应用多文件数组处理大整数的加减乘除

include stdio h include stdlib h include string h include f2 h include f3 h include f4 h include f5 h define max len 100 int an1 max len 10 0 int an2 max len 10 0 int result max len 10 0 char str1 max len 10 char str2 max len 10 void main int flag 1 printf n printf 1 求和 n printf 2 求差 n printf 3 求积 n printf 4 求商 n printf 5 退出 n printf n while flag 0 printf nPlease input your choice scanf d switch flag default printf The num is not correct please input again n break case 1 add an1 an2 break case 2 jian an1 an2 break case 3 mul an1 an2 break case 4 div an1 an2 break case 5 exit 0 include f2 h include stdio h include stdlib h include string h define max len 100 int add int an1 int an2 char str1 max len 10 char str2 max len 10 scanf s str1 scanf s str2 int i j 存储的字符串整数转换到 an1 中去 j 0 for i strlen str1 1 i 0 i an1 j str1 i 0 j 0 for i strlen str2 1 i 0 i an2 j str2 i 0 for i 0 i 10 看是否进位 an1 i 10 an1 i 1 进位 bool bStartOutput false 跳过多余的零 for i max len i 0 i if bStartOutput printf d an1 i 多余零都跳过则退出 else if an1 i printf The sum is d n an1 i bStartOutput true for j 0 j max len 10 j an1 j 0 an2 j 0 return 0 include f3 h include stdio h include stdlib h include string h define max len 100 int jian int an1 int an2 char str1 max len 10 char str2 max len 10 int i j scanf s str1 scanf s str2 for i 0 i 0 i an1 j str1 i 0 int nlen2 strlen str2 j 0 for i nlen2 1 i 0 i an2 j str2 i 0 for i 0 i max len i if an1 i 0 i if bStartOutput printf d an1 i 多余零都跳过则输出 else if an1 i printf The result is d n an1 i bStartOutput true for i 0 i 0 i an1 j str1 i 0 int nlen2 strlen str2 j 0 for i nlen2 1 i 0 i an2 j str2 i 0 for i 0 i nlen2 i for j 0 j nlen1 j result i j an2 i an1 j for i 0 i 10 result i 1 result i 10 result i 10 bool bStartOutput false 跳过多余的零 for i max len i 0 i if bStartOutput printf d result i 多余零都跳过则退出 else if result i printf The result is d n result i bStartOutput true for j 0 j 0 bool bStartOutput false 跳过多余的零 for i max len i 0 i if bStartOutput printf d result i 多余零都跳过则退出 else if result i printf The result is d n result i bStartOutput true for j 0 j 0 i an1 j str1 i 0 int nlen2 strlen str2 j 0 for i nlen2 1 i 0 i an2 j str2 i 0 if nlen1 nlen2 printf 0 n nlen1 sub an1 an2 nlen1 nlen2 if nlen1 0 bool bStartOutput false 跳过多余的零 for i max len i 0 i if bStartOutput printf d result i 多余零都跳过则退出 else if result i printf The result is d n result i bStartOutput true for j 0 j max len 10 j an1 j 0 an2 j 0 return 0 int sub int p1 int p2 int nlen1 int nlen2 返回值代表的是结果长度 不够减返回 1 刚好减完返回 0 int i if nlen1 0 i