利用C语言实现经典游戏斗兽棋

第利用C语言实现经典游戏斗兽棋#defineCardH()img_animals[0].getheight()

#defineCardX(col)(28+col*(CardW()+42))//28左边的间隔42横向中间的间隔

#defineCardY(row)(65+row*(CardH()+43))//65上边的间隔43横向中间的间隔

voidcard_init(Card*card,introw,intcol,intaniType)

card-row=row;

card-col=col;

card-animalType=aniType;

voidcard_draw(Card*card)

putimage(CardX(card-col),CardY(card-row),getAnimalImage(card-animalType));

intcard_type(Card*card)

if(card-animalType=8)

returnBT_Blue;

elseif(card-animalType8card-animalTypeAT_Max*2-1)

returnBT_Red;

//两张牌类型是否相同

boolcard_sameType(Card*card1,Card*card2)

returncard_type(card1)==card_type(card2);

//消费者是否能吃食物

boolcard_eat(Card*food,Card*consumer)

//先把大于8的，也转成小于八的，方便比较

intftype=food-animalType;

intctype=consumer-animalType;

ftype=ftype8food-animalType-8:ftype;

ctype=ctype8consumer-animalType-8:ctype;

if(!card_sameType(food,consumer)//不是同一方

ftype=ctype||/*大吃小*/(ftype==AT_Elephantctype==AT_Mouse)//老鼠吃大象

returntrue;

returnfalse;

Cardcards[4][4];

intcurBothType=BT_Blue;//当前行棋方

enumState

Begin,

intpress=Begin;//第一次点击还是第二次点击

structIndex

introw;

intcol;

}beg={-1,-1},end={-1,-1};

voidinit()

srand(time(NULL));

for(inti=0;ii++)

for(intk=0;kk++)

card_init(cards[i]+k,i,k,i*4+k+1);

//打乱数组

for(inti=0;ii++)

for(intk=0;kk++)

intr=rand()%4;

intc=rand()%4;

Cardt=cards[r][c];

cards[r][c]=cards[i][k];

cards[i][k]=t;

//加密数组

for(inti=0;ii++)

for(intk=0;kk++)

cards[i][k].animalType+=20;

printf("%d",cards[i][k].animalType);

putchar('\n');

voiddraw()

//绘制背景

putimage(0,0,imgs+0);

for(inti=0;ii++)

for(intk=0;kk++)

IMAGE*t=getAnimalImage(cards[i][k].animalType);

putimage(CardX(k),CardY(i),t);

if(beg.row!=-1)

setlinestyle(PS_SOLID,3);

setlinecolor(RED);

intx=CardX(beg.col);

inty=CardY(beg.row);

intw=CardW();

inth=CardH();

rectangle(x,y,x+w,y+h);

//65264286590108

boolisIn(intx,inty,intleft,inttop,intw,inth)

if(xleftxleft+wytopytop+h)

returntrue;

returnfalse;

voidonMouseLbuttonDown(ExMessage*msg)

for(inti=0;ii++)

for(intk=0;kk++)

//判断是否在卡牌上点击

if(isIn(msg-x,msg-y,CardX(k),CardY(i),CardW(),CardH()))

//如果没有翻开,则翻开

if(cards[i][k].animalType20)

cards[i][k].animalType-=20;

//如果翻开了，可以移动或者吃

else

//如果点击的是同一方的牌,直接改变begin

//if(card_type(cards[i][k])==curBothType)

//press=Begin;

//点击不同的牌在move函数里进行判断

//移动或者吃，需要知道两次点击的牌

if(press==Begin)

beg={i,k};

press=End;

printf("begin(%d%d)%d\n",i,k,curBothType);

elseif(press==End)

end={i,k};

press=Begin;

printf("end(%d%d)%d\n",i,k,curBothType);

voidmove()

//begend不为-1并且不是同一个位置

if((beg.row!=-1end.row!=-1)!(beg.row==end.rowbeg.col==end.col))

//在同一列或者同一行

if((abs(beg.row-end.row)==1beg.col==end.col)||(abs(beg.col-end.col)==1beg.row==end.row))

boolok=card_eat(cards[end.row][end.col],cards[beg.row][beg.col]);

//移动

if(ok||cards[end.row][end.col].animalType==AT_None)

cards[end.row][end.col]=cards[beg.row][beg.col];

cards[beg.row][beg.col].animalType=AT_None;

beg=end={-1,-1};

//切换棋手

curBothType=(curBothType+1)%2;

intmain()

initgraph(540,677/*,EW_SHOWCONSOLE*/);

loadResource();

init();

while(true)

BeginBatchDraw();

draw();

EndBatchDraw();

ExMessagemsg;