毕业设计—装配式钢筋混凝土简支T梁桥课程设计.pdf

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(kn)? 1-8 ? )( 2 1 1 100 = += n j qjk qjc kq n i q gik gi udssss ? ? ? 1?2?3?4?5 ml 2/ 818.01353.796.822686.697 ml 4/ 613.51014.5171.662013.096 ql 2 / 0137.284.97177.983 1 ? 5 q0167.8236.4424.92504.258 ml 2/ 851.81105.7862.602376.328 ml 4/ 638.8829.3346.951782.185 ql 2 / 0112.223.21144.633 2 ? 4 q0174.72184.7810.43432.034 ml 2/ 851.8858.8657.042059.604 ml 4/ 638.8644.1342.781544.63 ql 2 / 087.162.93112.775 3 q0174.72296.439.01571.282 ?0? ? c? !“#? ? ? ! 13 ? ? ? ? ? ? ?m d? ?!“#$%?ab?c?defg )(5 .1195 .10130 0 cmah h = “# 1-1 $% t .130c89:1f cd =13.8mpa6 b77t r?= h b a f s ?o?i?() ?i?()fghfg n 3? cm b f b f x f hbfaf cd cd s sd 14.8 1813.8 1118-15013.8-84.7280 )( = = = ? ?i?3 ? ? ? ? .m2686.697knm2672.69kn. 2/11. 01.850.110.18-1.508 .13 0.148/2-1.1850.1480.188 .13) 2 ()( 2 10 10 3 3 0 0 = + =+= h hhb f h f m f cdcd df b f x bx ?4?i?*+? ? ? ?e 4 ?3?3!“#-(?%(15.125 2 7 . 3 3130 2 3130;358.20 0 2 cm d hcmag = 9037. 01009.037 125.1518 358.20 )/( 10 3- 0 = =pbh ag ?571.282kn 0 = vd ? bcde? xfa ? 18 ? ? ? mm sv 159 180195100.6300.90370.620.2 282.5710.6 1251.5101 . 10 . 1 2 2-622 = + = gymm sv 150=? hh?i?9.3.13 ?jkml_mnlo?!) 1 p?rqrs?t?uv!w s* 100mm? xdyz?t?|ao? ?d?9y8 oa46 ? 3 ?66?x?$? ?b66, c?3 mm sv 001=fa0.0056 1018 1.006 = = b s a v v sv mm sv 150=0.0037 1518 1.006 = = b s a v v sv ?s*?q?)|t?ar235 ?!)* 0.18%?#.? ? ? ?t?sg) hijkl?ana4 ?kp?sgtu() c3ee”?ud?3 ?a deef.?ag? ?4o66d 0.02291118-15015.1251884.7/=+=? w ? ?e? ?e? ? 19 ?mkn mmmssmp agqjk n j j m i giks .1862.4196.821.07 .13537 . 0818.0 0 . 1 7 . 0 1 1 1 =+= +=+= + = ?e? ?mkn mmmssmp agqjk n j j m i gikl .1398.2196.824 . 07 .13534 . 0818.0 4 . 0 4 . 0 1 2 1 =+= +=+= + = g?f?:a 1.375 1862.41 1398.215 . 0 1 0.5 1 )/(20.17 1.251584.787 . 0 41.1862 87 . 0 2 24 4- 0 10 10 = +=+= = = n n c m ha m s l s s ss kn es?hrb335 ?a mpa 10 5 0 . 2?bc2xfa )(2 . 0mm0.169 0.0229100.28 3230 2.0 20.17 011.3750 . 1 10 10 8 4 mm wfk = + + =? ? ? ?!“#$?% ? a?ba4 )cde%?feghi%&-jk ?a4?l 0013. 0)/(,018. 3 2 =bh a cm ass ? mn o-oop?bo?oo? qr?sf- ?tuvwx?ykwz?( ?_?p ? ?_? ?5a mpa mpa s cr s cr b e f ws w f m b b m m m m b c tk tk cr cr 10 )()( 4 00 0 0 22 0 0 . 3 2.01 /2 1 = = = + = ? bcas0ddefgh!ijk%lmfgnopfqrstnop)guv- ?wddmfgcxpy z 6g)y|-w ?b+a 0)()( 2 1 2 1 0 2 1 2 1 )( = xnb ha tx bxb s ?a ? 20 mmcmx x x x xx 2544 .25 085.1832204 0)118.5(84.70.667)18180( 2 1 180 2 1 2 2 2 )11( = =+ = ? ? ? ? m s 3767 0 101010 5.11681.866244.9302 2 110-254 180110-254110/2-2541101800 =+= += efgtno)?xva ?mm i 410 010 8948. 6= efg?%?x?va ? ? mmn w f m ws mmxhiw tk cr .057. 2 382. 1/2 7.4058)254-1185/(8948. 6)/( 10 1010 8 0 00 2710 0000 = = = icrk%fg)?xv?b?a mm tx bxb x hai bn scr 41010 3 3 2 3 1 3 1 2 1010 )110254( 254 )2541185( )()( 5.716540.16124-0.983224.89456 )1801800( 3 1 1800 3 1 84706676. )( 3 1 3 1 0 =+= += += ? mmnmkn c c m i eb i eb s cr cr .86241 . 1 .41.1862 1.9650.95 715 . 1 10 10 10 9 15 0 0 15 = = = ? mm b b m m m m b n s cr s cr b cr 215 15 15 22 15 0 22 0 .1.6819 1.715 1.965 9 8 1 9 8 1.965 1 10 10 10 ) 10 86241. 1 10 057. 2 () 10 86241. 1 10 057. 2 ( 10 )()( = + = + = ?q?)? )?nhi)$?v?vm gk 4p4?hi)$ ?)?vh!?l= mqk po?p?3 ?hi)$?vm rk ?2?4? ? hpl?6)? ?5?6)?!? ?nhi)?(?!? ?-ls?hi)c?(a ? 21 ? ? ? 25. 3 600 1950 600 11. 30.0311 1.681948 82.961041.37 . 05 6 . 1 48 5 6 . 1 10 19.510 0.7 9 23 2 cm l cmm b f lmmrk qk = + = + = h?l/“=?( ?*+?fi 1fl ?ij?fi 1hi)?(“ #?) pp?oo ?1= + = + ? ?3? ?*+?(? ?n p? s?hi)? (- ? ? ? 64. 40464. 0 48 ) 5 6 . 1 48 5 6 . 1 2 2 0.7( 2 1 2 1 cmm b gk b gk f lmmmlm m rk qk = + = = + ? ? t”?6)?6?6c)6?$?6cfg? ?$!?*?c6cr)?6se?- pt5?k?c6q)?atc6)$!?= ?p ?- ?p?c6)?h?a?l cd?tc6)?a ?v?akny pq p kk oq 144.46)1.02381.024.85 2 1 5 .10( 2 1 )( 2 1 =+=+= ?akn poq 173.35144.461.2= ?t?c6cr)? ?g?o?s?)? pt? 6)ds? ? ? 22 l mr)?s?a ?p ?k? p 6pq/h-0.1940.594 1511 = ?l a -0.7471.821-1.810.3971.82945 . 0 211.02 2111 1 =+= +=ddd m r ?p ?k? _ 6pq/a -0.6861.810.0031.820.194- 1.02 5251 5 =+= += ? dd m r mr)?s?a ?p ?k? ? 6pq/h0.2990.397 2212 = ?l a ? 23 671 . 01.811-1.81.0299 . 0 1.820.3