C#中Z顺序的说明.docx

关于C# 中Z顺序的含义：关于sendtoback和bringtofront的使用探底：鄙人薄见初始界面：1. 若果不使用sendtoback和bringtofront，仅在同一Z面上进行操作，代码如下：试验按钮为：button1;（1）代码段1-1:private void button1_Click(object sender, EventArgs e) button1.Dock = DockStyle.Bottom; button2.Dock = DockStyle.Bottom; button3.Dock = DockStyle.Bottom; button4.Dock = DockStyle.Bottom; button5.Dock = DockStyle.Bottom; button6.Dock = DockStyle.Bottom; button7.Dock = DockStyle.Bottom; button8.Dock = DockStyle.Top; 运行代码段1-1之后：界面显示结果如下：（2）代码段1-2：仅在同一Z面上进行部分按钮的dock属性设置，结果会怎样？代码段1-2：private void button1_Click(object sender, EventArgs e) button1.Dock = DockStyle.Bottom; button2.Dock = DockStyle.Bottom; button3.Dock = DockStyle.Bottom; button4.Dock = DockStyle.Bottom; button8.Dock = DockStyle.Top; 运行结果如下：(3)代码段1-3：将所有的按钮进行sendtoback处理：private void button1_Click(object sender, EventArgs e) button1.SendToBack(); button1.Dock = DockStyle.Bottom; button2.SendToBack(); button2.Dock = DockStyle.Bottom; button3.SendToBack(); button3.Dock = DockStyle.Bottom; button4.SendToBack(); button4.Dock = DockStyle.Bottom; button5.SendToBack(); button5.Dock = DockStyle.Bottom; button6.SendToBack(); button6.Dock = DockStyle.Bottom; button7.SendToBack(); button7.Dock = DockStyle.Bottom; button8.SendToBack(); button8.Dock = DockStyle.Top; 运行结果如图：（4）代码段1-4：对代码1-3中6,7按钮不做任何处理，会怎样呢：private void button1_Click(object sender, EventArgs e) button1.SendToBack(); button1.Dock = DockStyle.Bottom; button2.SendToBack(); button2.Dock = DockStyle.Bottom; button3.SendToBack(); button3.Dock = DockStyle.Bottom; button4.SendToBack(); button4.Dock = DockStyle.Bottom; button5.SendToBack(); button5.Dock = DockStyle.Bottom; /6,7按钮不做操作处理会怎样 button8.SendToBack(); button8.Dock = DockStyle.Top; 运行结果如下：因此会产生覆盖：（5）代码段1-5:在1-4上再加上对6,7在Z面上的操作，不进行sendtoback处理：（5）代码段1-5：private void button1_Click(object sender, EventArgs e) button1.SendToBack(); button1.Dock = DockStyle.Bottom; button2.SendToBack(); button2.Dock = DockStyle.Bottom; button3.SendToBack(); button3.Dock = DockStyle.Bottom; button4.SendToBack(); button4.Dock = DockStyle.Bottom; button5.SendToBack(); button5.Dock = DockStyle.Bottom; button6.Dock = DockStyle.Top; button7.Dock = DockStyle.Top; /在Z面上进行操作 button8.SendToBack(); button8.Dock = DockStyle.Top; 注：带阴影为Z面sendtoback后：（6）代码段1-6：在代码段1-5上做些改动后:private void button1_Click(object sender, EventArgs e) button1.SendToBack(); button1.Dock = DockStyle.Bottom; button3.SendToBack(); button3.Dock = DockStyle.Bottom; button4.SendToBack(); button4.Dock = DockStyle.Bottom; /打乱1,2,3，4,5的顺序；再不对8进行操作 button2.SendToBack(); button2.Dock = DockStyle.Bottom; button5.SendToBack(); button5.Dock = DockStyle.Bottom; button6.Dock = DockStyle.Top; button7.Dock = DockStyle.Top; 运行结果如图：（7）代码段1-7：恢复对button8的sendtoback操作：private void button1_Click(object sender, EventArgs e) button1.SendToBack(); button1.Dock = DockStyle.Bottom; button3.SendToBack(); button3.Dock = DockStyle.Bottom; button4.SendToBack(); button4.Dock = DockStyle.Bottom; button2.SendToBack(); button2.Dock = DockStyle.Bottom; button5.SendToBack(); button5.Dock = DockStyle.Bottom; button6.Dock = DockStyle.Top; button7.Dock = DockStyle.Top; button8.SendToBack(); button8.Dock = DockStyle.Top; （8）代码段1-8：将代码1-7中的top与bottom对调：private void button1_Click(object sender, EventArgs e) button1.SendToBack(); button1.Dock = DockStyle.Top; button3.SendToBack(); button3.Dock = DockStyle.Top; button4.SendToBack(); button4.Dock = DockStyle.Top; button2.SendToBack(); button2.Dock = DockStyle.Top; button5.SendToBack(); button5.Dock = DockStyle.Top; button6.Dock = DockStyle.Bottom; button7.Dock = DockStyle.Bottom; button8.SendToBack(); button8.Dock = DockStyle.Bottom; 运行结果如下：（9）代码段1-9：将1-8中sendtoback全部改为：bringtofrontprivate void button1_Click(object sender, EventArgs e) button1.BringToFront(); button1.Dock = DockStyle.Top; button3.BringToFront(); button3.Dock = DockStyle.Top; button4.BringToFront(); button4.Dock = DockStyle.Top; button2.BringToFront(); button2.Dock = DockStyle.Top; button5.BringToFront(); button5.Dock = DockStyle.Top; button6.Dock = DockStyle.Bottom; button7.Dock = DockStyle.Bottom; button8.BringToFront(); button8.Dock = DockStyle.Bottom; (10)代码段1-10：将1-9中button8改为sendtobackprivate void button1_Click(object sender, EventArgs e) button1.BringToFront(); button1.Dock = DockStyle.Top; button3.BringToFront(); button3.Dock = DockStyle.Top; button4.BringToFront(); button4.Dock = DockStyle.Top; button2.BringToFront(); button2.Dock = DockStyle.Top; button5.BringToFront(); button5.Dock = DockStyle.Top; button6.Dock = DockStyle.Bottom; button7.Dock = DockStyle.Bottom; button8.SendToBack(); /将其改为sendtoback button8.Dock = DockStyle.Bottom; 运行结果：（11）不妨更乱一点：运行结果如图：总结一下：从实验来看，如果仅把 Z轴上看成3个面的话：bringtofront面为最上面，中间是Z面，下面是sendtoback面；那么他们放置按钮的原则是：1. bringtofront和Z面上为“接着放”