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,CHAPTER2SHEAR,材料力学,第二章剪切,CHAPTER2SHEAR,21STRENGTHCALCULATIONABOUTSHEARANDBEARINGOFCONNECTINGMEMBERS,EXCERCISELESSONSOFSHEARANDBEARING,第二章剪切,21连接件的剪切与挤压强度计算,拉压和剪切习题课,Productionoftheshearingstress,SHEAR,剪切,剪应力的产生,21STRENGTHCALCULATIONABOUTSHEARANDBEARINGOFCONNECTINGMEMBERS,1、Characteristicsofloadsanddeformationofconnectingmembers:,1)Connectingmember,Thestructurememberthatconnectsonemembertoanotheriscalledtheconnectingmember.Suchas:bolts、rivets、keysetc.Theconnectingmemberissmall,butitplaystheroleofpassingloads.,Characteristic:Itcanpassgeneralloadsandcanbedismounted.,bolt,SHEAR,21连接件的剪切与挤压强度计算,一、连接件的受力特点和变形特点:,1、连接件,剪切,在构件连接处起连接作用的部件,称为连接件。例如:螺栓、铆钉、键等。连接件虽小,却起着传递载荷的作用。,特点:可传递一般力,可拆卸。,螺栓,rivet,Characteristic:Itcanpassgeneralloads,butcannotbedismounted.forexample,thetrussinabridgeisconnectedbyit.,nogap,Characteristic:Itcanpasstorques.,SHEAR,剪切,铆钉,特点:可传递一般力,不可拆卸。如桥梁桁架结点处用它连接。,无间隙,2)Characteristicsofloadsanddeformation:,Usearivetasanexample:,Characteristicofloads:Therivetissubjectedtotwoequalandoppositeforces.Theactinglinesofthesetwoforcesareveryclose.,Characteristicofdeformation:Twopartssubjectedtotwoequalandoppositeforcestendtoshiftoveroneanotheralongthejunctionplaneoftwoforces.,SHEAR,2、受力特点和变形特点:,剪切,以铆钉为例:,受力特点:构件受两组大小相等、方向相反、作用线相距很近(差一个几何平面)的平行力系作用。,变形特点:构件沿两组平行力系的交界面发生相对错动。,(Resultant),(Resultant,Shearingplane:Theplanealongwhichtwopartsofthemembertendtoshiftoveroneanother.Suchasnn.,Internalforceonshearingplane:InternalforceShearingforceQ,itsactinglineisparalleltotheshearingplane.,SHEAR,剪切,剪切面:构件将发生相互的错动面,如nn。,剪切面上的内力:内力剪力Q,其作用线与剪切面平行。,3)Threekindsofbreakageatjoint:FailureduetoshearSnipalongtheshearingplaneoftherivet,suchasalongsectionnn.BreakageduetobearingFailduetomutualbearingbetweentherivetandthesteelplateintheirconnectingplane.Breakageduetotension,Thesteelplateisweakenedinthesectioninwhichtherivetholesexistandstressintheweakenedsectionincreasessothatthesteelplateiseasilybrokenduetotensionattheconnectingposition.,SHEAR,剪切,3、连接处破坏的三种形式:剪切破坏沿铆钉的剪切面剪断,如沿nn面剪断。挤压破坏铆钉与钢板在相互接触面上因挤压而使溃压连接松动,发生破坏。拉伸破坏,钢板在受铆钉孔削弱的截面处,应力增大,易在连接处拉断。,2、Practicalcalculationofshear,Methodofthepracticalcalculation:Accordingtopossibilityofbreakageofthemembersomeassumptionsbywhichbasiccharacteristicsubjectedtoforceactionscanbereflectedandcalculationscanbesimplifiedareused.Thencalculateitsnominalstress,determinethecorrespondingpermissiblestressinaccordancewiththeresultofdirecttest.Atlastdothestrengthcalculation.Applyingrange:volumeofthememberisnotlargeandrealstressisquitecomplex.Suchastheconnectingpiecesetc.,Assumptionofpracticalcalculation:Assumethatshearingstressisdistributeduniformlyintheshearingplaneandequaltotheaverageshearingstress.,SHEAR,剪切,二、剪切的实用计算,实用计算方法:根据构件的破坏可能性,采用能反映受力基本特征,并简化计算的假设,计算其名义应力,然后根据直接试验的结果,确定其相应的许用应力,以进行强度计算。