复数的基本运算(C语言).doc

。#include#includetypedef struct fushu/抽象数据类型定义float real;/数据对象float image;fushu;fushu ComplexNumberInput(float a,float b)/构造二元组fushu c;c.real=a;/实部c.image=b;/虚部return(c);fushu ComplexNumberAdd(fushu c1,fushu c2)/求和运算fushu sum;sum.real=c1.real+c2.real;sum.image=c1.image+c2.image;return (sum);fushu ComplexNumberSub(fushu c1,fushu c2)/求差运算fushu sub;sub.real=c1.real-c2.real;sub.image=c1.image-c2.image;return (sub);fushu ComplexNumberMul(fushu c1,fushu c2)/求积运算fushu Mul;Mul.real=c1.real*c2.real-c1.image*c2.image;Mul.image=c1.real*c2.image+c1.image*c2.real;return (Mul);fushu ComplexNumberDiv(fushu c1,fushu c2)/求商运算 fushu div; float d1,d2,d3,d4; d1=c1.real*c2.real+c1.image*c2.image; d2=c2.real*c2.real+c2.image*c2.image; d3=c1.image*c2.real-c1.real*c2.image; d4=c2.real*c2.real+c2.image*c2.image; if(d2!=0&d4!=0) div.real=d1/d2; div.image=d3/d4; return(div); else div.real=0; div.image=0; return(div); void ComplexNumberOutput(fushu c)/输出运算结果if(c.real=0.0&c.image=0.0) printf(0n); if(c.real=0.0&c.image!=0.0) printf(%fin,c.image);if(c.real!=0.0&c.image=0.0) printf(%fn,c.real);if(c.real!=0.0&c.image!=0.0) printf(%f+(%fi)n,c.real,c.image);void main()/主函数int choice;int k;float a1,a2,b1,b2;struct fushu c1,c2,sum,sub,mult,div;printf(欢迎进行复数的基本代数运算n);printf(1: 复数加法运算n);printf(2: 复数减法运算n); printf(3: 复数乘法运算n);printf(4: 复数除法运算n);printf(0: 推出系统n);printf(请分别输入第一个复数的实部和虚部: );scanf(%f%f,&a1,&b1);c1 = ComplexNumberInput(a1,b1);printf(第一个复数为: );ComplexNumberOutput(c1);printf(请分别输入第二个复数的实部和虚部: );scanf(%f%f,&a2,&b2);c2 = ComplexNumberInput(a2,b2);printf(第二个复数为: );ComplexNumberOutput(c2);for(;)printf(请输入你选择的功能: );scanf(%d,&choice);switch(choice)case 0:exit(0);break;case 1:sum = ComplexNumberAdd(c1,c2);printf(求和后结果为: );ComplexNumberOutput(sum);break;case 2:sub = ComplexNumberSub(c1,c2);printf(求差后结果为: );ComplexNumberOutput(sub);break;case 3:mult = ComplexNumberMul(c1,c2);printf(求积后结果为: );ComplexNumberOutput(mult );break;case 4:div=ComplexNumberDiv(c1,c2); if(div.real!=0&div.image!=0) printf(求商后结果: ); ComplexNumberOutput(div); break; else