塔吊扶墙计算(品茗英文版)

Calculation For Attach Buildings1. Location and size of attachmentsLocation of attachments can be seen in the following table： TOWER CRANE SCHDULENoCodeBuildingTower Height(m)Attach FloorTC01FM2555KM599.955F/11F/17F/23FTC02C6018M6B92.756F/13F/20FTC03TC5518M6A67.253F/9F/14FThe plan, elevation drawings and embedded members of attachments can be seen in attachment. 2. CalculationBecause of the difference model of tower cranes, there are two kinds of attachments used in this project: Attachment with four Support members, which used for tower crane 1; Attachment with three Support members, which is used for tower crane 2, tower crane 3; Now we calculate the attachments of tower crane 1 and tower crane 2, which are in the worst loading conditions. Tower crane 11) Calculation of the support forceAs the attachments are installed in accordance with the requirement of the specifications, the attachment which on top of tower crane has the biggest load, so the load of this attachment can be taken as the rationale to design and check the attachments.The tower of attached tower crane can be seen as a rigid support with a cantilever beam, its forces and support reactions are calculated as follows: The standard value of wind load should be calculated as the following formula: Wk=W0zsz In which: W0 base wind pressure(kN/m2)，according to the “General Construction Specification”: W0= 0.83kN/m2; z wind load height variation coefficient，according to the “General Construction Specification”:z=2.030; swind load shape coefficient：Us=0.065； z vibration factor at the height Z,z=0.70 Horizontal force of wind load: Nw=WkBKs In which Wk horizontal pressure of wind load,Wk=0.077kN/m2 B width of tower crane,B=2.00m Ks reduction factor of frontal area，Ks=0.20 According to calculation, the horizontal action of wind load: q=0.03kN/m Maximum overturning moment of tower crane: M=1500kN.m Calculation result: Nw=108.02kN2) Calculation of Support member forces Sketch map of calculation: Equilibrium equation of calculate unit:11X1+1p=0 1p=Ti0Ti/EA 11=Ti0Tili/EAAccording to calculate, the axial force of each support members:T1*=X1 ; T2*=T20X1+T2; T3*=T30X1+T3; T4*=T40X1+T43) Calculation of the first kind of construction situationCalculate the above equations, in which cycles from 0 to 360, at last, we can get the maximum axial pressure and axial tension of every Support member. The maximum axial pressure of Support member 1: 27.51 kN; The maximum axial pressure of Support member 2: 98.86 kN;The maximum axial pressure of Support member 3: 119.19 kN;The maximum axial pressure of Support member 4: 45.20 kN; The maximum axial tension of Support member 1: 27.51 kN; The maximum axial tension of Support member 2: 98.86 kN; The maximum axial tension of Support member 3: 119.19 kN; The maximum axial tension of Support member 3:45.20 kN;4) Calculation of the strength of support membera) Checking of the axial tension strength of support memberChecking formula: =N/Anf In which Nmaximum axial tension of support member; N=119.19kN； tensile stress of support member； Ansection area of support member, in this project, we use U-steel 16, An=2195mm2； According to calculation, the maximum tensile stress: 119.191000/2195=54.30N/mm2 The maximum tensile stress is no more than 216N/mm2, which is allowable tensile stress of support member, it can satisfy the requirements! b) Checking of the axial compressive strength of support member Checking formula: =N/Anf In which compressive stress of support member; Naxial stress of support member, support member 1:N=27.51kN; Support member 2:N=98.86kN; Support member 3:N=119.19kN;Support member 4: N=45.20kN. slenderness ratio of support member;Member 1 = 8741.853 / 62.800 = 139;Member 2 = 7212.489 / 62.800 = 115;Member 3 = 7212.489 / 62.800 = 115Member 4 = 8741.853 / 62.800 = 139; pressure stability factor of support member, which is calculated by; Member 1: =0.349, Member 2: =0.464; Member 3: =0.464, Member 4: =0.349;1 = 27.51 1000 / (0.349 2195.000) = 35.911 N/mm2; 2 = 98.86 1000 / (0.464 2195.000) = 97.066 N/mm2; 1 = 119.19 1000 / (0.464 2195.000) = 117.027N/mm2; 2 = 45.20 1000 / (0.349 2195.000) = 59.004 N/mm2; According to calculation, the maximum compressive stress is 117.027N/mm2. The maximum compressive stress is no more than 216N/mm2, which is the allowable compressive stress, meets the requirements! 