Java计算器.docx

Java平台第一版版最后结果如图：可实现连等、连加、开平方、正负运算。代码：import java.awt.BorderLayout; /还可以增加的功能，整数运算超过Long上限的提示。 -ANS的快速显示 import java.awt.GridLayout; import java.awt.event.ActionEvent;import java.awt.event.ActionListener;import java.awt.event.KeyAdapter;import java.awt.event.KeyEvent;import javax.swing.JButton;import javax.swing.JFrame;import javax.swing.JPanel;import javax.swing.JTextField;public class MyCalculator extends KeyAdapter implements ActionListener Override public void keyPressed(KeyEvent e) throws java.lang.NumberFormatException / TODO Auto-generated method stub if (e.getKeyCode()=KeyEvent.VK_0 & e.getKeyChar()1) str=str.substring(0,str.length()-1); totle=totle.substring(0,str.length()-1); else System.out.println(e.getKeyCode(); throw new java.lang.NumberFormatException(); Override public void actionPerformed(ActionEvent e) String s = e.getActionCommand();/返回键的值 if (index=1) MyCalculator.str+=s; totle+=s; text.setText(px+totle); else MyCalculator.ano+=s; totle+=s; text.setText(px+totle); private JFrame board=new JFrame(Calculator by XTANMY);private JPanel p=new JPanel();static JTextField text= new JTextField();private JButton b0=new JButton(0);private JButton b1=new JButton(1);private JButton b2=new JButton(2);private JButton b3=new JButton(3);private JButton b4=new JButton(4);private JButton b5=new JButton(5);private JButton b6=new JButton(6);private JButton b7=new JButton(7);private JButton b8=new JButton(8);private JButton b9=new JButton(9);private JButton sum=new JButton(+);private JButton equ=new JButton(=);private JButton dot=new JButton(.);private JButton min=new JButton(-);private JButton mul=new JButton(*);private JButton div=new JButton(/);private JButton fu=new JButton(+/-);private JButton sq=new JButton(sqrt);private JButton clr=new JButton(C);static String px= ; /可以不用px,使用replace()static String totle= ; /用于显示static String str=0; /为空是不能parseInt的，加0不影响数值static String ano=0; static int index=1;/标示第一个数还是第二个数 static int in=0;/标示是整数还是实数static char op;/操作符static boolean now=false;/标示是否连等static boolean jump=false;/标示是否从整除跳到实数除static Long a=0l;static Long b=0l;static Double c=0.0;static Double d=0.0;static int flag1=1; /表示负号static int flag2=1;static boolean dotonly=true;/只能加一个小数点void first() text.setHorizontalAlignment(JTextField.LEFT);text.addKeyListener(this);/ board.addKeyListener(this);board.setResizable(false);/不能最大化board.getContentPane().add(text,BorderLayout.NORTH);board.getContentPane().add(p,BorderLayout.SOUTH); board.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);void second()p.setLayout(new GridLayout(4,5);p.add(b7);p.add(b8);p.add(b9);p.add(div);p.add(mul);p.add(b4);p.add(b5);p.add(b6);p.add(min);p.add(sum);p.add(b1);p.add(b2);p.add(b3);p.add(dot);p.add(sq);p.add(b0);p.add(fu);p.add(clr);p.add(equ);b0.addActionListener(this);b1.addActionListener(this);b2.addActionListener(this);b3.addActionListener(this);b4.addActionListener(this);b5.addActionListener(this);b6.addActionListener(this);b7.addActionListener(this);b8.addActionListener(this);b9.addActionListener(this);sum.addActionListener(new sum();equ.addActionListener(new equ();dot.addActionListener(new dot();min.addActionListener(new min();mul.addActionListener(new mul();div.addActionListener(new div();fu.addActionListener(new fu();sq.addActionListener(new sq();clr.addActionListener(new clr();board.pack();board.setVisible(true);board.setLocationRelativeTo(null); /设置窗口居中显示 static void clr()now=false;jump=false;index=1;op= ;a=0l;b=0l;c=0.0;d=0.0;str=0;ano=0;in=0;flag1=1;flag2=1;dotonly=true;totle= ;px= ;text.setText(0); return;static void play()/整数相加,相减，相乘，不提供相除if (str.length()=1 & ano.length()!