适用:构件体积不大,真实应力相当复杂情况,如连接件等。,实用计算假设:假设剪应力在整个剪切面上均匀分布,等于剪切面上的平均应力。,1)Shearingplane-AQ:Shiftingplane.Shearingforce-Q:Internalforceontheshearingplane.,2)Nominalshearingforce-:,3)Strengthconditionofshear:,Workingstressshouldnotexceedthepermissiblestress.,SHEAR,where,剪切,1、剪切面-AQ:错动面。剪力-Q:剪切面上的内力。,2、名义剪应力-:,3、剪切强度条件(准则):,工作应力不得超过材料的许用应力。,3、Practicalcalculationsofbearing,1)BearingforcePjy:Theresultantforceactingonthetouchingplane.,Bearing:Thephenomenonthatthereispressureonthepartialareaofamember.Bearingforce:Theresultantforceactingonthebearingplane,designatedbyPjy.,Assumption:Bearingstressesaredistributeduniformlyovertheeffectivebearingplane.,SHEAR,三、挤压的实用计算,1、挤压力Pjy:接触面上的合力。,剪切,挤压:构件局部面积的承压现象。挤压力:在接触面上的压力,记Pjy。,假设:挤压应力在有效挤压面上均匀分布。,2)Bearingarea:AreaoftheprojectionplaneofthetouchingplaneinthedirectionperpendiculartoPjy,3)Strengthconditionofbearing:Workingbearingstressshouldnotexceedthepermissiblebearingstress,Bearingarea,SHEAR,2、挤压面积:接触面在垂直Pjy方向上的投影面的面积。,3、挤压强度条件(准则):工作挤压应力不得超过材料的许用挤压应力。,剪切,挤压面积,4、Applications,SHEAR,1)Checkthestrength,2)Selectthecrosssectionarea,3)Determinetheexternalload,四、应用,剪切,Example1Awoodentenonjointisshowninthefigure.Knowingthatthequantitiesarea=b=12cm,h=35cm,c=4.5cmandP=40KN.Trytodeterminetheshearingstressandbearingstressforthejoint.,Solution:Freebodydiagramisshowninthefigure,:Shearingstressandbearingstress,Shearingforceis,Bearingforceis,SHEAR,例1木榫接头如图所示,a=b=12cm,h=35cm,c=4.5cm,P=40KN,试求接头的剪应力和挤压应力。,解:受力分析如图,剪应力和挤压应力,剪切面和剪力为,挤压面和挤压力为:,剪切,Solution:Freebodydiagramofthekeyisshowninthefigure,Example2Agearandashaftareconnectedbyakey(bhL=2012100).Thetorquethatthekeycantransmitism=2KNm.Knowingthediameteroftheshaftisd=70mm,thepermissibleshearingstressandthepermissiblebearingstressofthekeyarerespectively=60MPaandjy=100MPa.Trytocheckthestrengthofthekey.,SHEAR,解:键的受力分析如图,例2齿轮与轴由平键(bhL=2012100)连接,它传递的扭矩m=2KNm,轴的直径d=70mm,键的许用剪应力为=60MPa,许用挤压应力为jy=100MPa,试校核键的强度。,剪切,Accordingtotheabovecalculation,strengthconditionsofthekeyaresatisfied.,Checkthestrengthofshearandbearing,SHEAR,综上,键满足强度要求。,剪应力和挤压应力的强度校核,剪切,Solution:Freebodydiagramofthekeyisshowninthefigure,Example3Agearandashaftareconnectedbyakey(b=16mm,h=10mm).Thetorquethatthekeycantransmitism=1600Nm.Knowingthediameteroftheshaftisd=50mm,thepermissibleshearingstressandthepermissiblebearingstressofthekeyarerespectively=80MPaandjy=240MPa.Trytodesignthelengthofthekey.,SHEAR,解:键的受力分析如图,例3齿轮与轴由平键(b=16mm,h=10mm,)连接,它传递的扭矩m=1600Nm,轴的直径d=50mm,键的许用剪应力为=80MPa,许用挤压应力为jy=240MPa,试设计键的长度。