汇编语言作业.doc

作业1：用汇编语言实现下列C功能：chars16;printf(“nWhat is your name? ”);scanf(“%s”,s);printf(“nMy name is %sn”,s);程序：stck segment stack stack dw 32 DUP(?)stck endsdata segmentX DB 16,0,16 DUP(?)Y DB 0AH,What is your name?$Z DB 0AH,My name is:$data endscode segmentbegin proc farassume ss:stck,cs:code,ds:datapush dssub ax,axpush axmov ax,datamov ds,axMOV DX,OFFSET Y ;显示What is your name?并回车换行MOV AH,9INT 21HMOV DX,OFFSET X ;键入并显示字符串MOV AH,10INT 21HMOV BL,X+1 ;将$送入字符串后MOV BH,0MOV BXX+2,$MOV DX,OFFSET ZMOV AH,9INT 21HMOV DX,OFFSET X+2 ;显示出结果MOV AH,9INT 21Hretbegin endpcode endsend begin作业2.从键盘上键入09中任意自然数N，将其立方值送显示器显示程序：stck segment stackdw 32 dup(?)stck endsdata segmentINPUT DBPLEASE INPUT N(09):$OUTPUT DB 0DH,0AH,THE RESULT IS:$LFB DW 00H,01H,08H,27H,64H,125H,216H,343H,512H,729HN DB ?data endscode segmentbegin proc farassume ss:stck,ds:data,cs:codepush dssub ax,axpush axmov ax,datamov ds,axMOV DX,OFFSET INPUT;显示输入提示信息MOV AH,9INT 21HMOV AH,1;键入并回显NINT 21HMOV N,AL;保留NAND N,0FH;立方表中的偏移量SHL N,1MOV BL,NMOV BH,0MOV CX,LFBBX;查表得N立方的BCD形式MOV DX,OFFSET OUTPUT;输出提示信息MOV AH,9INT 21HAND CH,0FH;将百位转化ADD CH,30HMOV DL,CHMOV AH,2INT 21HMOV BL,CL;将十位转化SHR CL,4ADD CL,30HMOV DL,CLMOV AH,2INT 21HAND BL,0FH;将个位转化ADD BL,30HMOV DL,BLMOV AH,2INT 21Hretbegin endpcode endsend begin作业3从键盘输入一个无符号的十进制数（0255），得到其实际数值后保存到bl中。为：在显示器上以二进制/十六进制显示做准备。stck segment stack dw 32 dup(?) stck endsdata segmentINPUT DB 4,0,4 DUP(0)OUTPUT db Please input N(0-255):$ data endscode segmentbeginproc farassume ss:stck,ds:data,cs:codepush dssub ax,axpush axmov ax,datamov ds,axMOV DX,OFFSET OUTPUT;输出输入提示 MOV AH,9 INT 21H MOV DX,OFFSET INPUT MOV AH,10 INT 21H MOV BL,INPUT+1 ;BL储存十进制个数 MOV BH,0 MOV INPUT BX+2,$ ;存入输入的十进制数并在尾端存入$ MOV DL,0DH MOV AH,2 INT 21H MOV DL,0AH MOV AH,2 INT 21H ;换行 MOV DL,N MOV AH,2 INT 21H MOV DL,= MOV AH,2 INT 21H MOV DX,OFFSET INPUT+2 MOV AH,9 INT 21H MOV DL,= MOV AH,2 INT 21H ;输出部分的十进制输出 MOV SI,OFFSET INPUT+2 MOV CL,INPUT+1 MOV CH,0 MOV AX,0 MOV DL,10AGAIN: MUL DL AND byte ptr SI,0FH ;ASCLL码处理成二进制 ADD AL,SI ADD AH,0 INC SI LOOP AGAIN ;十进制处理成了二进制，结果在al中 MOV BL,AL MOV AH,AL ;AH和BL中均备份 AND AH,0F0H MOV CL,4 SHR AH,CL ;AH中用二进制的高四位 CMP AH,10 JB K1 ADD AH,7K1: ADD AH,30H mov dl,AH mov AH,2 INT 21H MOV AL,BL AND AL,0FH ;AL只要低四位 CMP AL,10 JB K2 ADD AL,7K2: ADD AL,30H mov dl,AL mov AH,2 INT 21H mov dl,H mov AH,2 INT 21H mov dl,= mov AH,2 INT 21H ;十六进制输出完毕 MOV CX,8 ;八次循环将bl中备份的二进制数输出 CIR: MOV BH,0 SHL BL,