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balanced and run the satisfaction of the people education. Room XX City Bureau of educational supervision of XX municipality May 6, 2016 County economic information and Business Council System Committee two learn a do learning arrangements specific programme for advance full strictly rule party, according to County Organization Department on County two learn a do learning arrangements of specific programme and I Board learning education implementation programme spirit, according to distinguish level, and has targeted solution problem of requirements, ensure learning education made effectiveness, promote all members consciously respected Constitution, and comply with party rules, with XI General Secretary series important speech spirit armed mind, and guide practice, and Promote the work and be qualified party members and learning arrangements are hereby makes the following specific programmes. Learning requirements, on all party members to study the party Constitution and party rules and unify the XI series of important speech, General Secretary, speech learning series to deepen understanding of the Constitution Party rules, Constitution Party rules in the deep insight series address the basic spirit and practical requirements. 1. Constitution Party rules. Learning of the party Constitution, a deep understanding of the partys nature, purpose, guiding principles, goals, organization, good style, grasp conditions, rights and obligations of party members, bearing in mind that oath, clear qualified party member criteria and conditions. Learning the code of self-discipline of the CPC, the CPCs disciplinary regulations, the Chinese Communist Party Member Rights Ordinance and so on, mastering self-discipline standards of four must, the four upholdings, mastering various types of disciplinary offence and punishment provisions. 2. series spoke. To XI General Secretary series important speech reading (2016 version) and out poverty for basic textbook, learning understand XI General Secretary series important speech of basic spirit, learning understand Central ruling acting political new concept new thought new strategy of basic content, learning understand XI General Secretary in Fujian work during advocate of four grassroots immediately on do drop weak bird first fly and the in Nanping research study proposed of gravity Xia moved, and innovation mechanism, important thought, Master and strengthen the party spirit, fulfills the purpose ideas, moral character, conservation related to the basic requirements. Main understand master following aspects content: (1) ideal faith is Communists spirit Shang of calcium, set right of worldview, and Outlook on life, and values; (2) China dream is national of dream, and national of dream, and people of dream, is Chinese modern yilai most great of dream, core Essentials is national prosperity, and national revitalization, and people happiness; (3) China features Socialist is achieved Chinese great revival of way, enhanced road confidence, and theory confidence, and system confidence; (4) four a full Strategy layout is new of history conditions Xia party ruling acting political total strategy, consciously with four a full led the work; (5) insisted innovation, and coordination, and green, and open, and shared development is relationship China development global of one deep change, according to new development concept do job; (6) practice line Socialist core values, promote Socialist thought moral and Chinese traditional virtue一、课程设计目的 加深对C语言课程所学知识的理解,进一步巩固C语言语法规则。