,剪切,Strengthconditionsoftheshearingstressandthebearingstress,Accordingtotheabovecalculation,SHEAR,剪切,剪应力和挤压应力的强度条件,综上,Solution:Freebodydiagramisshowninthefigure,Example4Arivetedtie-inactedbyforceP=110kNisshowninthefigure.Knowingthethicknessist=1cm,widthofitisb=8.5cm.Thepermissiblestressis=160MPa.Diameteroftherivetisd=1.6cmandthepermissibleshearingstressis=140MPa,thepermissiblebearingstressisjy=320MPa.Trytocheckthestrengthoftheriveting.(Assumetheforceactedoneachrivetisequal.),SHEAR,解:受力分析如图,例4一铆接头如图所示,受力P=110kN,已知钢板厚度为t=1cm,宽度b=8.5cm,许用应力为=160MPa;铆钉的直径d=1.6cm,许用剪应力为=140MPa,许用挤压应力为jy=320MPa,试校核铆接头的强度。(假定每个铆钉受力相等。),剪切,Thesections22and33ofthesteelplatearethecriticalsections.,Thestrengthconditionsofshearandbearing,Therefore,thetie-inissafe.,SHEAR,钢板的2-2和3-3面为危险面,剪应力和挤压应力的强度条件,综上,接头安全。,剪切,1、Internal-forceandaxial-forcediagramsoftherodintensionandcompression,1)ExpressionofAxialforce?,2)Methodtodetermineaxialforce?,3)Positiveandnegativeofaxialforce?,Exerciselessonsoftensionandcompressionandshear,Whydoweplottheaxial-forcediagram?Whatshouldwepayattentionwhenwedoit?,4)Axial-forcediagram:ExpressedbythediagramofN=N(x)?,SHEAR,一、轴向拉压杆的内力及轴力图,1、轴力的表示?,2、轴力的求法?,3、轴力的正负规定?,剪切,拉压和剪切习题课,为什么画轴力图?应注意什么?,4、轴力图:N=N(x)的图象表示?,Simplemethodtodetermineaxialforces:Taketheleftpartofthesectionxastheobject,theaxialforceonthesectionxcanbecalculatedbyfollowingformula:,Where“P()”and“P()”expressthesumofleftdirectionforcesandthesumofrightdirectionforcesoftheleftpartofthesectionx.Taketherightpartofthesectionxastheobject,theaxialforceN(x)ofpointxcanbecalculatedbythefollowingformulate:Where“”and“”denotethesumofrightdirectionforcesandthesumofleftdirectionforcesoftherightpartofsectionx.,SHEAR,轴力的简便求法:以x点左侧部分为研究对象,x点的轴力N(x)由下式计算:,其中“P()”与“P()”为x点左侧向左的所有外力与向右的所有外力。以x点右侧部分为研究对象,x点的轴力N(x)由下式计算:其中“P()”与“P()”为x点右侧向右的所有外力与向左的所有外力。,剪切,Example1Forces5P,8P,4PandPareactedatpointsA,B,CandDontherodrespectively,theirdirectionsareshowninthefigure.Trytoplottheaxial-forcediagramoftherod.,A,B,C,D,O,2P,SHEAR,例1图示杆的A、B、C、D点分别作用着5P、8P、4P、P的力,方向如图,试画出杆的轴力图。,剪切,A,B,C,D,O,2P,Positiveandnegativeofstress?,1)Stressonthecrosssection:,2、Stressoftherodintensionorcompression,Criticalsectionandmaximumworkingstress?,2)Stressontheinclinedsection,Saint-Venantprinciple?,Stressconcentrations?,SHEAR,应力的正负规定?,1、横截面上的应力:,二、拉压杆的应力,危险截面及最大工作应力?,2、拉压杆斜截面上的应力,Saint-Venant原理?,应力集中?,剪切,3、Strengthdesigncriterion:,1)Strengthdesigncriterion,Checkstrength:,Designthecrosssectionarea:,Designtheload:,SHEAR,三、强度设计准则(StrengthDesignCriterion):,1、强度设计准则?,校核强度:,设计截面尺寸:,设计载荷:,剪切,1)Elasticlawoftherodwithequalaxialforces,2)Elasticlawwithvariableinternalforces,3)Elasticlawinuniaxialstressedstate,4、Deformationandstrainoftherodintensionorcompression,SHEAR,1、等轴力拉压杆的弹性定律,2、变内力拉压杆的弹性定律,3、单向应力状态下的弹性定律,四、拉压杆的变形及应变,剪切,4)Possionsratio(orlateraldeformationfactor),5)Theenlarged-deformationdiagramandthemethodtodeterminethedisplacement,SHEAR,4