=1 & !now)/解决在结果上继续算的问题 now=true; /此时不读c,只读d b=Long.parseLong(ano)*flag2; if (ano.length()=1 & !now & op!= ) /第二个数没值 /用来解决结果为25时，计算25*=625. if (str.length()1) a=Long.parseLong(str)*flag1;/读第一个值 / System.out.println(a);b=a; now=true;/不按普通方法读俩数 index =-1; /不让a乘两遍flag1 if (!now & op!= ) a=Long.parseLong(str)*flag1; b=Long.parseLong(ano)*flag2;Long c; /包装器才有toString方法if (op=/ & b=0) /除数不能为0 text.setText(除数不能为0,自动复位); now=false;jump=false;index=1;op= ;a=0l;b=0l;str=0;ano=0;in=0;flag1=1;flag2=1;dotonly=true;totle= ;px= ;return;if (op=/& a%b!=0) now =true; jump=true;/ System.out.println(jump); play2(); return; /必须return啊。不然执行下个switch。if (now & index!=-1)a=a*flag1;/1、6*6 2、+/- = 参考windows计算器结果为-36*6switch (op)case +:c=a+b;text.setText(c.toString();a=c;now=true;index=1;str=0;ano=0;in=1;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;case -:c=a-b;text.setText(c.toString();a=c;now=true;index=1;str=0;ano=0;in=1;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;case *:c=a*b;text.setText(c.toString();a=c;now=true;index=1;str=0;ano=0;in=1;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;case /:c=a/b;text.setText(c.toString();a=c; now=true;index=1;str=0;ano=0;in=1;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;static void play2() /实数相加、相减、相乘、相除if (str.length()=1 & ano.length()!=1 & !now)/解决result*5=5result问题 now=true; /此时不读c,只读d d=Double.parseDouble(ano)*flag2; if (in=1) c=(double) a; /解决Ans*1.0 ans为整数的问题。 if (ano.length()=1 & !now & op!=s & op!= ) /第二个数没值 if (c=0 | str.length()1) c=Double.parseDouble(str)*flag1; d=c; now=true; index=-1; if (!now & op!= ) c=Double.parseDouble(str)*flag1; d=Double.parseDouble(ano)*flag2;Double x;if (jump) /jump过来的d先赋值c=(double) a;d=(double) b;jump=false;if (op=/ & d=0) /除数不能为0 text.setText(除数不能为0,自动复位); now=false;jump=false;index=1;op= ;a=0l;b=0l;c=0.0;d=0.0;str=0;ano=0;in=0;flag1=1;flag2=1;dotonly=true;totle= ;px= ; return;/else if (op=/ & c%d=0)/play();if (op=s & in=1) c=(double) a*flag1; now=false; /防止乘两遍flag1 if (now & index!=-1) /解决9+6=15，- = -15+6=-9的问题c=c*flag1;if (op=s & c0)text.setText(被开方数必须为正，自动复位);now=false;jump=false;index=1;op= ;a=0l;b=0l;c=0.0;d=0.0;str=0;ano=0;in=0;flag1=1;flag2=1;dotonly=true;totle= ;px= ;return;int m=0,n=0; /按小数精度运算if (c.toString().contains(.) m=c.toString().length()-c.toString().indexOf(.)-1;if (d.toString().contains(.) n=d.toString().length()-d.toString().indexOf(.)-1;int sum=m+n;if (mLong.MAX_VALUE)/得有绝对值，因为可能为负的sum-;/System.out.println(flag1+,+flag2);switch (op)case +:x=Math.round(c+d)*Math.pow(10,m)/Math.pow(10,m);text.setText(x.toString();c=x;now=true;index=1;str=0;ano=0;in=2;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;case -:x=Math.round(c-d)*Math.pow(10,m)/Math.pow(10,m);text.setText(x.toString();c=x;now=true;index=1;str=0;ano=0;in=2;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;case *:x=Math.round(c*d)*Math.pow(10,sum)/Math.pow(10,sum);text.setText(x.toString();c=x;now=true;index=1;str=0;ano=0;in=2;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;case /:x=c/d;text.setText(x.toString();c=x;now=true;index=1;str=0;ano=0;in=2;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;case s:x=Math.sqrt(c);text.setText(x.toString();c=x;now=true;index=1;str=0;ano=0;in=2;flag1=1;flag2=1;MyCalculator.dotonly=true;totle=;px=;break;static void change() /防止显示-形式 if (MyCalculator.totle.charAt(0)=-)if (totle.charAt(0)=- & px= )px=-;totle=totle.replace(-, );if (totle.charAt(0)=- & px=-)px= ;totle=totle.replace(-, );public static void main(String args) throws java.lang.NumberFormatException MyCalculator my=new MyCalculator(); my.first(); my.second();class sum implements ActionListener Overridepublic void actionPerformed(ActionEvent e)/ TODO Auto-generated method stub MyCalculator.index=2; MyCalculator.op=+; MyCalculator.now=false; MyCalculator.dotonly=true; if (MyCalculator.str.length()=1 & MyCalculator.in=2) /该if解决ANS/5的显示问题 MyCalculator.totle=MyCalculator.c.toString(); else if (MyCalculator.str.length()=1 & (MyCalculator.in=1| MyCalculator.in=0) MyCalculator.totle=MyCalculator.a.toString(); MyCalculator.change(); MyCalculator.totle+=+ ; /e.getCommand()+ ;也可以 MyCalculator.text.setText(MyCalculator.px+MyCalculator.totle);class min implements ActionListener Overridepublic void actionPerformed(ActionEvent e)/ TODO Auto-generated method stub MyCalculator.index=2; MyCalculator.op=-; MyCalculator.now=false; MyCalculator.dotonly=true; if (MyCalculator.str.length()=1 & MyCalculator.in=2) MyCalculator.totle=MyCalculator.c.toString(); else if (MyCalculator.str.length()=1 & (MyCalculator.in=1| MyCalculator.in=0) MyCalculator.totle=MyCalculator.a.toString(); MyCalculator.change(); MyCalculator.totle+=- ; MyCalculator.text.setText(MyCalculator.px+MyCalculator.totle);class mul implements ActionListener Overridepublic void actionPerformed(ActionEvent e)/ TODO Auto-generated method stub MyCalculator.index=2; MyCalculator.op=*; MyCalculator.now=false; MyCalculator.dotonly=true; if (MyCalculator.str.length()=1 & MyCalculator.in=2) MyCalculator.totle=MyCalculator.c.toString(); else if (MyCalculator.str.length()=1 & (MyCalculator.in=1| MyCalculator.in=0) MyCalculator.totle=MyCalculator.a.toString(); MyCalculator.change(); MyCalculator.totle+=* ; MyCalculator.text.setText(MyCalculator.px+MyCalculator.totle);class div implements ActionListener Overridepublic void actionPerformed(ActionEvent e)/ TODO Auto-generated method stub MyCalculator.index=2; MyCalculator.op=/; MyCalculator.now=false; MyCalculator.dotonly=true; /MyCalculator.in=2; if (MyCalculator.str.length()=1 & MyCalculator.in=2 ) MyCalculator.totle=MyCalculator.c.toString(); else if (MyCalculator.str.length()=1 & (MyCalculator.in=1| MyCalculator.in=0) MyCalculator.totle=MyCalculator.a.toString(); MyCalculator.change(); MyCalculator.totle+=/ ; MyCalculator.text.setText(MyCalculator.px+MyCalculator.totle); class equ implements ActionListener Overridepublic void actionPerformed(ActionEvent e)/ TODO Auto-generated method stubif (MyCalculator.str.contains(.) | MyCalculator.ano.contains(.)| (MyCalculator.str.length()=1 & MyCalculator.in=2 ) )/length为 /1和equals0等价。实数(op)一个数则结果应也为实数。MyCalculator.play2();else MyCalculator.play();class dot implements ActionListener Overridepublic void actionPerformed(ActionEvent e) if (MyCalculator.index=1 & MyCalculator.dotonly) MyCalculator.str+=.; MyCalculator.dotonly=false; MyCalculator.totle+=.; MyCalcul