化工原理实验数据处理

1、化工原理实验数据处理作者:日期:L/hh1/cmh2/cmh3/cmh4/cmh5/cmh6/cm0102.3102.2102.444.644.544.7160102101.4101.736.635.636.4350101.398.5100.534.934.434.8500100.890.999.433.732.733.670099.787.397.230.529.430.485098.179.194.727.825.727.190098.377.194.226.324.926.2110096.668.191.523.521.223.40、h2段截面连续性方程验证丿序号流量L/h流速1(m/s

2、)流速2(m/s)u1df (m3/s)u2df(m3/s)100.00000.14000.00000.247321600.06290.34870.44440.615833500.13760.75350.97221.330845000.19661.40681.38902.484757000.27521.58311.94442.796168500.33421.95852.36113.459279000.35392.06892.50003.6545811000.43252.40273.05564.2444hi、h3段压头损失与流速的关系丿序号流量L/h流速1(m/s)h1/cmh3/cm压头损失/

3、cm100.0000102.3102.4-0.121600.0629102101.70.333500.1376101.3100.50.845000.1966100.899.41.457000.275299.797.22.568500.334298.194.73.479000.353998.394.24.1811000.432596.691.55.1序号流量流速h3/cmh4/cm压头损失/cmL/h1(m/s)100.0000102.444.657.821600.0629101.736.665.133500.1376100.534.965.645000.196699.433.765.75700

4、0.275297.230.566.768500.334294.727.866.979000.353994.226.367.9811000.432591.523.568.0入、h5段雷诺数与流体阻力系数的关系丿序号流量L/h流速1(m/s)h4/cmh5/cm压力损失/cm雷诺数摩擦系数100.000044.644.50.100.000021600.062936.635.61.017725.055133500.137634.934.40.538760.528245000.196633.732.71.055380.517457000.275230.529.41.177520.290568500.3

5、34227.825.72.194140.376079000.353926.324.91.499680.2236811000.432523.521.22.3121820.2459h5、h6段管道平均流速与中心流速的关系丿序号流量L/h流速1(m/s)h5/cmh6/cm压力损失/cm中心流速U/(m/s)100.000044.544.70.20.198021600.062935.636.40.80.396033500.137634.434.80.40.280045000.196632.733.60.90.420057000.275229.430.41.00.442768500.334225.72

6、7.11.40.523879000.353924.926.21.30.5048811000.432521.223.42.20.6567五实验数据分析h*本实验所得的实验结果存在巨大误差， 与实际生产生活实际很不相符，精确 度不准确，主要产生误差的地方有：流体未处于稳态过程，波动性很大，影响实 验结果；由于波动性很大，以至于操作人员读数的不缺定性，引起很大的实验结 果误差；实验装置本身的误差。六思考题1流体在管道中流动时涉及到那些能量？答：主要涉及动能、位能和静压能的相互转换。2.观察实验中如何测得某截面上的静压头，又如何得到某截面的动压头？ 答：通过在截面上安装一只单管压力计，通过压力计液位的高度来反映静压头； 通过水平两截面之间的压力机中液位差和已知流量来确定另一截面的动压头。3管观察各项机械能数值的相对大小，并进行分析讨论。答：通过观察各项机械能数值的相对大小，可以得出：hl大于h2,由于截面的内径发生变化，也就是动压头的变化，静压能转化为动能；h2大于h3，由于节流件的影响，造成阻力损失，以至于静压能减少；h3大于h4