




文档简介
1 (2005) 368378a of 989. It is to be by as et 3 N r 2005 +H. 1. of of of of by 985, y 1 of as a of et 2 is a in to a in a in to of a In 3is a 1. a at of by is of of to a In a to on is An if it be to to 005 100 d, 1609, 4 004; in 004; 0 004Y. of a at 4a be as 5 s on to ys is q*, at a is to be is gi(as 1)as : To be be a ; i 1;2; .; n, (1)n is of q z0;y0;f0;of of q y N Y. 1 (2005) 368378 369(2)of as by q. (3). be if q. (2) to :9=; 6. (3). If is is at of is by If is at be of a be to 6a be to Z O X Y Z O (x0,y0,1. to N of is no on to a to is by it is as to is to If is is of a to or A to of a is of is to of L:As 3, n; i 1;2; .; n; n be as : : : :2637et 7 to a to It et 8 an to of L( of to of It X of r of as (4) (5) (6)l is an of 6 6 6 46 Y. 1 (2005) 368378370WL: : : :7) n 6; is is n be of n n of to N Y. 1 (2005) 368378 371n n of n to of is to be to on of in n a s 2. Y (a1,b1,2,b2,(x1,y1,(x2,y2,(ai,bi,(xi,yi,(3. A N V X 0. (9) q. (9). an a of 0;0;0;3;0;00;1;1;0;0;00;1;1be be C0 is nd (8) 9) V0. 10(10) q. (11) is 0. (11)(11) r: In to an 1, 0, 0, 0, 0, 0, is is x 0 in of is of is by a is if of X be as of 90j: by 1, 1, 0nd . s) r n of If a n C0 r 0 r; 1r of s) to r : : : : : : :be as X (8)e y;Dz;ax;ay;x, y, z x, y, z of w is by of r Y. 1 (2005) 368378i 1;2; :; .N 0, 0, 10, 2, 1, 00,0, 1, 00, 3, 0, 20,0, 1, 00, 1, 0, 2is 01 3 :s 1;2; :;6l 1;2; :;6 () 6C0 r on a C+ to In a a is on a as 4. of as : 0, 0, 10, 1, 3, 00,2: 0, 0, 10,3,3,00,: V is a q. (11). r be 66637776663777:l 1;2; :;6 is of q. (10) a 101;0 j 1;2; :;6C0 r; 2. C2 n of to a r C2 r a 6C0 r r; 1r of s) to r C2 r :26663777H. Y. 1 (2005) 368378 373010N of 0 0000:50:5 00:51:50:75 5 1:50 00:25 0:25 0 00:5 0000000:5 is as a of of ve A of is of be 0; 0; 0; 0; 0x on an to of 4. Y. 1 (2005) 3683783745 a of in as 1: 0, 1, 00, 896, ,0, 1, 00, 1060, ,0, 1, 00, 1010, , 977, , 977, , 1034, of 1 0 515:000:896001 0378: 1:06000 1 0 612:00:01000:9955 349 0:0880 445 664 0:86380:9955 349 0:0880 728 664 0:82800:0880 0:0170 960 866:6257998 :2466 0:093626666666643777777775,o6 is It is of ve of 1is L; N 10378:001:06000 1 0 612: :01000:9955 349 0:0880 445 664 0:86380:9955 349 0:0880 728 664 0:82800:0880 0:0170 96 866:6257998 :2466 0:of :8768 607 665 21:3716 0:49953:0551 551 448 32:4448 0956 1:0862 12:0648 764 916044 0:0044 0:0061 061 00:0025 025 0:0065 069 0:0007004 0:0004 0:0284 284 is on ve is as 5. 10 (H. Y. 1 (2005) 368378 375:0551 551 448 32:4448 0956 1:0862 12:0648 764 916044 0:0044 0:0061 061 00:0025 025 0:0065 069 0:0007004 0:0004 0:0284 284 o ve to ,1:876860766521:37160:499526666666643777777775551 551 448 32:4448 0956 1:0862 12:0648 764 916044 0:0044 0:0061 061 00:0025 025 0:0065 069 0:0007004 0:0004 0:0284 284 02666666664377777
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 【正版授权】 ISO/IEC TS 33064:2025 EN Information technology - Process assessment - Process assessment model for safety processes
- 2025新款房屋租赁合同范本「官方版」
- 2025二手车买卖租赁合同范本
- 高考试题及答案不得公布
- 分光计考试题及答案
- 防火灾培训考试题及答案
- 动画色彩考试题目及答案
- 中国工业洗瓶剂项目创业投资方案
- 电网营销岗考试题及答案
- 固废处理可行性研究报告
- 2025年下半年四川广元青川县招聘事业单位工作人员18人重点基础提升(共500题)附带答案详解
- 人教版五年级数学上学期第三单元 小数除法综合提优卷(A)(含答案)
- 大庆市2025黑龙江大庆市机关事务服务中心所属事业单位选调工作人员10人笔试历年参考题库附带答案详解
- GB/T 4744-2013纺织品防水性能的检测和评价静水压法
- C语言期末题库(八套试卷)及答案
- 印刷包装企业风险分级管控告知牌
- 等差数列的前n项和 完整版PPT
- JJF 1318-2011 影像测量仪校准规范-(高清现行)
- 小学信息技术五年级全册教案(全面完整版)
- 卫生部心血管疾病介入诊疗技术培训教材(共206页)
- 优才内经复习指导
评论
0/150
提交评论