数字信号处理基于计算机的方法第11章答案

数字信号处理基于计算机的方法第11章答案Tag内容描述：<p>1、7-1 In a binary communication system the receiver test statistic, ro(t0) =ro, consists of a polar signal plus noise. The polar signal has values so1= + A and so2 = -A. Assume that the noise has a Laplacian distribution, which iswhere so is the rms value of the noise.(a) Find the probability of error Pe as a function of A/so for the case of equally likely signaling and VT having the optimum value.(b) Plot Pe as a function of A/so decibles. Compare this result with that obtain。</p><p>2、3-2 (a) Sketch the naturally sampled PAM waveform that results from sampling a 1-kHz sine wave at a 4-kHz rate.(b) Repeat part (a) for the case of a flat-topped PAM waveform.Solution:3-4 (a)Show that an analog output waveform (which is proportional to the original input analog waveform) may be recovered from a naturally sampled PAM waveform by using the demodulation technique showed in Fig.3-4.(b) Find the constant of proportionality C, that is obtained with this demodulation techn。</p><p>3、7-1In a binary communication system the receiver test statistic,ro(t0) =ro, consists of a polar signal plus noise. The polar signal has valuess s s so1o1o1 o1= = = = + + + +A A A Aands s s so2o2o2o2= = = = A A A A. . . . Assume that the noise has a Laplacian distribution, which is 2|/ 1 () 2 oo n o o f ne = whereois the rms value of the noise. (a) Find the probability of errorPeas a function ofA/ofor the case of equally likely signaling andVThaving the optimum value. (b) PlotPeas。</p><p>4、1 SOLUTIONS MANUAL to accompany Digital Signal Processing: A Computer-Based Approach Fourth Edition Sanjit K. Mitra Prepared by Chowdary Adsumilli, John Berger, Marco Carli, Hsin-Han Ho, Rajeev Gandhi, Martin Gawecki, Chin Kaye Koh, Luca Lucchese, Mylene Queiroz de Farias, and Travis Smith Copyright 2011 by Sanjit K. Mitra. No part of this publication may be reproduced or distributed in any form or by any means, or stored in a database or retrieval system, without the prior written conse。</p><p>5、1 SOLUTIONS MANUAL to accompany Digital Signal Processing: A Computer-Based Approach Fourth Edition Sanjit K. Mitra Prepared by Chowdary Adsumilli, John Berger, Marco Carli, Hsin-Han Ho, Rajeev Gandh。</p><p>6、Chapter 7 7.1 Impulse response of the moving average filter is: = = otherwise., 0 , 10, 1 Mn nh M Its frequency response is: . )2/sin( )2/sin(1 1 11 )( 2/ jM j jM j e M M e e M eH = = = = Now, for a BR transfer function, ., 1)( j eH For the moving-average filter, . )2/sin( )2/sin(1 )( = M M eH j We shall show by induction that ., 1 )2/sin( )2/sin(1 M M Now, for , 2=M., 1)2/cos(。</p>