5) Calculation of the connection of attach embedded member and building Attach supporting is usually connect with building by the way of embedded members connecting with the bolt of building elements. The embedded length and number should meet the following requirement: In which: nnumber of the embedded bolts; ddiameter of embedded bolt; lembedded length; fbond strength of embedded bolts and concrete(C20: 1.5N/mm2; C30: 3.0N/mm2);Naxial force of attach members; In this project, we embedded 20 rebar, the minimum concrete grade of attached building elements is C25; The number of rebar welded on embedded member is 9, which embedded length is 400mm.0.75*12*3.14*20*400*2.0=N=452.16KNAccording to the above analysis, the maximum axial force of attach member is 119.19KN452.16KN; So the connection of attach supporting and building satisfy the requirement! Tower crane 21) Calculation of the support forceAs the attachments are installed in accordance with the requirement of the specifications, the attachment which on top of tower crane has the biggest load, so the load of this attachment can be taken as the rationale to design and check the attachments.The tower of attached tower crane can be seen as a rigid support with a cantilever beam, its forces and support reactions are calculated as follows: The standard value of wind load should be calculated as the following formula: Wk=W0zsz In which: W0 base wind pressure(kN/m2)，according to the “General Construction Specification”: W0= 0.83kN/m2; z wind load height variation coefficient，according to the “General Construction Specification”:z=2.030； swind load shape coefficient：Us=0.065； z vibration factor at the height Z,z=0.70 Horizontal force of wind load: Nw=WkBKs In which Wk horizontal pressure of wind load,Wk=0.077kN/m2 B width of tower crane,B=2.00m Ks reduction factor of frontal area，Ks=0.20 According to calculation, the horizontal action of wind load: q=0.03kN/m Maximum overturning moment of tower crane: M=1500kN.m Calculation result: Nw=110.26kN2) Calculation of Support member forces Sketch map of calculation: Equilibrium equation of calculate unit:Fx=0T1cos1+T2cos2-T3cos3=-NwcosFy=0T1sin1+T2sin2+T3sin3=-NwsinM0=0T1(b1+c/2)cos1-(1+c/2)sin1+T2(b1+c/2)cos2-(1+c/2)sin2+T3-(b1+c/2)cos3+(2-1-c/2)sin3=MwIn which:1=arctanb1/a1 2=arctanb1/(a1+c) 3=arctanb1/(a2- a1-c)3) Calculation of the first kind of construction situationThe tower crane works in full loading, the wind direction perpendicular to the boom, considers wind load torque and the torque produced by the rotary inertia of the tower top section. Calculate the above equations, in which cycles from 0 to 360, taking both positive situation and negative situation, at last, we can get the maximum axial pressure and axial tension of every Support member. The maximum axial pressure of Support member 1: 145.62 kN; The maximum axial pressure of Support member 2: 0 kN; The maximum axial pressure of Support member 3: 103.59 kN; The maximum axial tension of Support member 1: 74.91kN; The maximum axial tension of Support member 2: 35.98 kN; The maximum axial tension of Support member 3: 116.93 kN;4) Calculation of the second kind of construction situationThe tower crane in no operates condition, wind direction along the boom, without considering the impact of torque. Calculate the above equations, in which = 45, 135, 225, 315, Mw = 0, at last, we can get the maximum axial pressure and axial tension of every Support member. The maximum axial pressure of Support member 1:110.26 kN; The maximum axial pressure of Support member 2: 0kN; The maximum axial pressure of Support member 3: 110.26 kN; The maximum axial tension of Support member 1: 110.26kN; The maximum axial tension of Support member 2: 0kN; The maximum axial tension of Support member 3: 110.26kN;5) Calculation of the strength of support memberc) Checking of the axial tension strength of support memberChecking formula: =N/Anf In which Nmaximum axial tension of support member; N=116.932kN； tensile stress of support member； Ansection area of support member, in this project, we use U-steel 16, An=2195mm2； According to calculation, the maximum tensile stress: 116.9321000/2195=53.272N/mm2 The maximum tensile stress is no more than 216N/mm2, which is allowable tensile stress of support member, it can satisfy the requirements! d) Checking of the axial compressive strength of support member Checking formula: =N/Anf In which compressive stress of support member; Naxial stress of support member, support member 1:N=145.617kN; Support member 2:N=0kN; Support member 3:N=110.261kN; pressure stability factor of support member, which is calculated by; =0.575; slenderness ratio of support member, =61.488; According to calculation, the maximum comp