学会编制结构清晰、风格良好、数据结构适当的语言程序,从而具备解决综合性实际问题的能力, 使学生通过系统分析、系统设计、编程调试,写实验报告等环节,初步掌握软件系统设计的方法和步骤,训练灵活运用程序设计语言进行软件开发的能力,提高分析问题和解决问题的能力,提高程序设计水平,培养必要的工程实践动手能力二、课程设计内容 学生学籍管理系统1, 输入并验证密码;2, 设计菜单进行选择相应的操作;3, 用链表录入并输出数据,包括学生的户籍、成绩、奖惩信息;4, 将录入的数据存放在文件里面并读取文件;5, 对录入的数据进行修改;6, 删除个人信息;7, 查找个人信息;8, 对录入的成绩进行排序;9, 统计不及格的成绩;10, 释放链表;三、需求分析对所开发系统功能、性能的描述,想要实现的目标。输入并验证密码的正确性,定义结构体类型来存放学生的基本信息(包括学生的姓名、学号、性别、出生日期等),然后建立链表存放信息,将信息存入文件中,以便以后的各个功能模块调试时直接调用,对数据进行修改、删除、查找、排序操作,然后对输入的数据进行统计,查出不及格的学生成绩。实现的目标是对学生的学籍进行管理,更新并统计数据。 四、概要设计输入数据函数输出数据函数查找数据函数删除数据函数输 入 密 码修改数据函数主 菜 单保存文件函数读取文件函数排序函数统计函数退出系统功能模块说明:输入密码:从键盘输入密码,判断输入的密码是否与系统设定的密码相同,若相同则进入主菜单,不相同则继续输入; 主菜单:显示系统的各项功能与相对应的数字选项。输入数据函数:从键盘输入数据,并将数据存入链表。输出数据函数:对存储的数据进行输出。查找数据函数:对存储的数据进行查询并显示查询结果。删除数据函数:对存入的数据进行删除。修改数据函数:对存入的数据进行修改。保存数据函数:将从键盘输入的数据存入到文件中读取数据函数:从文件中读取个人信息。排序函数:对平均成绩进行排序并显示排序结果统计函数:对不及格成绩进行统计并显示统计结果。退出系统:退出系统五、详细设计及运行结果流程图错误 判断正确性主菜单正确 修改数据是选择5选择1选择3选择2选择4否否否否是是是是从键盘输入数据并存入链表输出数据查找个人信息删除数据否是保存文件选择6否是读取文件选择7否 是对成绩进行排序选择8否是统计不合格的成绩选择9选择0退出六、调试情况,设计技巧及体会 通过两周的课程设计,我对学过的C语言基本知识进行了巩固,并且还对知识进行了扩展。在本次实习时,刚开始完全没有头绪,不知道从何入手,感觉难度很大.但是逐渐开始编写程序慢慢发现,原来不是想象中的那么难.在一个个模块成功编写出来的同时,获得了巨大的成就感,并且掌握的许多上课遗漏和不很了解的知识.。对一些细节以前不太注意,常常忽略,真正操作起来时发现一些小问题也会导致程序无法进行。要想运行正常,必须保证零错误。 同时,这两周的实习使我对链表更熟悉了。以前总感觉链表很难,这次程序设计中,我用链表存取数据,并进行删除修改等操作,慢慢对链表熟悉。另外,在程序运行编译的过程中出现一些错误,需要耐心的去检查错误,调试程序。七、参考文献C语言程序设计 谭浩强 清华大学出版社C语言程序设计教程 张毅坤 曹锰 张亚玲 西安交通大学出版社C语言程序设计 王曙燕 曹锰 科学出版社 #include #include #include #include #include #include #include #define LEN sizeof(struct student)typedef struct int year; int month; int day; DATE; struct student int num; char name10; char sex; DATE birthday; int math; int C; int physic; int English; float average; DATE time; char reason50; char result50; char unit50; struct student *next;struct student * read_file(); /*读取文件*/void save_file(); /*保存*/void input(); /*创建链表,输入数据*/void output(struct student *head); /*输出*/void seek(struct student *h); /*查找*/void del() ; /*删除*/void change (); /*修改*/void sort() ; /*对成绩进行排序*/void summarise(); /*对不及格成绩进行统计*/void free_linklist(void); /*释放链表*/void print(struct student *p); /*输出函数*/void menu(); /*菜单*/void password(); /*密码*/struct student *head=NULL;int number=0;main() password(); getch(); system(cls); printf(nnnnnttt*欢迎进入学生学籍管理系统*nnn); getch(); menu();void password() char s8,ch; int i; s0=0;s1=4; s2=0; s3=8 ; s4=2; s5=0; s6=4; s7=1 ; printf(nnnnnttt*nn); printf(ttt*nn); printf(ttt*nnnnn); do printf(ttttplease input password: nttttt); for(i=0;inum); fflush(stdin); scanf (%s,p1-name); fflush(stdin); scanf (%c,&p1-sex); fflush(stdin); scanf (%d%d%d,&p1-birthday.year,&p1-birthday.month,&p1-birthday.day); printf (score information:n); printf (math C physic Englishn); scanf (%d%d%d%d,&p1-math,&p1-C,&p1-physic,&p1-English); p1-average=(float)(p1-math+p1-C+p1-physic+p1-English)/4; printf( rewards and punishments:n); printf ( time(year month day )n); scanf (%d%d%d,&p1-time.year,&p1-time.month,&p1-time.day); printf (reason: ); fflush(stdin); scanf (%s,p1-reason); printf (result: ); fflush(stdin); scanf (%s,p1-result); printf (unit: ); fflush(stdin); scanf (%s,p1-unit); p1-next=NULL; number+; if(head=NULL) head=p1; else p2=head; while (p2-next ) p2=p2-next; p2-next=p1; getch();void output(struct student *head) /*输出链表*/ struct student *p; int kind,flag=1; char choice=a; if (head=NULL) printf(Not Input before!n); getch(); return; while (flag) printf (students information input before as fowllow:n); printf (1:address; 2:score; 3:rewards and punishments 0:exitn); printf (please choice: ); scanf (%d,&kind); p=head; do switch(kind) case 1: printf (address information:n); printf (num name sex year month day n); printf (%d %s %c ,p-num,p-name,p-sex); printf ( %d %d %dn,p-birthday.year,p-birthday.month,p-birthday.day); break; case 2: printf (score information:n); printf (num name math C physic English averagn); printf (%d %s %d %d %d %d ,p-num ,p-name , p-math,p-C,p-physic,p-English); printf (%2.2fn,p-average); break; case 3: printf( rewards and punishments:); printf (num : %d name %s n,p-num,p-name); printf (time: year/%d month/%d day/%d n,p-time.year,p-time.month,p-time.day); printf(reason: %sn,p-reason); printf(result: %sn,p-result); printf (unit: %sn,p-unit); break; p=p-next; while(p); printf (continue to choice (y/n) ); fflush(stdin); choice=getchar(); if(choice=n) flag=0; printf(Display finish!n); getch();void seek(struct student *h) /*查找链表*/ struct student *p; int seeknum; printf (please input the num what you look for :); scanf (%d,&seeknum); p=h; while (p&seeknum!=p-num) p=p-next; if(!p) printf (the num you look for dont exist!n); else print(p); getch();void del () /*删除链表*/ int delnum; struct student *p1,*p2; p1=head; printf(input delete num:n); scanf(%d,&delnum); while (delnum!=p1-num&p1-next!=NULL) p2=p1; p1=p1-next; if (delnum=p1-num) if (p1=head) head=p1-next; else p2-next=p1-next; printf (the students information you input have been deleted!n); number-; else printf (the student you what to delete dont exist!n); getch();void change() /*修改链表*/ int changenum,kind; int choice,flag=1; char select=1; struct student *p; p=head; while (flag!=0) printf (please input the num you want to change:n); scanf (%d,&changenum); while (changenum!=p-num) p=p-next; if (changenum=p-num) printf (input the new information:n); printf (1:address ; 2:score ;3: rewards and punishments; 0:exit;n); printf(input the kind you want to change:); fflush(stdin); scanf(%d,&kind); switch(kind) case 1: printf (1: name; 2:sex; 3:birthday;); printf (please choice :); fflush(stdin); scanf (%d,&choice); switch (choice) case 1: printf (input the new name:); fflush(stdin); scanf (%s,p-name); break; case 2: printf (input the new sex:); fflush(stdin); scanf(%c,&p-sex); break; case 3: printf (input the new birthday:); fflush(stdin); scanf(%d%d%d,&p-birthday.year,&p-birthday.month,&p-birthday.day); break; break; case 2: printf (1:math; 2:C; 3: physics; 4:English;); printf (please choice :); fflush(stdin); scanf (%d,&choice ); switch (choice) case 1: printf (input the new math:); fflush(stdin); scanf (%d,&p-math); break; case 2: printf (input the new C:); fflush(stdin); scanf (%d,&p-C); break; case 3: printf (input the new physic:); fflush(stdin); scanf (%d,&p-physic); break; case 4: printf (input the new English:); fflush(stdin); scanf (%d,&p-English); break; break; case 3: printf (1: time; 2:reson; 3: result; 4: unit;); printf (please choice:); fflush(stdin); scanf (%d,&choice); switch (choice) case 1: printf (input the new time:); fflush(stdin); scanf (%d%d%d,&p-time.year,&p-time.month,&p-time.day); break; case 2: printf (input the new reason:); fflush(stdin); scanf (%s,p-reason); break; case 3: printf ( input the new result :); fflush(stdin); scanf (%s,p-result); break; case 4: printf (input the new unit:); fflush(stdin); scanf (%s,p-unit); break; else printf (the num you want to change dont exist!n); printf( continue to change ?(y/n); fflush(stdin); select=getchar(); if(select=n) flag=0; else printf (continue!n); print(p); getch();void save_file() /*保存文件*/ FILE *fp; struct student *stu; char filename10; printf (input infile name:n); scanf (%s,filename); if (fp=fopen(filename,wb+)=NULL) printf (cannot open file!); exit(0); stu=head; do if(fwrite(stu,LEN,1,fp)!=1) printf (file write error!); stu=stu-next; while(stu); printf (the file has been kept!n); fclose (fp); getch();struct student * read_file() /*读取文件*/ FILE *fp; char filename10; struct student *p,*head=NULL,*stu; printf (please input filename:n); scanf(%s,filename);
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