初中因式分解习题.doc

.因式分解练习题1（一）填空1一个多项式若能因式分解，则这个多项式被其任一因式除所得余式为_2变形（1）(a+b)(a-b)=a2-b2，（2）a2-b2=(a-b)(a+b)中，属于因式分解过程的是_3若a，b，c三数中有两数相等，则a2(b-c)+b2(c-a)+c2(a-b)的值为_412.7180.125-0.1254.718=_51.132.5+2.252.5+0.622.5=_6分解因式：a2(b2-c2)-c2(b-c)(a+b)=_7因式分解：(a-2b)(3a+4b)+(2a-4b)(2a-3b)=(a-2b)( )8若a+b+c=m，则整式m(a-b)2+(b-c)2+(c-a)2+6(a+b+c)(ab+bc+ca)可用m表示为_9(2x+1)y2+(2x+1)2y=_10因式分解：(x-y)n-(x-y)n-2=(x-y)n-2_11m(a-m)(a-n)-n(m-a)(a-n)=_12因式分解：x(m-n)+(n-m)y-z(m-n)=(m-n)( )13因式分解：(x+2y)(3x2-4y2)-(x+2y)2(x-2y)=_1421a3b-35a2b3=_153x2yz+15xz2-9xy2z=_16x2-2xy-35y2=(x-7y)( )172x2-7x-15=(x-5)( )1820x2-43xy+14y2=(4x-7y)( )1918x2-19x+5=( )(2x-1)206x2-13x+6=( )( )215x2+4xy-28y2=( )( )22-35m2n2+11mn+6=-( )( )236+11a-35a2=( )( )246-11a-35a2=( )( )25-1+y+20y2=( )( )2620x2+( )+14y2=(4x-7y)(5x-2y)27x2-3xy-( )=(x-7y)(x+4y)28x2+( )-28y2=(x+7y)(x-4y)29x2+( )-21y2=(x-7y)(x+3y)30kx2+5x-6=(3x-2)( )，k=_316x2+5x-k=(3x-2)( )，k=_326x2+kx-6=(3x-2)( )，k=_3318x2-19x+5=(9x+m)(2x+n)，则m=_，n=_3418x2+19x+m=(9x+5)(2x+n)，则m=_，n=_3520x2-43xy+14y2=(4x+m)(5x+n)，则m=_，n=_3620x2-43xy+m=(4x-7y)(5x+n)，则m=_，n=_38x4-4x3+4x2-1=_392x2-3x-6xy+9y=_4021a2x-9ax2+6xy2-14ay2=_41a3+a2b+a2c+abc=_422(a2-3ac)+a(4b-3c)=_4327x3+54x2y+36xy2+8y3_441-3(x-y)+3(x-y)2-(x-y)3=_45(x+y)2+(x+m)2-(m+n)2-(y+n)2=_4625x2-4a2+12ab-9b2=_47a2-c2+2ab+b2-d2-2c