微机原理,汇编与接口技术第二版朱定华第3章+习题PPT课件

.,3-1写出执行下列程序段的中间结果和结果,.,1.MOVAX，0809HMULAH；AX=AAM；AX=,0048H,0702H,.,2.MOVAX，0809HMOVDL，5AAD；AX=DIVDL；AX=MOVDL，AHAAM；AX=DL=,0059H,0411H,0107H,04H,.,3.MOVAX，0809HADDAL，AHMOVAH，0；AX=AAA；AX=,0011H,0107H,.,4.MOVAX，0809HMOVDL，10XCHGAH，DLMULAH；AX=AAM；AX=ADDAL，DL；AX=,005AH,0900H,0908H,.,5.MOVAL,98HMOVAH,ALMOVCL,4SHRAH,CLANDAL,0FHAAD；AL=H,62,.,6.MOVCL,248XORAX，AXMOVCH,8AG：SHLCL，1ADCAL，ALDAAADCAH，AHDECCHJNZAG；AX=H,0248,.,3-2编写程序，将字节变量BVAR中的压缩BCD数转换为二进制数，并存入原变量中。,.,BVARDB99HMOVAL,BVARMOVCL,4SHRAL,CLMOVAH,10MULAHANDBVAR,0FHADDBVAR,AL,.,本题还可以先将2位压缩BCD数转换为非压缩BCD数，然后用AAD指令将非压缩BCD数转换为二进制数。实现转换的程序段如下：,.,MOVAL,BVARMOVAH,ALMOVCL,4SHRAH,CLANDAL,0FHAADMOVBVAR,AL,.,3-4编写求两个4位非压缩BCD数之和，将和送显示器显示的程序。D1DD06070809HD2DD04050607HOBFDB6DUP(0),.,MOVSI，0MOVDI,OFFSETOBF+5MOVBYTEPTRDI,$MOVCX,4XORAH,AHAGAIN:MOVAL,BYTEPTRD1SIADDAL,BYTEPTRD2SIADDAL,AHMOVAH，0AAA,.,ADDAL,30HDECDIMOVDI,ALINCSILOOPAGAINANDAH,AHJZNWW,；无万位，转移,.,DECDIMOVBYTEPTRDI,1NWW:MOVDX,DIMOVAH,9INT21H,.,3-5编写求两个4位压缩BCD数之和，将和送显示器显示的程序。,W1DW8931HW2DW5678HOBFDB6DUP(0),.,MOVAL,BYTEPTRW1ADDAL,BYTEPTRW2DAAMOVAH,ALMOVAL,BYTEPTRW1+1ADCAL,BYTEPTRW2+1DAAPUSHFMOVDIOFFSETOBF+5MOVBYTEPTRDI,$,.,MOVCL,4XCHGAH,ALAGAIN:MOVDL,0FHANDDL,ALADDDL,30HDECDIMOVDI,DLSHRAX,CLANDAX,AXJNZAGAIN,.,POPFJNCOPUTDECDIMOVBYTEPTRDI,1OPUT:MOVDX,DIMOVAH,9INT21H,.,3-6编写程序，将字节变量BVAR中的二进制数（0FFH）转换为BCD数，在屏幕上以十进制数形式显示结果。,.,BVARDB99HOBUFDB4DUP(0)MOVAL,BVARMOVAH,0MOVDL,100DIVDLADDAL,30HMOVOBUF,AL,.,MOVAL，AHAAMADDAX，3030HMOVOBUF+1，AHMOVOBUF+2，ALMOVOBUF+3，$MOVDX，OFFSETOBUFMOVAH，9INT21H,.,3.9有一原码形式的双字符号数，试编制求其补码的程序。,.,3.11将键盘输入的8位二进制数以十六进制数形式在显示器上显示出来，试编写这一程序。,IBUFDB9,0,9DUP(0)MOVDX,OFFSETIBUFMOVAH,10INT21HMOVCX,MOVSI,2,.,MOVCX,8MOVSI,2AG:SHRIBUFSI,1RCLDH,1INCSILOOPAG,.,MOVDL,DHMOVCL,4SHRDL,CLCMPDL,39HJBENAD71ADDDL,7NAD71:MOVAH,2INT21H,.,MOVDL,DHANDDL,0FHCMPDL,39HJBENAD72ADDDL,7NAD72:MOVAH,2INT21H,.,3.12将键盘输入的十进制数（-128127）转换为二进制数，以十六进制数形式在显示器上显示出来，试编写这一程序。,IBUFDB5,0,5DUP(0)MOVDX,OFFSETIBUFMOVAH,10INT21HMOVCL,IBUF+1MOVCH,0MOVSI,OFFSETIBUF+2,.,CMPBYTEPTRSI,PUSHFJNESININCINCSIDECCXSININC:MOVAL,0AGAIN:MOVAH,10MULAHANDBYTEPTRSI,0FHADDAL，SIINCSILOOPAGAIN,.,POPFJNZNNEGNEGALNNEG:MOVDL,ALMOVDH,ALMOVCL,4SHRDL,CLCMPDL,39HJBENAD71ADDDL,7,.,NAD71:MOVAH,2INT21HMOVDL,DHANDDL,0FHCMPDL,39HJBENAD72ADDDL,7NAD72:MOVAH,2INT21H,.,3.13编写将字变量SW中的16位无符号二进制数以十制数形式送显示器显示的程序。,SWDW1234HOBUFDB5DUP(0)MOVBX,5MOVOBUFBX,$MOVCX,10MOVAX,SW,.,AG:MOVDX,0ANDAX,AXJZSCDIVCXADDDL,30HDECBXMOVOBUFBX,DLJMPAG,.,SC:MOVDX,OFFSETOBUFADDDX,BXMOVAH,9INT21H,.,3.16从键盘输入一字符串（字符数），然后在下一行以相反的次序显示出来。,BUFDB255,0,255DUP(0),MOVDX,OFFSETBUFMOVAH,10INT21HMOVSI，OFFSETBUT+2MOVBX，SIADDBL，BUF+1ADCBH，0,.,MOVBYTEPTRBX，$DECBXAGAIN：MOVAL，BXXCHGAL，SIMOVBX，ALDECBXINCSICMPSI，BXJCAGAINMOVBUF+1，0AHMOVDX，OFFSETBUF+1MOVAH，9INT21H,.,3-28源程序如下，阅读后做如下试题：1.在分号后给指令或（向下）给程序段加上注释（实质是做什么？例如，第1个注释若注为将2送BX，则视为非实质注释，不给分）。2.列举实例，说明该程序的功能（键入什么？显示什么？）。3.画出实例的数据存储图。,.,IBUFDB255,0,255DUP(0)ABCDDB0AH,ABCD:DB255DUP(0)MNOPDB0AH,0DH,MNOP:DB255DUP(0)MOVDX,OFFSETIBUFMOVAH,10INT21H,.,MOVBX,2；MOVSI,OFFSETABCD+7MOVDI,OFFSETMNOPQ+8AG:CMPIBUFBX-1,0DH；JEEXITCMPIBUFBX,-；JNEP1CALLMPJMPAG,.,P1:XCHGSI,DI；CALLMPXCHGSI,DIJMPAGEXIT:MOVBYTEPTRSI-1,$MO