagrams,thenusesuperposition.y1y2ω1y3y4ω2abcdlMM(6)、Ifthediagramiscomplex,thediagramcanbedividedinto2ormoreeasierdiagrams,thenusesuperposition.acdlalSUMMARY:(1)yomustbeobtainedfromalinerdiagram(2)Iflinearfunction
diagramconsistsofzigzagline,thecalculationmustbedonebydividingthelineintosegments.(3)Ifcrosssectionisnotuniform,calculationmustconductbysegments.(4)If2diagramsareonthesamesideofmember,theproductispositive,or,isnegative.(5)If2diagramsarebothliner,theareaandordinatecanbeobtainedfromeitherofthediagrams.(6)Ifthediagramiscomplex,thediagramcanbedividedinto2ormoreeasierdiagrams,thenusesuperposition.
Themagnitudeofareasandthelocationoftheircentroidforsomecommondiagramsaregivenasfollowing.
Solution1:(1)DrawM(2)Unitloadisappliedonpointc,drawM(M)(M)
Findverticalandangulardisplacement
CVand
CSolution2:
AnunitmomentisappliedtopointC(M)(M)
P170;Ex.9-6P171;Ex.9-7
Problem:9--19Section7Displacementscausedbyotherfactors1、DisplacementcausedbymanufacturingerrorsThedisplacementcausedbymanufacturingerrorsintrussisWhere:istheerror.
ExInthistruss,membe
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