汇编语言程序设计(习题).ppt

P189 4.10 下面的程序是实现从键盘输入十个一位10进制数后累加。最后累加和以非 压缩BCD码形式存放在AH（高位）和AL（低位）中。 试把程序段中所空缺的指 令填上。 XORBX，BX LOP ：MOVAH，01H INT 21H MOVAH，BH ADDAL，BL MOVBX，AX LOOP LOP 第三章 汇编语言程序设计 MOVCX，10 DAA ANDAL，0FH；纠错 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P189 4.11 下面的程序段的功能是把DA1数据区的数09转换为ASCII码。 试完善本 程序段。 DA1DB 00H，01H，02H，03H，04H，05H DB06H，07H，08H，09H ASCIDB10H DUP（？） CONT=ASCI-DA1 LEASI，DA1 LEADI，ASCI LOP1：MOVAL，SI MOVDI，AL INCSI INCDI LOOPLOP1 第三章 汇编语言程序设计 MOVCX，CONT ORAL，30H Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P190 4.12 BUFFDBABD$QC%$AXYZ CONTEQU$-BUFF CLD LEA DI,BUFF MOVCX,CONT MOVAL,$ XORDX,DX NEXT:REPNZSCASB;搜索BUFF中的“$” CMPCX,0 JZK1 INCDX;”$”的个数加1 JMPNEXT K1: 上述程序段运行后，DX中的值表示的意义是什么？ 第三章 汇编语言程序设计 DX中是$出现的次数。 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P190 4.13设A，B是长度为10的字节数组，用串操作指令编写程序实现AB 两数组的内容相互交换，试完善本程序。 DATASEGMENT ADB1，2，3，4，5，6，7，8，9，0AH ORG0010H BDB0AH，9，8，7，6，5，4，3，2，1 DATAENDS LEASI，A LEADI，B MOVCX，10 LOP：LODSB XCHGAL，DI DECDI STOSB INCDI LOOPLOP 第三章 汇编语言程序设计 CLD；增加指令 XCHGDI，SI XCHGDI，SI Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P191 4.14现有一子程序： 第三章 汇编语言程序设计 （1） 当AL 0且BL 0AL，BL不变 当AL 0且BL 0AL，BL交换 当AL 0且BL 0AL，BL不变 当AL 0且BL 0AL，BL交换 结论：AL，BL为相反数交换，同号则 不变 SUB1PROC TESTAL，80H JEPLUS TESTBL，80H JNEEXITO JMPXCHANGE PLUS：TESTBL，80H JEEITO XCHANGE：XCHG AL，BL EXITO：RET SUBENDP 试回答： （1）子程序的功能是什么？ （2）如调用子程序前AL=9AH，BL=77H ，那么返回主程序时AL=？BL=？ （2）AL与BL为相反数相互交换， AL=77H BL=9AH Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. DATASEGMENT BUFDB58H ASCDB？，？ DATAENDS CODESEGMENT ASSUME CS：CODE，DS：DATA P192 4.19编写一完整源程序，将BUF字节单元存放的两位BCD码，转换为 2字节的ASCII码，并分别存放在ASC和ASC+1字节单元中。 第三章 汇编语言程序设计 START：MOVAX，DATA MOVDS，AX MOVAL，BUF MOVCL，4 SHRAL，CL ORAL，30H MOVASC，AL MOVAL，BUF ANDAL，0FH ORAL，30H MOVASC+1，AL MOVAH，4CH INT21H CODEENDS ENDSTART Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P192 4.20 在A1单元开始定义了一长度为N的字符串，找出其中所有的小写字母存入 到以A2开始的存贮区中。统计出小写字母的个数，存放到SL单元中。请编一完 整的源程序。 