、泊松比(或横向变形系数),剪切,5、小变形放大图与位移的求法,Assemblestressinitialstress,Temperaturestress,Equilibriumequations;Geometricequationscompatibilityequationsofdeformation;Physicalequationselasticlaws;Complementaryequations:gettingfromgeometricequationsandphysicalequations;Solvingthecombinedequationsincludingofequilibriumequationsandcomplementequations.,6)Thestepstosolvethestaticallyindeterminateproblem,SHEAR,装配应力预应力,温度应力,剪切,平衡方程;几何方程变形协调方程;物理方程弹性定律;补充方程:由几何方程和物理方程得;解由平衡方程和补充方程组成的方程组。,6、超静定问题的处理方法步骤:,5、Mechanicalpropertiesofthematerialsintensionandcompression,3)Unloadedlaw;Coldhardening;Cold-drawntimeeffect.,1)Elasticlaw,4)Residualrelativeelongation,5)Permanentrelativereductionofarea,SHEAR,2)Limitstress,6)Permissiblestress,五、材料在拉伸和压缩时的力学性能,3、卸载定律;冷作硬化;冷拉时效。,1,、弹性定律,剪切,4、延伸率,5、面缩率,1)Practicalcalculationofshear,6、Practicalcalculationofshearandbearingoftheconnectingmemberoftherodsintensionandcompression,2)Practicalcalculationofbearing,SHEAR,1、剪切的实用计算,六、拉(压)杆连接部分的剪切与挤压强度计算,剪切,2、挤压的实用计算,Bearingarea,SHEAR,Checkthestrength,Designthedimension,Designtheexternalload,剪切,挤压面积,Example2TherodsAB、CD、EFandGHinthestructureareshowninthefigureEachofthemconsiststwoofrolledunequal-legssteels.Knowing=170MPa,E=210GPa.RodsACandEGmaybeseenasrigidrod.TrytoselectthesectiondimensionofeachrodandtodeterminethedisplacementsofpointsA、DandC.,P=300kN,0.8m,3.2m,1.8m,1.2m,2m,3.4m,A,B,C,D,F,H,q0=100kN/m,Solution:Determinetheinternalforce.Thefreebodydiagramisshowninthefigure.,E,G,SHEAR,例2结构如图,AB、CD、EF、GH都由两根不等边角钢组成,已知材料的=170MPa,E=210GPa。AC、EG可视为刚杆,试选择各杆的截面型号和A、D、C点的位移。,剪切,P=300kN,0.8m,3.2m,1.8m,1.2m,2m,3.4m,A,B,C,D,F,H,q0=100kN/m,解:求内力,受力分析如图,E,G,D,q0=100kN/m,E,G,A,C,NG,NC,NA,NE,ND,=ND,P=300kN,Determinetheareabystrengthcondition,SHEAR,剪切,D,q0=100kN/m,E,G,A,C,NG,NC,NA,NE,ND,=ND,P=300kN,由强度条件求面积,Determinethetypesoftherodsreferencetothetable,Determinethedeformation,SHEAR,剪切,试依面积值查表确定型钢号,求变形,Determinethedisplacement.Thedeformationisshowninthefigure.,A,B,D,F,H,E,G,C,C1,A1,E1,D1,G1,SHEAR,求位移,变形图如图,剪切,A,B,D,F,H,E,G,C,C1,A1,E1,D1,G1,Example3DiametersofrodACandBDinthestructureshowninthefigurearerespectivelyd1=25mm,d2=18mm.Knowing=170MPa,E=210GPa.RodABmaybeseenasarigidrod.Tryto(1)checkthestrengthofeachrodandtodeterminethedisplacementsAandBofpointsAanB.(2)determinethedisplacementFofpointFwhentheforcePisactedonpointA.F=Aisagenerallaw,whichiscalledtheoremofconjugatedisplacement.,A,B,C,D,P=100kN,1.5m,3m,2.5m,F,Solution:DeterminetheinternalforceThefreebodydiagramisshowninthefingure.,SHEAR,例3结构如图,AC、BD的直径分别为:d1=25mm,d2=18mm,已知材料的=170MPa,E=210GPa,AB可视为刚杆,试校核各杆的强度;求A、B点的位移A和B。(2)求当P作用于A点时,F点的位移F,F=A是普遍规律:称为位移互等定理。,剪切,A,B,C,D,P=100kN,1.5m,3m,2.5m,F,解:求内力,受力分析如图,Checkthestrength,Determinet

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