英文文献-基于FPGA的高速实时数据采集系统的设计与实现

F F 3, , 006 of LC he in a on by of in 4 be up 28 Mb/s by of a by in 1 be an to is be is a it is to l. At be is by In to up of 2005Z) 00876, U 00876, of 00820, D 10052006) 04to to a a at In 4075 is j, = 75 640 32 ( So 4 of a is to to In of 2 3it is to by a a of be by on 5a he of is as a of in 2 of he is on a of be 1. It on a 32 32 CI 2 Mb of as to to on so of 0 2 2 2 006 in CI of in 9052 C 1 of (64075 4 in 30 i To a DC in 2). DC is a to of is to as as a to 3), to -.? I*- I 2 of 00 3 to of )T as a to to of 052 he be to CI 052 be CI of to or be 4 = 128 m/S -, 16-, 2052 a to In cI to 2 33 CI to a be up to 132 to be or Up to up to In o. 4 of is on a 32 32 n et of 3 as CI is 4. E I * I I :0 6 2 CI DC 2 CI 1:0 4 a a as as , as a In a to of rI r Y C, , - r 5 of is 2 DC co cI in eo is 6 of is 2 to to to CI to to to to %, LL 0%. A of is I 4 006 6. . . 6 of of 0 4K 4K I by 4K is rI of is as 1) if 1 1111111111) = 0000000000; = 1; is of (,- = = 01 11 1 11 11 1) - = = 0111111111) )= 0; = I ; if( 01 11 11 11 11 I = 0; or 1 1 11 11 11 1l)= 1; AM 1) - if( 0)= 0 1 ) 1111111111) = 0000000000; = 1; if( 0111111111 or 1= 1 ; = 0; is a if is by of EN be a of be to or to R is is D is is on -3 is to by of to to of is 7. 4 et of 5 * - SA - Q3 1 :O A 1 :O * :O * is SM of is 8. is 1 8 SM of n of be to to In MC in to M1 of 9. 1) of on to M1 by 2) to of as as to of V 5 V ( (DC ( at a DC 3) as to as on as to to 4) W by is of to 4 a on CI by of a by in in an as CI 4 be up 28 MB/s. 0 is by 60330271018). . et of of 2004, 1 l(2): 802003 052 2000 Xi2003: 59, , , et A to 2002, 49(3): 1190. M, u, C J, et A 1020s 2002,37(12): 1618. 3. 4. 5. 66 006 , , , e