数据段如下： DATASEGMENT A1DBASdDpKrJadldjFefASDEF NEQU $-A1 A2DBN DUP (?) SLDB? DATAENDS 第三章 汇编语言程序设计 习 题 课 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. DATASEGMENT A1DBASdDpKrJadldjFefASDEF NEQU $-A1 A2DBN DUP (?) SLDB? DATAENDS CODESEGMENT ASSUME CS：CODE，DS：DATA START:MOVDX，DATA MOVDS，DX LEASI,A1 LEADI,A2 MOVCX,N LOP：MOVAL,SI CMPAL,z JANEXT CMPAL,a JBNEXT MOVDI, AL INCDI INCSL NEXT：INC SI LOOPLOP MOVAH,4CH INT21H CODEENDS ENDSTART 汇编连接EXA31 a b c x y z 61H 62H 79H 7AH 小写字母 算法: CMPAL, z JANEXT CMPAL, a JBNEXT MOVDI, AL NEXT: Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P192 4.20 简化段伪指令 .MODEL SMALL .DATA A1DB AbcdaEFgh N=$-A1 A2DB NDUP(?) SLDB ? .STACK .CODE .STARTUP LEASI,A1 LEADI,A2 MOVCX,N LOP:MOVAL,SI INC SI CMPAL,z；大于z JANEXT CMPAL,a ；小于a JBNEXT MOVDI,AL INC DI NEXT:LOOPLOP SUBDI,OFFSETA2 MOVWORD PTR SL,DI .EXIT END Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P192 4.21 设在DAT单元存放一个-9+9的字节数据，在SQRTAB的数据区中存放 09平方值，请用直接查表方法编写一个子程序，在SQRTAB中查找出DAT单元 中数据对应的平方值送SQR单元。并写出主程序的调用方式。 数据段如下： DATASEGMENT DATDB-8 SQRTAB DB0,1,4,9,16,25,36,49,64,81 SQRDB? DATAENDS 第三章 汇编语言程序设计 习 题 课 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. DATASEGMENT DATDB-8 SQRTABDB0,1,4,9,16,25,36,49,64,81 SQRDB? DATAENDS 第三章 汇编语言程序设计 CODESEGMENT ASSUME CS:CODE,DS:DATA MAINPROC START: MOVAX,DATA MOVDS,AX LEABX,SQRTAB MOVAL,DAT CALLSQRP MOVSQR,AL MAINENDP MOVAH,4CH INT21H SQRPPROC CMP AL,0 JGE NEXT NEG AL NEXT:XLAT RET SQRPENDP CODEENDS ENDSTART MAIN 表：BX=SQRTAB 表：AL=DAT CALL SQRP 保存到SQR 结束 NEG AL AL=0? 查表 返回 SQRP =0 0 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P1924.21简化段伪指令 .MODELSMALL .STACK .DATA DATDB 4 SQRTABDB 0,1,4,9,16,25,36,49,64,81 SQRDB ? .CODE .STARTUP MAINPROC LEABX,SQRTAB MOVAL,DAT CALLSQRP MOVSQR,AL MAINENDP .EXIT SQRPPROC CMP AL,0 JGE NEXT NEG AL NEXT:XLAT RET SQRPENDP END Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. P192 4.22 编写能完成下列要求的程序:测试字 节数据STATUS,若其中位1、3、5有一 位是“1”，程序转至ROUT1，若有二位 是“1”，程序转至ROUT2，若三位都是 “1”，程序转至ROUT3；若这三位没有 一位是“1”，程序转至ROUT4。 DATASEGMENT STATUS DB ROUTDW ROUT4，ROUT1 DW ROUT2，ROUT3 DATAENDS 第三章 汇编语言程序设计 算法： DL逻辑右移两位 CF=1？ SAL SI，1 INC SI 开始 DL=STATUS，SI=0，CX=3 LEA BX，ROUT CX=0？ J y N Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. START:MOV DX,DATA MOV DS,DX MOV SI,0 MOV CX,3 MOV DL,STATUS NEXT:SHR DL,1 SHR DL,1 JNCCF1 INCSI CF1:LOOP NEXT LEABX,ROUT SALSI,1 JMP BX+SI EXIT:MOV AH,4CH INT21H 第三章 汇编语言程序设计 ROUT1: MOV AL,1 JMP EXIT ROUT2: MOV